The ratio between the P and Q age is 7: 9. If the difference between the present ages of Q and P's age after 4 years is 2 then what is the total of the present ages of P and Q?
As per Formula:
(If the given ages in a ratio a : b then age will be ax and bx)
So age of P will be 7x and Q will be 9x
As per the question:
(9x - 7x) +4 = 2,
=> x = 3
=> P present age will be = 21, Q age will be = 23
So Total of their Present age = 27 + 21 = 48
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7
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The ratio of the ages of priya and riya is 2:5. After 8 years, their ages will be in the ratio of 2:3. Then the sum of their present ages
As per Formula:
(If the given ages in a ratio a : b then age will be ax and bx)
so priya age = 2x and riya age = 5x.
So After 8 years their age ratio
(2x + 8)/(5x + 8) = 2/3
=> 6x + 24 = 10x + 16
=> 4x = 8
=> x = 2
so priya age will be 4 years and riya age will be 10 years
So their sum of age (priya and riya) = 14
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The ratio of the ages of two persons are in the ratio of 5:7 and the difference between their ages is 18 years. Find the sum of the ages of the persons after 5 years,
As per Formula:
(If the given ages in a ratio a : b then age will be ax and bx)
=> 7x - 5x = 18
=> 2x = 18 => x = 9
so Their age is 45 and 63 after 5 year their age will be 50 and 68
sum of age = 50 + 68 = 118 years.
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8
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10
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If P age is twice the average age of P, Q and R ages. Q's age is one half the average of P, Q and R's age. If the age of R is 5 years, then find the sum of ages of P, Q and R.
P = 2*(P + Q+ R)/3 --------(1)
Q = (1/2)*(P + Q+ R)/3 ------- (2)
and R = 5 -----------(3)
By solve the above equations,
=> P = 20, Q = 5 and R = 5
Sum of their ages = P+Q+R = 20 + 5 + 5 = 30 years.
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The sum of the age of mother and daughter is 100 years. 5 years ago their age were in the ratio of 2:1. The ratio of the age of daughter and mother after 10 years
As per Formula:
(If the given ages in a ratio a : b then age will be ax and bx)
Five year ago mother age = 2x years and daughter age = x years
Sum of their present ages = (2x+5) + (x+5) = 100
=> 3x + 10 = 100
=> x = 90/3 => x = 30
Present age of mother and daughter is 65 and 35 years respectively.
After 10 years ratio of daughter and mother ages = (35+10)/(65+10)
= 45/75 = 3/5
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46
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30
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76
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If 6 is subtracted from the present age of Ritu and the remainder is divided by 6, then the present age of Sheema is obtained. If Sheema is 4 years younger to raju whose age is 12 years, then find the age of Ritu
Lets assume Ritu present age = x years
so sheema age = (x-6)/6 years
As per question:
sheema age [(x-6)/6 + 4] = 12
(x-6)/6 = 12 - 4
=> (x-6)/6 = 8
=> x - 6 = 48 => x = 54
So Ritu age = 54 years.
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The difference between the age of the two persons is 6 years.Twelve years ago, the elder was thrice as old as the younger one.The present age of the elder
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