[Updated] Goldman Sachs Aptitude Test Questions and Answers
Practice List of TCS Digital Coding Questions !!!
Take 50+ FREE!! Online Data Interpretation Mock test to crack any Exams.

# Practice Questions & Answers :: HireMee

18.92K

## Total Practice Qs: 239+

NA
SHSTTON
55
Solv. Corr.
81
Solv. In. Corr.
136
Attempted
4 M:4 S
Avg. Time

1 / 239

Choose the correct option.

If 19 and 1140 are the respective HCF and LCM of two numbers, which are greater than 19 then what will be the possible number of such pair?

A0

B2

C3

D5

| | Important Formulas | Topic: | Asked In IBMTCS NQTHireMee |

Explanation:

Product of HCF and LCM = product of the numbers
Then, product of the numbers = 19 x 1140
Let 19a and 19b be the numbers.
19a x 19b = 19 x 1140
ab = 19 x 1140 / 19 x 19 = 60
If ab = 60 then (a,b) = (1,60), (2,30), (3,20), (4,15), (5,12) and (6,10).
Since a and b are co-primes then (a,b) = (1,60), (4,15) and (5,12)
Hence the number of such pairs = 3a

Tags: IBM TCS NQT

NA
SHSTTON
18
Solv. Corr.
67
Solv. In. Corr.
85
Attempted
0 M:0 S
Avg. Time

2 / 239

Choose the correct option.

Three wheels make 18, 24, 54 revolutions per minute. Each has a black mark on it. It is aligned at the start. When does it align again for the first time?

A2 Seconds

B10 Seconds

C12 seconds

DNone of these

| | Important Formulas | Topic: | Asked In CapgeminiHireMee |

Explanation:

Let the time be x minutes.
Therefore 18x 24x 54x
Hcf = 6
Therefore time = 1/6 minute ie 10 secs

Tags: Capgemini

NA
SHSTTON
104
Solv. Corr.
80
Solv. In. Corr.
184
Attempted
2 M:2 S
Avg. Time

3 / 239

Choose the correct option.

find the number between 100 to 400 which is divisible by either 2,3,5,7..

A120

B100

C205

D210

| | Important Formulas | Topic: | Asked In AccentureTCS NQTHireMee |

Explanation:

LCM of 2,3,5,7=210

NA
SHSTTON
73
Solv. Corr.
59
Solv. In. Corr.
132
Attempted
0 M:47 S
Avg. Time

4 / 239

Choose the correct option.

What is the least amount that a person can have, such that when he distributes it into groups of Rs.16 or Rs. 18 or Rs. 20 or Rs. 25, he is always left with Rs. 4?

ARs. 1796

BRs. 1804

CRs. 2596

DRs. 3604

| | Important Formulas | Topic: | Asked In CognizantHireMee |

Explanation:

Find the lcm of 16 18 20 and 25 i.e 3600.
so the amount is (3600 + 4) = Rs. 3604

Tags: Cognizant

NA
SHSTTON
108
Solv. Corr.
151
Solv. In. Corr.
259
Attempted
1 M:24 S
Avg. Time

5 / 239

Choose the correct option.

There are three numbers, these are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. What will be the sum of three numbers :

A80

B82

C85

D87

| | Important Formulas | Topic: | Asked In NagarroHexaware TechnologiesHireMee |

Explanation:

Given that numbers are co primes,
and two products have the middle number in common.

=> Middle number = H.C.F. of 551 and 1073 = 29

so first number is = 551/29 = 19
=> Third number = 1073/29 = 37

Therefore, sum of these numbers is = (19 + 29 + 37) = 85

NA
SHSTTON
7
Solv. Corr.
4
Solv. In. Corr.
11
Attempted
0 M:0 S
Avg. Time

6 / 239

Choose the correct option.

What is LCM of 36/225, 48/150 , 72/65 ?
A

A36/65

B144/5

C72/225

D288/5

| | Important Formulas | Topic: | Asked In HireMee |

Explanation:

LCM of fraction is LCM of Numerator upon LCM of Denominator.

Numerators = 36, 48 and 72

72 is largest number among them. 72 is not divisible by 36 or 48

72

Tags: No Tags on this question yet!

NA
SHSTTON
14
Solv. Corr.
27
Solv. In. Corr.
41
Attempted
0 M:0 S
Avg. Time

7 / 239

Choose the correct option.

The total number of prime factors of the product (8)20

A59

B98

C123

D4

E14

| | Important Formulas | Topic: | Asked In HireMee |

Explanation:

The prime numbers are 2,3,5,17 in the expression.

The expression can be written as (2

Tags: No Tags on this question yet!

NA
SHSTTON
6
Solv. Corr.
3
Solv. In. Corr.
9
Attempted
0 M:0 S
Avg. Time

8 / 239

Choose the correct option.

The least number which is divisible by 12, 15, 20 and is a perfect square, is -

A400

B900

C1600

D3600

E4200

| | Important Formulas | Topic: | Asked In HireMee |

Explanation:

12 = 2 x 2 x 3

15 = 3 x 5

20 = 2 x 2 x 5

So, LCM = 2 x 2 x 3 x 5 = 60

As 3 and 5 are not in pair in LCM’s factor so we need to multiply 60 by 5 and 3 to make it a perfect square.

Required smallest number = 60 × 3 × 5 = 900

Tags: No Tags on this question yet!

NA
SHSTTON
6
Solv. Corr.
2
Solv. In. Corr.
8
Attempted
0 M:0 S
Avg. Time

9 / 239

Choose the correct option.

Three piece of timber 42 m, 49 m and 63 m long have to be divided into planks of the same length. What is the greatest possible length of each plank?

A7m

B14m

C42m

D63m

E78m

| | Important Formulas | Topic: | Asked In HireMee |

Explanation:

The maximum possible length = (HCF of 42, 49, 63) = 7

Tags: No Tags on this question yet!

NA
SHSTTON
25
Solv. Corr.
20
Solv. In. Corr.
45
Attempted
0 M:0 S
Avg. Time

10 / 239

Choose the correct option.

The HCF of two numbers is 12 and their difference is also 12. The numbers are -

A66,78

B94, 104

C70,82

D84,96

| | Important Formulas | Topic: | Asked In HireMee |

Explanation:

Let the numbers be 12a,12b where gcd(a,b)=1. (By the definition of HCF).
Also, 12b−12a=12.
⟹b−a=1
So, we are left with two equations,
gcd(a,b)=1 and
b−a=1

Which is true for all adjacent pairs of natural numbers. Therefore,

(a,b)=(1,2)(2,3),(3,4),(4,5),…

Which means,
(12a,12b)=(12,24),(24,36),(36,48),(48,60),(84,96)…