At the time of marriage, a man was 6 years elder to his wife. 12 years after their marriage, his age is 6/5 times the age of his wife. What was wife's age at the time of marriage?
lets assume wifes age= x years.
So, husband age = (x+6) years.
After 12 years of marriage
wifes age = (x+12) Years.
husbands age = (x+6+12) Years = (x+18) Years.
6/5(x+12)=(x+18)
=> 6x + 72 = 5x + 90
=> x = 18 Years.
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Sum of ages of two friends is 32 while difference is 2 then their ages are
After 27 years sons age will be 27 years
and his fathers age will be 54
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When I was born, my mother was 23 years of age. After 6 years, when my sister was born, my father was 34 years of age. what is the difference between the ages of my parents?
When Son age = 0 year (born) ,Mother age was = 23 years.
After 6 years
Son=6 years,Mother age= (23+6)=29 years, and Father age = 34 years.
So difference between ages of Mother & Father = (34-29) = 5 years.
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The age of a father is 5/2 of his daughter. 5 years ago it was 3 times that of his daughter.what is daughter's present age?
Lets assume daughter's present age = x Years.
So, Father's present age = (5/2)*x Years.
5 years ago father's age = (5x/2)-5 = 3(x-5) Years.
Therefore,x=20 years
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A man is three years older than his wife and four times as old as his son. If the son attains an age of fifteen years after three years, what is the present age of the mother?
Ratio of ages fo A and B = 2:3
After 5 years their ages ratio = 3:4
=> ( 2x+5 ) /( 3x+5) = 3/4 => 8x+20=9x+15
=> x=5
So, Present age of A = 2x = (2*5) = 10 years.
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Ten years ago, P was half of Q in age. If the ratio of their present ages is 3:4, what will be the total of their present ages?
Ratio of their present ages = 3:4
So, the present age of P and Q will be 3x and 4x.
Given, Ten years ago P was half of Q in age.
=> (3x - 10) = (4x - 10)/2
=> 6x - 20 = 4x - 10
=> 2x = 10
=> x = 5
So, Total of their present ages = (3x + 4x) = 7x = 7*5 = 35
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A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, the how old is B?
Lets assume the age of C = x years
So B's age = 2x
A's age = 2x+2
Given, sum of their (A,B,C) ages = 27 years.
=> x+2x+2x+2 = 27
=> 5x=25
=> x = 5
So, B's age = 10 years.
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