Five years ago the average age of a family of six members was 20 years. A baby is born and now the average age is 22 years. How old is the baby at present ?
Lets assume the age of all the 6 people = 20 years.
After 5 years i.e. now their ages will be 25 years.
Total age of all the 6 will be = 25*6 = 150
Including baby's age, avg is 22 years
Let x be the age of baby.
(150+x)/7 = 22
=> x = 4 years.
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At the end of the 1894 Suresh was half as old as his grandmother. The sum of the years was born in 3644. How old Suresh was at the end of 1899?
Lets assume Suresh age in 1894 = x.
So, Grandmothers age = 2x.
Year of birth for Suresh = (1894 - x)
and grandmother = (1894-2x)
Adding 2*1894 - 3x = 3644
=> x=48
At the end of 1899, age = (48 + 1899-1894) = 53
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8 year old Eesha visited her grandpa. He gave her this riddle. I started working at 13. I spent 1/6 of my working life in a factory. I spent 1/4 of my working life in an office, and I spent 1/4 of my working life as a school caretaker. For the last 32 years of my working life I've been doing social service. How old am I?
Let x be the number of years he worked.
=> x/6 + x/4 + x/4 + 32 = x
=> x = 96
So, his age = 96 + 13 = 109
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When I become as old as my father is now, I will be 5 times the age of my son. In addition, my son will be 8 yrs older than What I am now. If the sum of my father's age and my age is equal to100. How old is my son now?
Let us consider the ages of the man, his father & his son is m, f & s respectively.
Then according to the problem F = 5s ------------ (i)
S + f-m = m+8 ------------- (ii)
F + m = 100 -------------(iii)
Putting (i) in (iii) we get
5s + m = 100 ---------(iv)
By, Putting (i) in (ii)
6s-2m = 8 ------- (v)
By Eq. (iv) & (v)
s = 13, f = 65 & m = 36
So, Son age = 13 years.
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Today, the age of a father is thrice the age of his son. Ater 5 years the age of father will be 2.5 times the age of his son. What is the age of son today?
Let the age of son = S years and the age of father = F years.
According to the question,
=> F = 3*S.
=> F = 3S.
After 5 years,
=> (F+5) = 2.5 * (S+5).
=> 3S + 5 = 2.5S + 12.5 [put F=3S]
=> 0.5S = 7.5
=> S = 15
Hence, the age of son = 15 years.
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Currently, the age of a father is three times that of his son. 2.5 years from now, age of the father becomes 2.5 times that of the son. The age of son currently is?
Let m and l be the present ages of Martha and Lyndra
Then m = 4l
4 years ago (m-4) = 8(l-4)
m = 8l-28
Equate "m"
4l = 8l - 28
4l = 28
l = 7
m = 28
After x years , Martha will be twice of Lyndra
(m+x) = 2(l+x)
28+x = 2*7+2x
28+x = 14+2x
x = 14
S,o after 14 years martha and lyndra ages will be 42 and 21
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Six years ago I was three times as old as my brother, and now I am twice as old my brother. Find my brother’s age (years).
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