Three numbers A,B,Care in ratio 1:2:3. Their average is 600. If A is increased by 10% and B is increased by 20%, then to get the average increased by 5%, C will increased by:
Let be A= x, B=2x, and C=3x.
(x+2x+3x)/3=600
this will be x=300
so, the numbers will be 300,600,900
new average= 105%of 600= 630
Let 110% of 300+80% of 600 + y= 630*3
solve it for y, you will get, y=1080
so, increase in C= 1080-900 =180
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In a class the average age is 16yrs.if the teacher who is 40 yrs of age is also included ,the average becomes 17 yrs,how many students were there?
Average age for five person (x) = 40 years.
=>x/5=40 => x=200 years.
Average of 10 person (y) = 25 years.
y/10=25 => y=250 years.
so avg age of 15 person = (250+200) / 15==30 years.
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The average age of 30 students is 9 years .If the age of their teacher is included ,it becomes 10 years . The age of the teacher (in years ) is :
Given 30 students avg. age = 9 years.
So total age of 30 students = 9*30 = 270 years.
Teacher's age included.
So, avg. of 30 students + one teacher = 10 years.
=> Total age of 30 students + one teacher = 10 * 31 = 310 years.
Therefore age of teacher = (310-270) = 40 years.
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The average age of 24 boys and the teacher is 15 years. When the teacher's age is excluded, the average decreases by 1. What is the age of the teacher ?
Given one teacher + 24 students avg. age = 15 years.
So total age of one teacher + 24 students = 15*25 = 375 years.
Teacher's excluded
So, 24 students avg. age = 14 years.
=> Total age of 24 students = 24 * 14 = 336 years.
Therefore age of teacher = (375-336) = 39 years.
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The average of the first five prime numbers greater than 20 is:
The average weight of 3 men A, B and C is 84 kg. Another man D joins the group and the average now becomes 80 kg. If another man E, whose weight is 3 kg more than that of D, replaces A then the average weight of B, C, D and E becomes 79 kg. The weight of A is :
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