let x is first no.
So, x,x+1,x+2,x+3,x+4 are consecutive no.
avg. of this 5 no.
=> (x+x+1+x+2+x+3+x+4)/5=n
x+2=n; n=x+2
As per the question:
Add next 2 no.
so new avg = (x+x+1+x+2+x+3+x+4+x+5+x+6)/7=m
x+3=m ;m=x+3
New avg-Old avg=x+3-x-2=1
Increased by 1
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The average of four consecutive even numbers is 27. The largest of these numbers is :
Lets assume numbers as x, y, and z.
Given, 2nd is twice the 1st and three times the 3rd (i.e so y is the largest).
x = (1/2)*y
z = (1/3)*y
Average = y[1/2 + 1 + 1/3]/3
=> (11/18)y = 44. => y = 18*44/11 = 72.
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The average age of 30 students of a class is 12 years. The average age of a group of 5 of the students is 10 years and that of another group of 5 of them is 14 years. What is the average age of the remaining students ?
Given average of 30 students = 12 years.
So Total age of 30 students = 30*12 = 360 years.
First group total age = 5*10 = 50 years.
Second group total age = 5*14 = 60 years.
Remaining = 360-(50+70)=240
So, Average = 240/20 = 12 years.
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The average set of numbers is 46, if 4 numbers whose average is 52 are subtracted from this set,the average becomes 44.5.find the original number in the set?
Let us consider total no's in a set = n.
Sum of set= 46 * n.
=> 46*n-4*52=44.5*(n-4)
=> 46n-208=44.5n-178
=> 1.5n=30 =>n=20.
Hence, total no. in a set = 20.
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The average of 7 numbers is 50. The average of three of them is 40, while the average of the last three is 60. What must be the remaining number
Lets assume he made runs in 51st innings = x.
Given, Gavaskar got 50 in 50 innings
so, total score = 50*50 = 2500 runs.
Now at 51st inining, average = (2500+x)/51 = 51
=> x = (2601-2500) = 101 runs.
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In seven given numbers,the average of first four numbers is 4 and that of last four numbers is also 4. if the average of these seven numbers is 3, the fourth number is?
Lets assume 7 numbers as a,b,c,d,e,f,g.
Given Average of first 4 nums are 4.
=> (a+b+c+d)/4=4.
=> a+b+c+d=16 ------------ (1)
Given, Average of last 4 nums are also 4.
=> (d+e+f+g)/4=4.
=> d+e+f+g=16 -------- (2)
Given, Average of 7 nums are 3.
(a+b+c+d+e+f+g)/7=3
=> a+b+c+d+e+f+g=21 ---------- (3)
By eq. (1), (2) and (3)
=> 16+16-d=21 => d=32-21 => d=11.
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A train travels at an average speed of 90 km/hr without any stoppages. However, its average speed decrease to 60km/hr on account of stoppages. On an average, how many minutes per hour does the train stop?
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