Global Edge Placement Questions & Answers :: Global Edge

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In each of the following questions find out the alternative which will replace the question mark.
Ornithologist : Bird :: Archealogist : ?


AIslands

BMediators

CArchealogy

DAquatic

 View Answer |  Submit Your Solution | Topic: Analogy | Asked In Global Edge |

Answer: Option C

Explanation:

As Ornithologist is a specialist of Birds similarly Archealogist is a specialist of Archealogy.

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Choose the correct option.

A 600m long train is running at 73 Kmph. How much time Train will take to cross an electric pole?


A29.58 sec

B28.58sec

C29 sec

D28sec

ENone of these

Answer: Option A

Explanation:

Formula Used: Time = ( Distance / Speed)
As all the option given in sec., so convert the train speed (Kmph) in to mps multiply by 5/18
speed (mps) = 73 * 5/18
Time = 600 / (73 * 5/18)
= (600 * 18 )/(73 * 5) sec
= (10800 / 365)
Time take by Train = 29.58Sec

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Choose the correct option.

A 120 m long train is running at 72 Kmph. How much time will it take to cross a man standing on the platform?


A6 sec

B2.5 sec

C5 sec

D12 sec

Answer: Option A

Explanation:

Formula Used: Time = ( Distance / Speed)



As all the option given in sec., so convert the train speed (Kmph) in to mps multiply by 5/18



speed (mps) = 72 * 5/18 = 20 mps



Time = (120 / 20) sec = 6 sec



Time take by Train = 6 Sec.

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Choose the correct option.

Two trains 400m and 300m long run at the speeds of 50 kmph and 40kmph respectively in opposite Directions on parallel tracks. The time taken to cross each other?


A20 sec

B28 secs

C25 sec

D24 sec

ENone of these

Answer: Option B

Explanation:

Trains are running in opposite Direction:
So need to find Length of two Trains = 300m + 400m = 700m

and Total Speed = 40 Kmph + 50 Kmph (Opposite Direction)
= 90 Kmph
so speed (m/sec) = 90 * 5/18 m/sec = 25 m/sec
Formula Used: Time = Distance/Speed

Time = 700/ 25 sec
Time = 28 Sec

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Choose the correct option.

Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?


A10 a.m.

B11 a.m.

C10 p.m.

D11 p.m.

Answer: Option A

Explanation:

Let they meet x hours after 7 a.m.

Distance covered by A in x hours = 20x km.

Distance covered by B in (x - 1) hours = 25(x - 1) km.

So Total Distance
=> 20x + 25(x - 1) = 110
=> 45x - 25 = 110 => 45x = 135
=> x = 3.
As They meet x hrs after 7 a.m. so they meet at 10 a.m.

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Choose the correct option.

Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train?


A27 m

B33 m

C27 7/9 m

D23 4/9 m

Answer: Option C

Explanation:

As train are running in same direction
so Relative speed = (40 - 20) km/hr = 20 km/hr
= ( 20 x 5/18 ) m/sec = 50/9 m/sec.
Formula Used: Distance = Speed * Time
Now Length of Faster Train = ( 50/9 x 5 ) m = 250/9 m
= 27 7/9 m

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Choose the correct option.

A train moves past a telegraph post and a bridge 264 m long in 8 seconds and 20 seconds respectively. What is the speed of the train?


A69.5 km/hr

B70 km/hr

C79 km/hr

D79.2 km/hr

Answer: Option D

Explanation:

Let the length of the train be x meters and its speed by y m/sec.

Then, x/y = 8 => x = 8y ----------- (1)

As per the question total distance = (x + 264) meters.
(x + 264)/20 = y
Put the value of x from equation 1.
=> 8y + 264 = 20y
=> y = 22.

Therefore Speed = 22 m/sec = ( 22 x 18 /5) km/hr = 79.2 km/hr.

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Choose the correct option.

An Athlete runs 200 metres race in 24 seconds. His speed is:


A20 km/hr

B24 kim/hr

C28.5 km/hr

D30 km/hr

Answer: Option D

Explanation:

Speed = (200/24) m/sec = 25/3 m/sec
convert m/sec to km/hr
(25/3 * 18/5) km/hr = 30 km/hr.

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Choose the correct option.

Albert is travelling on his cycle and has calculated to reach point A at 2 P.M. if he travels at 10 kmph, he will reach there at 12 noon if he travels at 15 kmph. At what speed must he travel to reach A at 1 P.M.?


A8 kmph

B11 kmph

C12 kmph

D14 kmph

Answer: Option C

Explanation:

Let's Assume the distance travelled Albert = x km.
Formula Used: Time = Distance/Speed
so (x/10 - x/15) = 2 hrs
=> (3x - 2x)/30 = 2 hrs.
=> (3x - 2x) = 60
x = 60 km.

Time taken to travel 60 km at 10 km/hr = 60/10 hrs = 6 hrs.
Formula Used: Speed = Distance/Time
So, Albert started 6 hours before 2 P.M. i.e @ 8 A.M.

Required speed = 60/5 kmph. = 12 kmph.

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Choose the correct option.

A person travelled by train for 1 hour at a speed of 50 kmph. He then travelled by a taxi for 30 minutes at a speed of 32 kmph to complete his journey. What is the average speed at which he travelled during the journey?


A44 kmph

B42 kmph

C41 kmph

D33 kmph

Answer: Option A

Explanation:

Total distance travelled in 1 hour
= 50 + (&frac; x 32) km
= 66 km
? Average speed = Total distance/Total time
= 66/(3/2) = 44 kmph.

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