# Hexaware Technologies Aptitude Questions and Answers for Freshers

**Home**>

**Freshers Archives**>

**Hexaware Technologies Placement Questions & Answers**>

**MCQs Questions**

*Accenture (147)*

*Adobe (3)*

*Alcatel-Lucent (2)*

*Broadcom Ltd (33)*

*Aricent (7)*

*Amazon (9)*

*Wipro (378)*

*Tech Mahindra (432)*

*IBM (455)*

*BOA (Bank of America) (70)*

*Capgemini (488)*

*Commvault (40)*

*Nagarro (80)*

*TCS (675)*

*Infosys (296)*

*Cognizant (127)*

*Mu-Sigma (25)*

*HCL Technologies (111)*

*Virtusa (121)*

*CGI (50)*

*Syntel Inc. (91)*

*ThoughtWorks (33)*

*iGate (356)*

*Cisco (126)*

*Global Edge (166)*

*Green Valley Motor (76)*

*Sopra Steria (83)*

*Societe Generale (224)*

*L&T Infotech (17)*

*MindTree (60)*

*SAP Labs (27)*

*Hexaware Technologies (60)*

*TCS NQT (611)*

*TCS Digital (94)*

*TCS Ninja (80)*

*Huawei (50)*

*Wipro NLTH (175)*

*Reliance Jio (26)*

*Radisys (2)*

*GlobalLogic (2)*

*Brocade (2)*

*Sapient (1)*

*(1)*

*Acuvate Software (1)*

*Citrix (2)*

*Goldman Sachs (1)*

*Happiest Minds (1)*

1 / 60

**Choose the correct option.**

There are three numbers, these are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. What will be the sum of three numbers :

A80

B82

C85

D87

**Answer:**** Option C **

**Explanation:**

Given that numbers are co primes,

and two products have the middle number in common.

=> Middle number = H.C.F. of 551 and 1073 = 29

so first number is = 551/29 = 19

=> Third number = 1073/29 = 37

Therefore, sum of these numbers is = (19 + 29 + 37) = 85

Submit Your Solution

2 / 60

**Choose the correct option.**

If 11 oranges bought for 10 rs and 10 oranges sold for 11 rs. What is the profit?

A2.10%

B1.20%

C12%

D21%

**Answer:**** Option D **

**Explanation:**

C.P. of one orange=10/11

S.P. of one orange=11/10

Profit=(sp-cp)/cp*100=21%.

Submit Your Solution

3 / 60

**Choose the correct option.**

| x | + x^3 =0. Solve x

A0

B-1

CBoth A and B

DNone of these

**Answer:**** Option B **

**Explanation:**

let x=-1

|X|=1

x^3=(-1)^3=-1

|x|+x^3=1-1=0

so X=-1

and also x= 0 because here didn't mention any condition

Submit Your Solution

4 / 60

**Choose the correct option.**

The total population of a village is 5000. The number of males and females increases by 10% and 15% respectively and consequently the population of the village becomes 5600. what was the number of males in the village ?

A2000

B2500

C3000

D4000

**Answer:**** Option C **

**Explanation:**

suppose number of males =m

and number of females =f

so m+f=5000-----(1)

after increase males by 10%, m1=110m/100

and female by 15%, f1=115f/100

and m1+f1=5600

so putting values of m1 and f1

equation become 110m+115f=560000-----(2)

after solving both equations we get f=2000 and m=3000

so no of males =3000 answer is (c)

Submit Your Solution

5 / 60

**Choose the correct option.**

The average of 5 consecutive numbers is n. If the next two numbers are also included, the average will:

Aincreases by 1

Bremain the same

Cincrease by 1.4

Dincrease by 2

**Answer:**** Option A **

**Explanation:**

let x is first no then x,x+1,x+2,x+3,x+4 are consecutive nos

avg of this 5 nos is (x+x+1+x+2+x+3+x+4)/5=n

x+2=n ;n=x+2

add next 2 nos new avg is (x+x+1+x+2+x+3+x+4+x+5+x+6)/7=m

x+3=m ;m=x+3

new avg-old avg=x+3-x-2=1

increased by 1

Submit Your Solution

6 / 60

**Choose the correct option.**

The mean of 100 abservations was calculated was 40. It was found later on that one of the observations was misread as 83 instead of 53. The correct mean is :

A39

B39.7

C40.3

D42.7

**Answer:**** Option B **

**Explanation:**

(x1+..........+83+........+x100)/100=40

=> x1+...........+83+........+x100=4000

=>x1+...............+x100=4000-83 -(1)

(x1...........+53+.........+x99+x100)/100=y

=> x1+...........+53+...........+x100=100y

=> x1+..............+x100=100y-53 -(2)

from (1)(2),we get

4000-83=y*100-53

100y=3970

y=39.70

Submit Your Solution

7 / 60

**Choose the correct option.**

Find the angle between the hour and the minute hand of a clock when the time is 3.25.

**Answer:**** Option A **

**Explanation:**

formula::angle=11/2m-30h

11/2 * 25-30*3

=95/2

=47.5

ans:: AIs

Submit Your Solution

8 / 60

**Choose the correct option.**

A, B ans C are three speakers. They have to speak randomly along with another 5 speakers in a function. A has to speak before B and B has to speak before C. What is the probability?

A1/4

B1/6

C1/8

D1/10

**Answer:**** Option B **

**Explanation:**

Without considering other speakers , their arrangement should be ABC

whereas 6 arrangements are possible among these 3 persons.

Submit Your Solution

9 / 60

**Choose the correct option.**

There is a circle of radius 5. What is the area of the biggest rectangle that can be cut out of this circle?

A30

B35

C50

D60

**Answer:**** Option C **

**Explanation:**

Biggest rectangle would be a square,whose diagonal is 10(5+5)

if side of square is a, 100=a^2+a^2=2a^2

so area of square=a^2=100/2=50

Submit Your Solution

10 / 60

**Choose the correct option.**

Two mixers and one T.V. cost Rs. 7000, while two T.V.s and a mixer cost Rs. 9800. The value of one T.V. is ?

ARs. 2800

BRs. 2100

CRs.4200

DRs. 8400

**Answer:**** Option C **

**Explanation:**

Let x=mixer, and y=tv;

So, 2x+y=7000 and x+2y=9800;

solving for x& y

x=1400 - Mixer

y=4200 - T.V

Submit Your Solution

Here is the list of questions asked in Hexaware Technologies Aptitude Questions and Answers for Freshers - Q4Interview. Practice Hexaware Technologies Written Test Papers with Solutions and take Q4Interview Hexaware Technologies Online Test Questions to crack Hexaware Technologies written round test. Overall the level of the Hexaware Technologies Online Assessment Test is moderate. Only those candidates who clear the written exam will qualify for the next round, so practic all the questions here and take all the free tests before going for final selection process of Hexaware Technologies