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With just six weights and a balance scale, you can weigh any unit number of kgs from 1 to 364. What could be the six weights?


A1, 3, 19, 27, 81, 243

B1, 3, 9, 27, 81, 243

C1, 3, 17, 27, 81, 243

D1, 3, 9, 27, 91, 243

Answer: Option B

Explanation:

1, 3, 9, 27, 81, 243 (All powers of 3)

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2 hours after a freight train leaves Delhi, a passenger train leaves the same station travelling in the same direction at an average speed of 16 km/hr. After travelling 4 hrs the passenger train overtakes the freight train.What was the average speed of the freight train ?


A20.76km/hr

B10km/hr

C10.67km/hr

DNone of these

Answer: Option C

Explanation:

Distance travelled by Passenger train=16*4=64km
so,time taken by freight train=4+2=6hr
then, avg speed of freight train=64/6=10.67km/hr

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There is a square field of side 10 m. A man runs with different speed 10 kmph, 15 kmph, 20 kmph, 25 kmph on the four sides of the field. What is the average speed of man ?


A18.75

B16

C15

D15.58

Answer: Option D

Explanation:

Avg. Speed = (Total Distance /Total Time)

Total Distance = 10*4 = 40m 0r 0.04 km.

So, avg. Speed = 0.04/[(0.01/10)+(0.01/15) + (0.01/20) + (0.01/25)]
=15.58kmph

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From a pack of 52 cards, two cards are drawn together at random. What is the probability of both the cards being kings?


A1/221

B1/212

C1

D25/57

Answer: Option A

Explanation:

Lets assume the sample space = S
Then, n(S) = 52C2 = (52 x 51)/(2x1) = 1326
Let E = event of getting 2 kings out of 4
=> n(E) = 4C2 = (4 x 3)/(2 x 1) = 6
=> P(E) =n(E)/n(S) =6/1326 = 1/221

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A pupil's marks were wrongly entered as 83 instead of 63. Due to the average marks for the class got increased by half. The number of pupils in the class is:


A40

B73

C12

D23

Answer: Option A

Explanation:

Lets assume total pupils in the class = x
As per the question: increased by 1/2.
Total increase in marks = (x * 1/2) = x/2
=> x/2 = (83 - 63)
=> x/2 = 20
=> x = 40

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6 persons standing in queue with different age group, after two years their average age will be 43 and seventh person joined with them. Hence the current average age has become 45. Find the age of seventh person?


A43

B69

C52

D31

Answer: Option B

Explanation:

Total age of 6 persons is x hours,after two years total age of 6 persons is x+12
Average age of 6 persons is after two years is 43
So (x+12)/6=43 => x = 246 ---------- (1)
After 7th person is added then (x+7th person age)/7=45
7th person age = 45 *7 - x
=> 7th age = 69

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There are 5 packages. The weight of 1st package is 500 kg and the weight of the 2nd package is 50% higher than the weight of 3rd package whose weight is 45% higher than the 1st package weight. The fourth package at 360 kgs is 60% lighter than the fifth package. Find the average weight of all the five packages.


A714.5 kgs

B798.3 kgs

C723.9 kgs

D712.6 kgs

Answer: Option A

Explanation:

Weight of tst package = 500 kgs
Weight of 3rd package is 45% higher than the tst package.
i.e., 45 x 500/100 + 500 = 225 + 500 = 725 kgs.
2nd package is 50% higher than the weight of 3rd package
i.e., 50 x 725/100 * 725 = 1087.5 kgs
Weight of the 4th package is 360 kgs which is 60% lighter than the fifth p
ackage
Let the weight of 5th package be X.
Then the weight of 4th package = 360 kgs = X - 60X/100
360 kgs = X - 60X/100
40X/100 = 360
X=900
Therefore, the weight of 5th package = 900 kg.
Total of 5 packages = (500 + 1087.5 + 725 + 360 + 900) = 3572.5 kgs
Average= 3572.5/5 = 714.5

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The average number of visitors of a library in the first 4 days of a week was 58. The average for the 2nd, 3rd, 4th and 5th days was 60.If the number of visitors on the 1st and 5th days were in the ratio 7:8 then what is the number of visitors on the 5th day of the library?


A18

B64

C58

D56

Answer: Option B

Explanation:

If number of visitors on 1st, 2nd, 3rd, 4th & 5th day are a, b, c, d & e respectively, then
a+b+c+d=58*4=232 ----(i) &
b+c+d+e=60*4=240 ----(ii)
Subtracting (i) from (ii), e-a=8 ---(iii)
Given, a/e=7/8 ---(iv)
So from (iii) & (iv), a=56, e=64

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A man gave Rs.A for buying every 10 items and Rs.B for buying every extra item. If he bought 10 items on Monday 13 items on Tuesday, 12 items on Wednesday, 11 items on Thursday and 12 items on Friday then what is his average daily spending in rupees for the five days?


AA+ 8B/5

B(5A+9B)/5

C10A+ 8B/5

D5A+8B

Answer: Option A

Explanation:

Solution: Monday = 10 items =  A



        Tueday= 13 items= A 3B  ,  Wednesday= 12 items= A 2B ,  Thursday= 11 items= A B



        Friday= 12 items= A 2B



        Average= (5A 8B)/5= A 8B/5

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In an exam, Ajith, Sachu, Karna, Saheep and Ramesh scored an average of 39 marks. Saheep scored 7 marks more than Ramesh. Ramesh scored 9 fewer than Ajith. Sachu scored as many as Saheep and Ramesh scored.Sachu and Karna scored 110 marks them. If Ajith scores 32 marks then how many marks did Karna score?


A53 marks

B23 marks

C57 marks

D30 marks

Answer: Option C

Explanation:

Lets assume marks of Ajith, Sachu, Karna, Saheep and Ramesh respectively u, v, w, x, y So, as per the question: z+7=x ---(i) u- 9=z ---(ii) x+ z=v ---(iii) v+w=110 ---(iv) Given, u=32 ---- (v) By solving eq. (i), (ii), (iii), (iv) and (v) w=57

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