Login/RegisterPractice Questions & Answers :: SBI Clerk Mains
SBI Clerk Mains
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Total Practice Qs: 26+
1 / 26
If an article with marked price of rs.400 is sold at successive discount of 10%, 25% and 15%, what is the price the customer has to pay?
A360
B300
C230
D270
Answer: Option C
Explanation:Discount=0.9*0.75*0.85=0.57
S0, 0.57*400=230
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2 / 26
A person walks a distance of 18 kms at a particular speed. For the next 30 kms he increases his speed by 2 kmph. Had he walked the entire distance at 3 kmph more than his initial speed, he would have reached 4 hours earlier. Find his initial speed.
A3 kms/hr
B2 kms/hr
C4 kms/hr
DNone of these
Answer: Option D
Explanation:Let x be the initial speed , then
18/x+30/x+2=12 , we get 12 from 3*4=12
by solving we get x=1,-3
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3 / 26
Three years ago the average of A and B was 18 Years. With C joining them now, the average becomes 22 years. How old is C now?
A24 years
B27 years
C28 years
D30 years
Answer: Option A
Explanation:let, present age of A and B and C is x and y and z.
before 3 yrs ago sum of their age was (x-3)+(y-3)=2*18
x+y=42..........(1) and
now sum of their age is x+y+z=22*3
x+y+z=66..........(2)
solving eqn (1) and (2), we get z=24
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4 / 26
A train is approaching a tunnel which is AB in length.Ther is a cat inside the tunnel which is 3/8 distance from the starting point of the tunnel.When the train whistes the cat starts to run.The train catches the cat exactly at the entry point of the tunnel.If the cat runs towards the exit,the train catches tha cat exactly at the exit point.The speed of the train is greater than the speed of the cat in what order?
A4:1
B1:4
C3:2
D2:3
ENone of above
Answer: Option A
Explanation:1.Time taken for x km by train = Time taken for 3/8 of AB by cat
2.Time taken for x+8 km by train = Time taken for 5/8 of AB by cat
eq1 => x/v1=(3/8)AB/v2
eq2 => (AB+x)/v1=(5/8)AB/v2 => x/v1=AB((5/8v2)-1/v1)
LHS of eq1 and eq 2 are same so RHS of 2 eqns are equal so :
(3/8)AB/v2 = AB((5/8v2)-1/v1)
(3/8)/v2=(5/8v2)-1/v1
1/v1=(2/8v2)
1/v1=1/4v2
v1=4v2
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5 / 26
A man can complete a job in 12 days, his wife will complete in 15 days. How many days, working together they will finish the job?
A%s
B%s
C%s
D%s
Answer: Option A
Explanation:man's one day work=1/12
wife's one day work=1/15
both=(1/12)+(1/15)=9/60
reciprocal of work is days
so 60/9=6 2/3 days.
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6 / 26
The sum of the digits of a two digit number is 8. If the digits are reversed the number is decreased by 54. Find the number.
A17
B71
C18
D81
Answer: Option B
Explanation:given a+b=8-->1
10b+a=a+10a-54(- bcoz reverse of digit dec by 54)-->2
from a+b=8
a=8-b sub this in eq 2
then we get 18b=18
b=1
a=7
so original numb is 71
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7 / 26
A train travels at an average of 50 miles per hour for 2x1/2 hours and then travels at a speed of 70 miles per hour for 1x1/2 hours. How far did the train travels in the entire 4 hours?
A120 miles
B150 miles
C200 miles
D230 miles
Answer: Option D
Explanation:total distance=50*5/2+70*3/2= 230miles
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8 / 26
An athlete runs 200 metres race in 24 seconds. His speed is
A20 km/hr
B28.5 km/hr
C24 km/hr
D30 km/hr
Answer: Option D
Explanation:speed = distance/time
speed=200/24 = 8.3 m/s
convert into km/hr =8.3*18/5 = 29.88
answer is 30 km/hr
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9 / 26
A man spend 810 in buying trouser at Rs 70 each and shirt at 30 each.What will be the ratio of trouser and shirt when the maximum number of trouser is purchased?
A2:3
B3:2
C3:4
D4:3
ENone of above
Answer: Option B
Explanation:70x + 30y = 810
if y= 6 than we get x = 9
so trouser:shirt = 9:6 = 3:2
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10 / 26
The average weight of 3 men A, B and C is 84 kg. Another man D joins the group and the average now becomes 80 kg. If another man E, whose weight is 3 kg more than that of D, replaces A then the average weight of B, C, D and E becomes 79 kg. The weight of A is :
A70 kg
B72 kg
C75 kg
D80 kg
Answer: Option C
Explanation:A+B+C=84*3=252....(i)
A+B+C+D=80*4=320...(ii)
D's age = 320-252=68 kg
then E's age = 68+3=71 kg
Now, B+C+D+E = 79*4=316.....(iii) B+C+68+71=316 or B+C = 177.....(iv)
Put value of B+C in eqn (i)
A=252-177 = 75kg Ans.
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