Lets assume father and son as x and y respectively.
So, five years ago.
=> x-5 = 5(9y-5) ------ (1)
After 2 years.
=> x+2 = 3(y+2) ------ (2)
By solving eq(1) & (2)
x/y=10/3.
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The average age of a woman and her daughter is 16 years. The ratio of their ages in 7 : 1 respectively. What is the woman's age?
Lets assume present ages of A, B and C as x,y, and z respectively.
Three years ago their ages were x-3,y-3,z-3.
Given:
=> (x-3+y-3+z-3)/3 = 27.
=> x+y+z=90.
and 5 years ago:
Then (x-5+y-5)/2=20.
=> y+z=50.
=> x=90-(y+z).
=> x=90-50 = 40 years.
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Total of the ages of A, B ahd C at present is 90 years. Ten years ago, the ratio of their ages was 1: 2: 3. What is the age of B at present
Lets assume suresh age = x years.
So, father age = (78-x) years.
Condition : 6 years hence
2* (x + 6) = (78 - x + 6)
=> 2x + 12 = 84 - x
=> 3x = 72
x = 24 years.
Father age = 78 - 24 = 54 years.
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A father is three times as old as his son. After fifteen years the father will be twice as old as his son's age at that time. Hence
the father's present age is
Lets assume son's current age = x years
So, father's current age = 3x
After 15 years (condition)
2(x+15)=3x+15
Son's age = 15 years, and father's age = 45 years.
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The sum of the ages of A,B and C was 52 three years ago.Four years ago B,who is a year younger than C,was 1 1/2 times as old as A.The sum of the ages of B and C two years hence,will be
Present sum of ages of A,B & C = A+B+C = 52+9=61 ---(i)
Given B is a year younger than C, so B+1 = C ---(ii)
Also B-4=(A-4)*3/2
=> 2B - 8 = 3A-12
=> 2B -3A= -4 ---(iii)
Substituting C=B+1 from (ii) in (i)
A+2B=60 ---(iv)
On solving (iii) & (iv)
A=16, B=22 so C=23
So sum of the ages of B & C two year hence= (B+2)+(C+2)=24+25 = 49 Years.
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A certain company retirement plan has a rule of 70 provision that allows an employee to retire when the employee's age plus years of employment with the company total at least 70. In what year could a female employee hired in 1986 on her 32nd birthday first be eligible to retire under this provision?
Lets assume it has taken x years to the female employee to reach the rule of 70.
So her age should be (32 + x).Also she gains x years of experience.
=> (32 + x) + x = 70
=> x = 19 years.
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In 4 years, Raj's father age twice as raj, Two years ago, Raj's mother's age twice as raj. If Raj is 32yrs old in eight yrs from now, what is the age of Raj's mother and father?
Raj present age = 32 - 8 = 24.
After 4 years Raj's age is 28. and Raj's fathers age is 28 x 2 = 56, and his present age is 52.
Two years ago, Raj's age is 22. and his mother's age is 22 x 2 = 44. His mother's present age = 46
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When Usha was thrice as old as Nisha, her sister Asha was 25, When Nisha was half as old as Asha, then sister Usha was 34. their ages add to 100. How old is Usha?
Let the age of Usha is 3x then Nisha is x and Asha is 25
Also Usha 34, Nisha y, and Asha 2y.
We know that 3x - 34 = x - 2y = 25 - 2y
Solving above three equations we get x = 9, y = 16
Their ages are 34, 16, 32. whose sum = 82. So after 18 years their ages will be equal to 100. So Usha age is 34 + 6 = 40
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