The average marks of 3 students A, B and C is 60. When another student D joins the group, the new average becomes 56 marks. If another student E, who has 3 marks more than D, joins the group, the average of the 4 students B, C, D and E becomes 55 marks. How many marks did A get in the exam?
Given that A + B + C = 60 * 3 = 180
A + B + C + D = 56 * 4 = 224
Therefore, D = 44
E = 44 + 3 = 47
Given, B + C + D + E = 55 * 4 = 220
B + C + 44 + 47 = 220
? B + C = 220 - 91 = 129
So A + 129 = 180 ? A = 51
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Of a set of 30 numbers, average of first 10 numbers = average of last 20 numbers. Then the sum of the last 20 numbers is?
sum = average x number of observations.
Let the common average = x
Now sum of first 10 numbers = 10x
Sum of the last 20 numbers = 20x.
So sum of the last 20 numbers = 2 × sum of the first ten numbers.
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You have been given a physical balance and 7 weights of 52, 50, 48, 44, 45, 46, and 78 Kgs.. Keeping weights on one pan and object on the other, what is the maximum you can weigh less than 183 Kgs.?
Solution: Putting on the Maximum weights that is 78 52 50= 180kg
Checking the options we can see that 180kg weight measurement is possible therefore 180kg is the possible answer.
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Rajesh calculated his average over the last 24 tests and found it to be 76. He finds out that the marks for three tests have been inverted by mistake. The correct marks for these tests are 87, 79 and 98. What is the approximate percentage difference between his actual average and his incorrect average?
Incorrect value is: 78, 97, 89
correct values are: 87, 79, 98
Difference between correct and incorrect value is= 9 + 9 -18=0
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There are 5 boxes in a cargo. The weight of the 1st box is 200 KG, the weight of the 2nd box is 20% higher than the third box, whose weight is 25% higher than the 1st box weight. The 4th box which weighs 350 KG is 30% lighter than the 5th box. Find the difference in average weight of the 4 heaviest boxes and the four lightest boxes.
Weight of 3rd box=(125/100)*200=250 weight of 2nd box=(120/100)*250=300 weight of 4th box =350
Weight of 5th box=(10/7)*350=500
Average of 4 highest weighted Boxes = (500+350+300+250)/4 = 350
Average of 4 lightest boxes = (350+300+250+200)/4 = 275 Difference = (350-275) = 75
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The average temperature of Tuesday Wednesday and Thursday was 37 C. The average temperature of Wednesday and Thursday and Friday was 38 C. if the temperature on Friday was 39 C.
Let 'T' be the total age of 5 girls.
Then, T/5 = 11.
=> T = 55.
Given, Age of the Oldest girl = 15.
Then, Total age of other 4 girls will be 55-15=40.
So, Avg. of other 4 girls 40/4 = 10.
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vijay weighed 65 1/2kg, He gained 1 2/5kg during the first week, 1 1/1 kg during the second week, but lost 5/16kg during the third week. What is his weight after the third week?
In ascending order: 65,70,75,78,112
middle number is 3rd i.e 75
so, median = 75
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The ratio between the boys and girls in a class in 6:5 if 8 more boys join the class and two girls leave the class then the ratio becomes 11: 7 What is the number of boys in the class now?
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