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The average age of 5 girls is 7. The oldest among them is 15 years ol What is the average age of others?


A5.5 Years

B6 Years

C5 Years

D4 Years

Answer: Option C

Explanation:

sum of ages of girls = 35
sum of ages of rest of 4 girls=20
So, Average = 20/4 = 5

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The average age of a family of 5 was 32 . It fell to 18 when the grandmother died. How old was she ?


A32 years

B34 Years

C78 Years

D88 Years

Answer: Option D

Explanation:

Given Avg of age of 5 family = 32
Total Member age / 5 = 32
Total age of 5 = 160

After grandma died, total age will be
Total Member age / 4 = 18
Total age of 4 Member = 72

Age of grandma = 160-72 = 88 Years.

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The captain of a cricket team of 11 members is 26 years old and the wicket keeper is 3 years older. If the ages of these two are excluded, the average age of the remaining players is one year less than the average age of the whole team. What is the average age of the team?


A23 years

B24 years

C25 years

DNone of these

Answer: Option A

Explanation:

Let the average age of the whole team by x years.

11x - (26 + 29) = 9(x -1)

11x - 9x = 46

2x = 46

x = 23.

So, average age of the team is 23 years.

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Average age of 22 students is 21 years, if avreage is increased by 1 then teacher included what is the age of teacher


A34

B44

C23

DNone of these

Answer: Option B

Explanation:

total age of students = 22 x 21 = 462
if teacher is included no of persons will be 23 avg will be 22 yrs
total age (if teacher included) = 23 x 22 = 506
Age of teacher = 506 - 462 = 44

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In a cricket tournament there was 16 teams.a amount of 8000 was allocated for prize. If prize per team increase with amount of 225 according to rank. Find amount given to first team if last team got 275.


A775

B356

C725

D454

Answer: Option C

Explanation:

Actually u wrote the que. wrong. 225 Rs was not given.
s=8000
s=8(2*275+15d)
by solving
d=30
so 1st team prize=275+(15*30)=725

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Ramesh got an overall average of 52 marks in an examination having five papers. He applied for re-evaluation and got the mark for one of the papers revised from 45 to 60. What is the new overall average.


A55

B67

C52

D57

E60

Answer: Option A

Explanation:

5 subjects each subject 100 marks total = 500

Mark = average * no. of paper
=> 52*5 = 260
=> 260+15 = 275
Mark= (275/500)*100 = 55%

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Mother, daughter and infant total weight is 74 kg. Mother's weight is 46 kg more than daughter and infant's weight. Infant's weight is 60% less than daughter's weight. Find daughter's weight.


A10

B9

C8

D7

Answer: Option A

Explanation:

Total weight is M+D+I=74 given that M-D-I=46
solving above 2 eq's we get Mother weight = 60
Now reaming weight=14 which is sum of daughter and Infant weight. Given that Infant weight is 60% less than Daughter.
i.e If daughter weight is 100 then infant weight is 40. So weight ratio Of D and I is 100 : 40 i.e ... 5 : 2

So (5+2)=7 parts equal to 14. then 5 parts equal to 10.
2 parts equal to 4. daughter weight is =10 and infant weight is = 4

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Average salary of 17 teachers is 45000.3 teachers left and the average salary dropped by 2500.What is the sum of salaries of 3 teachers who left?


A173000

B176000

C170000

D85000

Answer: Option C

Explanation:

Total Initial Salary : 17*45000 = 765000
Average Salary After removal of 3 Teachers = 45000-2500 = 42500
Total Final Salary : 14*42500 = 595000
Sum of Salaries of 3 teachers who left : 765000 - 595000 = 170000

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What is the average of the first 200 terms of the series
1, -2, 3, -4, 5, -6, 7......


A-1

B-1/3

C-1/2

D1/2

Answer: Option C

Explanation:

1+3+5+7+9+11+13.........+199 i.e 100 terms and
sum of n odd natural numbers is n^2 i.e 100^2 =10,000

-(2+4+6+8+10+12...........+200) i.e 100 terms and
sum of n even natural numbers is n(n+1) i.e -(100(100+1))= -10,100
average of first 200 terms = (10,000+(-10,100))/200
=-100/200
=-1/2 Ans.

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Thomas bought X number of sports goods for Rs.9000. If each item was cheaper by Rs.30 then with the same amount he could have bought 50 more items than X. Find the number of items bought by Thomas ?


A140

B200

C210

D100

ENone of these

Answer: Option D

Explanation:

Transaction I

Thomas have bought X items for Rs.9000.
Then the cost of each item = Rs.9000/X ...(1)

Transaction II

If each item was cheaper by Rs.30, he could have bought 50 more items.
Therefore, with Rs.30 discount, the amount of each item = Rs.9000 / X + 50 ...(2)

We know that the cost of each item in transaction II will be lesser than that of transaction I by Rs. 30.

i.e (1) - (2) = 30

Since he bought 50 more items when cost of each item is less by Rs.30 then we have
9000/X - 9000/X + 50 = 30
1/X - 1/X + 50 = 30/9000
50 / X(X + 50) = 1/300
X(X + 50) = 15000
X^2 + 50X = 15000
X^2 + 50X - 15000 = 0
(X+150)(X-100) = 0
X = -150 or X = 100
X cannot be a negative value. Therefore, X = 100.
Hence the answer is 100.

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