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# Problems on Ages Questions

Home > Quantitative Aptitude > Problems on Ages > General Questions
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Choose the correct option.

At the time of marriage, a man was 6 years elder to his wife. 12 years after their marriage, his age is 6/5 times the age of his wife. What was wife's age at the time of marriage?

A36 years

B30 years

C18 years

D24 years

Answer: Option C

Explanation:

lets assume wifes age= x years.
So, husband age = (x+6) years.
After 12 years of marriage
wifes age = (x+12) Years.
husbands age = (x+6+12) Years = (x+18) Years.
6/5(x+12)=(x+18)
=> 6x + 72 = 5x + 90
=> x = 18 Years.

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Sum of ages of two friends is 32 while difference is 2 then their ages are

A15 years, 17 years

B17 years, 15 years

C16 years, 18 years

D18 years, 16 years

Answer: Option B

Explanation:

Lets assume a and b be two friends
So, (a+b)=32 ----- (1)
(a-b)=2 ------ (2)
a=17, b=15

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A boy is born when his father is 27 years old. How old will he be when he is exactly half his fathers' age?

A23 Years.

B24 Years.

C39 Years.

D27 Years.

Answer: Option D

Explanation:

After 27 years sons age will be 27 years
and his fathers age will be 54

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When I was born, my mother was 23 years of age. After 6 years, when my sister was born, my father was 34 years of age. what is the difference between the ages of my parents?

A17 years

B11 years

C6 years

D5 years

Answer: Option D

Explanation:

When Son age = 0 year (born) ,Mother age was = 23 years.
After 6 years
Son=6 years,Mother age= (23+6)=29 years, and Father age = 34 years.
So difference between ages of Mother & Father = (34-29) = 5 years.

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The age of a father is 5/2 of his daughter. 5 years ago it was 3 times that of his daughter.what is daughter's present age?

A20 Years

B25 Years

C15 Years

D10 Years

Answer: Option A

Explanation:

Lets assume daughter's present age = x Years.
So, Father's present age = (5/2)*x Years.
5 years ago father's age = (5x/2)-5 = 3(x-5) Years.
Therefore,x=20 years

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A man is three years older than his wife and four times as old as his son. If the son attains an age of fifteen years after three years, what is the present age of the mother?

A60 years

B51 years

C48 years

D45 years

Answer: Option D

Explanation:

Lets assume mother age = x
and Father age = x+3
x+3=4 * 12
=> x=45 years.

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Total of ages of A,B and C at present is 90 years. If ratio of this ages is 2 : 3 : 4 what will be the age of C after 5 years?

A45 years

B44 years

C40 years

D37 years

Answer: Option A

Explanation:

Given, ratio of A, B and C are 2 : 3 : 4
=> 2x+3x+4x=90
=> x=10
So, c=40
After 5 years
40+5 = 45 Years

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The ratio of ages of A and B at present is 2:3. After five years the ratio of their ages will be 3:4 What is the present age of A in years?

A10

B15

C25

D30

Answer: Option A

Explanation:

Ratio of ages fo A and B = 2:3
After 5 years their ages ratio = 3:4
=> ( 2x+5 ) /( 3x+5) = 3/4 => 8x+20=9x+15
=> x=5
So, Present age of A = 2x = (2*5) = 10 years.

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Ten years ago, P was half of Q in age. If the ratio of their present ages is 3:4, what will be the total of their present ages?

A45

B40

C35

D30

Answer: Option C

Explanation:

Ratio of their present ages = 3:4
So, the present age of P and Q will be 3x and 4x.
Given, Ten years ago P was half of Q in age.
=> (3x - 10) = (4x - 10)/2
=> 6x - 20 = 4x - 10
=> 2x = 10
=> x = 5
So, Total of their present ages = (3x + 4x) = 7x = 7*5 = 35

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A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, the how old is B?

A10 years

B5 years

C12 years

D7 years

Answer: Option A

Explanation:

Lets assume the age of C = x years
So B's age = 2x
A's age = 2x+2
Given, sum of their (A,B,C) ages = 27 years.
=> x+2x+2x+2 = 27
=> 5x=25
=> x = 5
So, B's age = 10 years.

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