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# Average Questions

Home > Quantitative Aptitude > Average > General Questions
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Average of all prime numbers between 30 to 50

A37

B37.8

C39

D39.8

Explanation:

Solutions : All the prime numbers between 30 to 50 are- 31,37,41,43,47

Therefore average is (31 37 41 43 47)/5=39.8

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Average weight of 3 men A, B and C is 80 kg. Another man D joins the group and the average now becomes 75 kg. If another man E, whose weight is 2 kg more than that of D, replaces A then the average weight of B, C, D and E becomes 77 kg. The weight of A is:

A54 kg

B60 kg

C52 kg

D64 kg.

Explanation:

Total age of (A + B + C) = 80 * 3 = 240 kgs.
Total age of A + B + C + D = 75 * 4 = 300 kgs.
Weight of D = (300 - 240) = 60 kgs.
Also the weight of E (2 kgs more than D) = 62 kgs.
A is replaced by E
so (E + B + C + D) = 77 x 4 = 308
Difference between ages of E and A = (308 - 300) = 8 kgs
A's weight = (62 - 8) = 54 kgs

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The average of 7 numbers is 8. If one number is added, their average is 9. Then the added number is

A11

B16

C14

D12

Explanation:

Given average of 7 numbers = 8
So total = 8 * 7 = 56
Given One more number is added
=> there are 8 numbers with the average 9.
Total of 8 numbers = (8 * 9) = 72.
The added number = (72 - 56) = 16

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If the average of 10% of a number, 25% of that number, 50% of that number and 75% of that is 24, then the number will be

A50

B80

C70

D60

Explanation:

Let the number be N.
so (N*10% + N*25% + N*50% + N*75%)/4 = 24
=> (0.1 * N + 0.25 * N + 0.5 * N + 0.75 * N)/4 = 24
=> (1.6*N)/4 = 24
=> 1.6*N = 96
=> N = 60

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The average of 5 numbers is 27. If one number is excluded, the average becomes 25. The excluded number is

A25

B27

C30

D35

Explanation:

Given % numbers average = 27
So total of 5 numbers = 27 * 5 = 135
The total of 4 numbers = 25 * 4 = 100
So Excluded number = (135 - 100) = 35

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The number of students in the three sections of a class are in the ratio 2:3:4. The average marks scored in each of these sections is in the ratio 4:3:1. By what percent is the average mark of the second section more than the class average?

A23.27%

B28.57%

C32.38%

D36.74%

Explanation:

Let the number of students be 2x, 3x, 4x.

Let the average marks be 4y,3y,y.

Average mark of class = ( 8xy+9xy+4xy)/(2x+3x+4x) =21xy/9x=7y/3

Percentage difference = ( 3y-7y/3)/7y/3 *100 = 28.57%

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The average salary of all the workers in a workshop is Rs. 8,000/-. The average salary of 7 technicians is Rs. 12,000/- and the average salary of the rest is Rs. 6,000/-. The total number of the workers in the workshop is

A20

B21

C22

D23

Explanation:

Let the total number of workers = X
Total salary of the workers = (8000*X)
Total salary of 7 technicians = (12000 * 7) = 84000
Total salary of others (X - 7) = [6000 * (X - 7)]
so 8000 * X = 84000 + 6000*X - 42000
=> 2000 * X = 42000
=> X = 21

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The average weight of 29 students is 28 kg. By the admission of a new student, the average weight is reduced to 27.8 kg. The weight of the new student is

A22 kg

B21.6 kg

C22.4 kg

D21 kg

Explanation:

Given Total weight of 29 students = 29 kg.

So Total weight of 29 students = (29* 28)
The total weight of 30 students = (30* 27.8)
Weight of the new student = ( 30*27.8 - 29*28)
= (834 - 812) = 22

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The average age of 50 students and a teacher is 25 years. When the teacher's age is excluded, the average age decreases by 1 year. What is the age of the teacher?

A65

B75

C74

D64

Explanation:

Given Average of ( 50 student + one Teacher) = 25 years.

So total age of 50 students and 1 teacher = (25 * 51) = 1275
Total age of the students = (24 * 50) = 1200.
Condition: when teacher age excluded Average age reduces by 1.

So age of the teacher = (1275 - 1200) = 75 years

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A batsman makes a score of 87 runs in the 17th match and thus increases his average by 3. Find his average after 17th match

A36

B37

C38

D39

Explanation:

Let the average after 17th match is x
then the average before 17th match is x-3

so 16(x-3) + 87 = 17x
=> x = 87 - 48 = 39

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