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1 / 146
A' and 'B' complete a work togather in 8 days.If 'A' alone can do it in 12 days.Then how many day 'B' will take to complete the work?
A25 days
B24 days
C20 days
DNone of these
Answer: Option B
Explanation:A & B one day work = 1/8
A alone one day work = 1/12
B alone one day work = (1/8 - 1/12) = ( 3/24 - 2/24)
=> B one day work = 1/24
so B can complete the work in 24 days.
20
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2 / 146
If A alone can do a piece of work in 8 days and B alone can do the same work in 12 days. How many days A and B required to finish the same work if they work togather?
A24/5 days
B24 days
C5day days
D5/24 days
ENone of these
Answer: Option A
Explanation:A alone one day work = 1/8
B alone one day work = 1/12
Both A and B one day work = (1/8 + 1/12) = (3/24 + 2/24)
= 5/24
so A and B together finish the work in 24/5 day
or 4 4/5 days.
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3 / 146
When a number is divided by 13, the remainder is 11. When the same number is divided by 17, then remainder is 9. What is the number ?
A339
B349
C369
DData inadequate
Answer: Option B
Explanation:x = 13p + 11 and x = 17q + 9
ShortCut By :: Sairam349
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4 / 146
A can finish a piece work in 18 days and B can do the same work in half the time taken by A. So if they working together, what part of the same work can finished in a day?
A1/7
B1/6
C6
D5/6
Answer: Option B
Explanation:First find the 1 day work of both (A & B)
A's 1 day's work = 1/18
and
B's 1 day's work = 1/9 (B can do work in half time)
(A + B)'s 1 day's work = (1/18+1/9)
= (1+2)/18 = 3/18 = 1/6
so A & B together can do 1/6 of work in 1 day.
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5 / 146
The cost price of an article ls 80% of its marked price for sale. How much percent does the trades-man gain after allowing a discount of 12%?
A20
B10
C12
D8
Answer: Option B
Explanation:C.P. of the article = Rs. 100
So Marked price = (100*100)/80 = Rs. 125
SP after the discount = Rs.(125*88)/100 = Rs. 110
therefore Gain percent = 10
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6 / 146
If 6 is subtracted from the present age of Ritu and the remainder is divided by 6, then the present age of Sheema is obtained. If Sheema is 4 years younger to raju whose age is 12 years, then find the age of Ritu
A50
B52
C54
D58
EData inadequate
Answer: Option C
Explanation:Lets assume Ritu present age = x years
so sheema age = (x-6)/6 years
As per question:
sheema age [(x-6)/6 + 4] = 12
(x-6)/6 = 12 - 4
=> (x-6)/6 = 8
=> x - 6 = 48 => x = 54
So Ritu age = 54 years.
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7 / 146
A car averages 55 mph for the first 4 hours of a trip and averages 70 mph for each additional hour. The average speed for the entire trip was 60 mph. How many hours long is the trip?
A6 hrs.
B14 hrs.
C11 hrs.
D12 hrs.
Answer: Option A
Explanation:Lets assume additional hours = x hrs.
So total No. hours in journey = (4+x)
[(55*4)+(70*x)]/(4+x)=60 =>
=>x=2
Therefore, Total No. of hrs. in Journey = (x+4) = 6 hrs.
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8 / 146
2 boxes, 32 black n 31 red balls the probability of getting black ball is maximum. The maximum probability is
A3/4
B1/4
C2/3
DNone of these
Answer: Option A
Explanation:Here is no explanation for this answer
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9 / 146
A ball dropped from H height and moves 80% of height each time. Total distance covered is
A4H
B5H
C7H
D9H
Answer: Option D
Explanation:First time distance= H
Second time = 80H/100 = 4H/5
similarly third time 80% of 4H/5 = H(4^2)/(5^2)
and so on..
This will lead to infinite terms of geometric progression
i.e H+2*4H/5+2*16H/25..
So, Sum = H+ 2*4H/(5(1-4/5)) = 9H
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10 / 146
At 10:00 am 2 trains started travelling towards each other from station 287 miles apart they passed each other at 1:30 pm the same dayy .if average speed of the faster train exceeded by 6 miles /hr what is speed of faster train in miles/hr:
A34 miles/hrs.
B38 miles/hrs.
C44 miles/hrs.
D40 miles/hrs.
Answer: Option C
Explanation:Lets assume the speed of slower train = x miles/hrs.
So, speed of faster train is = (x+6) miles/hrs.
Given, passed each other at 1:30 PM i.e after 3 1/2 hrs.
Both train travelling towards each other so total relative speed = x+(x+6) = (2x+6)
So, 287/(2x+6) = 7/2 => 574 = 14x + 42
=> 14x = 542 => x = ~38
So spee of faster train = (x+6) miles/hrs. = 44 miles/hrs.
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