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# Problems on Ages Questions

Home > Quantitative Aptitude > Problems on Ages > General Questions
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When you reverse the digits of age of father you will get the age of son. one year ago the age of father was twice that of son's age. What are the current ages of father and son?

A73 & 37

B73 & 45

C65 & 37

DNone of these

Explanation:

When you reverse the digits of age of father you will get the age of son.

10x y = father's age

10y x = son's age

:

one year ago the age of father was twice that of son's age.

10x y - 1 = 2(10y x - 1)

10x y - 1 = 20y 2x - 2

10x - 2x = 20y - y - 2 1

8x = 19y - 1

x = 19/8y - 1/8

Only one set of single digit integers will satisfy this equation

y = 3; x = 7

Current ages of father and son

Dad is 73, son is 37

Check one year ago

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Joe's age , Joe's sister's age and Joe's fathers age sums up to a century. When sox s as old as his father, Joe's sister will be twice as old as now. When Joe is as old as his father then his father is twice as old as when his sister was as old as her father

AJoe=20 sister=35 father=50

BJoe=25 sister=30 father=50

CJoe=20 sister=30 father=50

DNone of these

Explanation:

Joe + joe's sister + father = 100 -------------(1)
After x years lets joe age is equal to his father
So. (joe + x) = father
Therefore, joe's sister + x = 2*sister
=>sister = x
joe+sister = father
therefore, 2*father=100
hence, Father=50, joe = 20 and sister = 30

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Find X's age which equals the number of grand children of a man who has 4 sons and 4 daughters. Each daughter of the man's wife have 3 sons and 4 daughters and each son of the man's wife have 4 sons and 3 daughters.

A53

B56

C43

DNone of these

Explanation:

Given, he had 4 sons and 4 daughters.
Each son has 4 sons and 3 daughters and each daughter has 3 sons and 4 daughters.
Therefore total number of grandsons = 4x4 + 4x3 = 16 + 12 = 28
And total number of grand daughters = 4x3 + 4x4 = 28
Total number of grandchildren is 28+28 = 56.

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At the time of his marriage Arunachalam was 29 years old. During marriage, his wife was younger by 3 1/2 years.20 years afterwards the total ages of Arunachalam, his wife and their only son Kamalraj is 110 years. What will be the age of Kamalraj forty years from now?

A45 1/2 years.

B35 1/2 years.

C30 years.

D25 years.

Explanation:

I. During Marriage
Arunachalam's age = 29 years
Wife's age = 29 - 3.5 = 25.5 years
II. 20 years afterwards
Arunachalam's age = 29 + 20 = 49 years
Wife's age = 25.5 + 20 = 45.5 years
Let Son's age (20 years after marriage) = S
It is given that, 20 years after wedding, Arunachalam's age + Wife's age + S = 110
Or 49 + 45.5 + S = 110
S = 15.5 years
III. 40 years afterwards.
Since we have found that the son was 15.5 years old 20 years after marriage, adding 20 to 15.5 will give age of Kamalraj after 40 years.
Therefore answer = 15.5 + 20 = 35.5 years =35 1/2 years.

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Each of Geetha's brothers have brothers as many as Leena's and Leena has sisters as many as her brothers. Then the sum of the boys in Geetha's family and girls in Leena's family will be

A9

B6

C13

D15

Explanation:

Let A be the number of boys in Geetha's family.
let B be the number of girls in Geetha's family.
let C be the number of boys in Leena's family.
let D be the number of girls in Leena's family.
We have to find the value of A + D.
Since A number of boys are in Geetha's family, every brother will have A - 1 brother.
Since each of Geetha's brothers and Leena have equal number of brothers then A - 1 = C ------(1)
Since Leena has equal number of brothers and sisters, D - 1 = C -----(2)
Sub C = D - 1 in eq 1,we get
A - 1 = D - 1
A = D
we know the fact that addition of two equal numbers must be an even number.
among the given options 6 is the only even number.

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A man whose age is 45 yrs has 3 sons named John, Jill, jack. He went to a park weekly twice. He loves his sons very much. On a certain day he found the shop keepers selling different things. An apple cost 1penny, 2chocalate costs 1penny & 3 bananas cost 1 penny. He has bought equal number of apple, chocolate & banana for each son. If the total amount he invest is 7 penny then how many he has bought from each piece for his son?

A1app, 1cho, 1 banana

B1 app, 2cho,3 banana

C1app, 2cho, 1banana

DNone of these

Explanation:

Here is no explanation for this answer

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At the end of 1994 Rohit was 1/4th as old as his grandmother. The sum of the years in which they were born is 3843. How old Rohit was at the end of 2001?

A48

B36

C29

D34

Explanation:

r=g/4, 1994-r 1994-g=3843, by solving we get r=29,

in 1994 rohit age was 29. therefore his age on 2001 is 36.

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After 6 years Raju's father will be twice that of his age and two years ago, his mothers age was twice of that of Raju's age. What is the sum of Raju's parent's age?

A4 less than four times Raju's age

B2 more than four times Raju's age

C4 more than four times Raju's age

D2 less than four times Raju's age

Explanation:

F+6=2(R+6)
F= 2R+6
M-2=2(R-2)
M= 2R-2
Therefore the sum of Raju's Parent's age is
F+M=2R+6+2R-2
F+M=4R+4
4 more than four times Raju's age

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Fathers age is 5 times his son's age. 4 years back the father was 9 times older than son.Find the fathers' present age.

A41

B40

C39

D45

Explanation:

Lets assume son's age = x years.
so father's age = 5x years
4 years back:
son age = (x-4) years.
father's age = (5x-4) years
as per Condition given
(5x-4) = 9*(x-4)
=> 5x - 4 = 9x - 36
=> (9x-5x) = 36 - 4
=> 4x = 32 => x = 8
So father's present age = 5 * 8 = 40 years.

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The age of Ritu's mother is 6 times that of Ritu's age. After 6 years it will be 3 times that of Ritu's age. what is Ritu's present age?

A4 years

B8 years

C6 years

D10 years

Explanation:

Lets assume Ritu age = x years.
So Ritu's mother age = 6x
After 6 years. 3(x+6)= (6x+6)
3x + 18 = 6x+6
=> 3x = 12 => x = 4 years.

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