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HireMee
Tot. Mock Test: 8+
Tot. Exam. Sec.: 2+
Total Practice Qs: 239+
1 / 239
If 19 and 1140 are the respective HCF and LCM of two numbers, which are greater than 19 then what will be the possible number of such pair?
A0
B2
C3
D5
Answer: Option C
Explanation:Product of HCF and LCM = product of the numbers
Then, product of the numbers = 19 x 1140
Let 19a and 19b be the numbers.
19a x 19b = 19 x 1140
ab = 19 x 1140 / 19 x 19 = 60
If ab = 60 then (a,b) = (1,60), (2,30), (3,20), (4,15), (5,12) and (6,10).
Since a and b are co-primes then (a,b) = (1,60), (4,15) and (5,12)
Hence the number of such pairs = 3a
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2 / 239
Three wheels make 18, 24, 54 revolutions per minute. Each has a black mark on it. It is aligned at the start. When does it align again for the first time?
A2 Seconds
B10 Seconds
C12 seconds
DNone of these
Answer: Option B
Explanation:Let the time be x minutes.
Therefore 18x 24x 54x
Hcf = 6
Therefore time = 1/6 minute ie 10 secs
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3 / 239
find the number between 100 to 400 which is divisible by either 2,3,5,7..
A120
B100
C205
D210
Answer: Option D
Explanation:LCM of 2,3,5,7=210
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4 / 239
What is the least amount that a person can have, such that when he distributes it into groups of Rs.16 or Rs. 18 or Rs. 20 or Rs. 25, he is always left with Rs. 4?
ARs. 1796
BRs. 1804
CRs. 2596
DRs. 3604
Answer: Option D
Explanation:Find the lcm of 16 18 20 and 25 i.e 3600.
so the amount is (3600 + 4) = Rs. 3604
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5 / 239
There are three numbers, these are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. What will be the sum of three numbers :
A80
B82
C85
D87
Answer: Option C
Explanation:Given that numbers are co primes,
and two products have the middle number in common.
=> Middle number = H.C.F. of 551 and 1073 = 29
so first number is = 551/29 = 19
=> Third number = 1073/29 = 37
Therefore, sum of these numbers is = (19 + 29 + 37) = 85
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6 / 239
What is LCM of 36/225, 48/150 , 72/65 ?
A
A36/65
B144/5
C72/225
D288/5
Answer: Option B
Explanation:LCM of fraction is LCM of Numerator upon LCM of Denominator.
Numerators = 36, 48 and 72
72 is largest number among them. 72 is not divisible by 36 or 48
start with table of 72.
72
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7 / 239
The total number of prime factors of the product (8)20
A59
B98
C123
D4
E14
Answer: Option D
Explanation:The prime numbers are 2,3,5,17 in the expression.
The expression can be written as (2
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8 / 239
The least number which is divisible by 12, 15, 20 and is a perfect square, is -
A400
B900
C1600
D3600
E4200
Answer: Option B
Explanation:12 = 2 x 2 x 3
15 = 3 x 5
20 = 2 x 2 x 5
So, LCM = 2 x 2 x 3 x 5 = 60
As 3 and 5 are not in pair in LCM’s factor so we need to multiply 60 by 5 and 3 to make it a perfect square.
Required smallest number = 60 × 3 × 5 = 900
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9 / 239
Three piece of timber 42 m, 49 m and 63 m long have to be divided into planks of the same length. What is the greatest possible length of each plank?
A7m
B14m
C42m
D63m
E78m
Answer: Option A
Explanation:The maximum possible length = (HCF of 42, 49, 63) = 7
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10 / 239
The HCF of two numbers is 12 and their difference is also 12. The numbers are -
A66,78
B94, 104
C70,82
D84,96
Answer: Option D
Explanation:Let the numbers be 12a,12b where gcd(a,b)=1. (By the definition of HCF).
Also, 12b−12a=12.
⟹b−a=1
So, we are left with two equations,
gcd(a,b)=1 and
b−a=1
Which is true for all adjacent pairs of natural numbers. Therefore,
(a,b)=(1,2)(2,3),(3,4),(4,5),…
Which means,
(12a,12b)=(12,24),(24,36),(36,48),(48,60),(84,96)…
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