A flight from Dubai to London is scheduled to leave Dubai at 10 am local time. London local time is 4 hours behind Dubai. The plan requires 9 hours to cover the distance. If the plane takes off two hours late, what will be the local time at London
When time in Dubai = 10 am
Time in London = 6 am
Scheduled arrival time at London = 6+9 = 15 = 3pm
Delay in flight = 2hrs
Actual Arrival = 3pm+2hr = 5pm
Workspace
NA
SHSTTON
9
Solv. Corr.
25
Solv. In. Corr.
34
Attempted
0 M:0 S
Avg. Time
82 / 88
Choose the correct option.
In a race from point X to point Y and back, Jack averages 30miles/hr to point Y and 10 miles/hr back to point X. Sandy averages 20 miles/hr in both directions. If Jack and Sandy start race at same time, who will finish first?
Arun drove from home to his hostel at 60 miles per hour. While returning home he drove half way along the same route at a speed of 25 miles per hour and then took a bypass road which increased his driving distance by 5 miles, but allowed him to drive at 50 miles per hour along this bypass road. If his return journey took 30 minutes more than his onward journey, then the total distance traveled by him is
A motorbike leaves point A at 1 pm and moves towards point B at a uniform speed. A car leaves point B at 2 pm and moves towards point A at a uniform speed which is double that of the motorbike. They meet at 3:40 pm at a point which is 168 km away from A. What is the distance, in km, between A and B7
Let ABC be a right-angled triangle with BC as the hypotenuse. Lengths of AB and AC are 15 km and 20 km, respectively. The minimum possible time, in minutes, required to reach the hypotenuse from A at a speed of 30 km per hour is
A man leaves his home and walks at a speed of 12 km per hour, reaching the railway station 10 minutes after the train had departed. If instead he had walked at a speed of 15 km per hour, he would have reached the station 10 minutes before the train's departure. The distance (in km) from his home to the railway station is
⇒ While A covers 1000 meters, B can cover 900 meters
⇒ While B covers 1000 meters, C can cover 900 meters
⇒ Lets assume that all three of them are running same race. So when B runs 900 meters, C can run 900 × 9/10 =810
⇒ So A can beat C by 190 meters.
Workspace
NA
SHSTTON
7
Solv. Corr.
3
Solv. In. Corr.
10
Attempted
0 M:0 S
Avg. Time
88 / 88
Choose the correct option.
Ram walks at a speed of 12 km/h. Today the day was very hot so walked at ⅚ of his average speed. He arrived his school 10 minutes late. Find the usual time he takes to cover the distance between his school and home?
⇒ If Ram is walking at ⅚ of his usual speed that means he is taking 6/5 of using time.
⇒ 6/5 of usual time - usual time = 10 mins
⇒ 1/5 of usual time = 10 mins
⇒ Usual time = 50 mins
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