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Time and Distance Questions

Home > Quantitative Aptitude > Time and Distance > General Questions
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A starts riding his bike at 10am with a speed of 20kmph and B also starts at 10am with a speed of 40kmph from the same point in the same direction. A turns south at 12 o'clock and B turns north at 11 am. What will be the distance between A and B at 2 pm?


A250 km

B120 km

C160 km

D145.6 km

Answer: Option C

Explanation:

At 12 o clock A cover 40km and on the other side B at 11 o clock cover 40km, again they traveled towards each other(which is actually the distance between them), that is A has to traveled 2hr(From 12 to 2 at 20km/hr) i.e 2*20=40km and other side B has to traveled 3hr(From 11 to 2 at 40km/hr) i.e 3*40=120Km.
Then the total distance traveled by them is the Actual distance between them ie 40+120=160Km(Ans.)

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60 litres of diesel is required to travel 600 km using a 800 cc engine. If the volume of diesel required to cover a distance varies directly as the capacity of the engine, then how many litres of diesel is required to travel 800 kms using 1200 cc engine?


A90 liters.

B100 liters.

C120 liters.

DNone of these

Answer: Option C

Explanation:

Let keep 800 cc constant and calculate amount of diesel for 800 kms.
800*60/600=80 liters.
Now, calculate diesel required for new distance i.e 800 km,
80*1200/800=120 liters.

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If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:


A50 km

B56 km

C70 km

D80 km

Answer: Option A

Explanation:

Let the actual distance travelled be x km.
Then, x/10 = (x + 20)/14.
=> 14x = 10x + 200
=> 4x = 200.
=> x = 50 km.

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A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:


A100 kmph

B110 kmph

C120 kmph

D130 kmph

Answer: Option C

Explanation:

Let speed of the car be x kmph.
Then, speed of the train = (150/100)x = (3/2)x kmph.
=> 75/x - 75/(3/2)x = 125 / (10 * 60)
=> 75/x - 50/x = 5/24.
=> x = (25 x 24)/5 = 120 kmph.

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The ratio between the speeds of two trains is 7 : 8. If the second train runs 400 km in 4 hours, then the speed of the first train is:


A70 km/hr

B75 km/hr

C84 km/hr

D87.5 km/hr

Answer: Option D

Explanation:

Let the speed of two trains be 7x and 8x km/hr.
Then, 8x = 400/4 = 100
=> x = 100/8 = 12.5.
So, the speed of first train = (7 x 12.5) km/hr = 87.5 km/hr.

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A man driving his bike at 24 kmph reaches his office 5 minutes late. Had he driven 25% faster on an average he would have reached 4 minutes earlier than the scheduled time. How far is his office?


A24 km

B72 km

C18 km

DData Insufficient

Answer: Option C

Explanation:

Let x km be the distance between his house and office. 

While travelling at 24kmph, he would take x/24  hours. 

While travelling at 25% faster speed,

i.e. 24 25% of 24=24×(1/4)=30 kmph, he would take x/30 hr



Now as per the problem, time difference = 5 min late 4 min early = 9 min

x/24-x/30=9 min



Solving this we get â‡’ x= 18 km



 

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A man drives 150 km from to in 3 hours and 20 minutes and returns to the place in 4 hours and 10 minutes. If is the average speed of the entire trip, then the average speed of the trip from to, exceeds by:


A5.0 km/hour

B4.5 km/hour

C4.0 km/hour

D2.5 km/hour

Answer: Option B

Explanation:

Let's assume Man drives From point A to B i.e 150 km.
Man drive (from point A to B) in 3 hours 20 minutes (i.e 3 + 1/3 = 10/3 hours) then Speed is 150/(10/3) = 45km/hr.
Return, Man drives (from point B to A) (same 150 km) in 4 hours 10 minutes (i.e 4+1/6 = 25/6 hr) then speed = 150/(25/6) = 36km/hr.
So, Average Speed (45+36)/2 = 40.5 km/hr.
So, Average speed exceeds Speed from to by (i.e from A to B by) = (45 - 40.5) = 4.5km/hr.

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Maria drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 9 hours. When Maria drove home, there was no traffic and the trip only took 4 hours. If her average rate was 40 miles per hour faster on the trip home, how far away does Maria live from the mountains?


A288 miles

B280 miles

C175 miles

D170 miles

Answer: Option A

Explanation:

Time taken for trip from home to mountains=9h
Time taken for trip from mountains to home=4h
Let distance from home to mountains=x miles
let average speed from home to mountains=y miles/h
Given avg speed on the trip home is 40m/h faster than speed from home to mountains=y+40 m/h
=> (x/9)=y and (x/4)=y+40
by solving this, we get y=32 m/h and the distance x=32*9=288 miles.

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Vikas can cover a distance in 1hr 24min by covering 2/3 of the distance at 4 kmph and the rest at 5kmph.the total distance is?


A8 km.

B9 km.

C8.4 km.

DNone of these

Answer: Option C

Explanation:

Lets assume total distance = x km.
vikas covered 2/3 of x = 4kmph*84min
so,
x = (4kmph*84min*3)/(2*60) = 8.4 km.

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Driving her car to work 4 days per week one costs $7.00 a day for parking and $36.00 a week for fuel. How much would she save week by taking a bus at a fuel at a fare of $1.30 each way?


A$53

B$56.60

C$53.60

DNone of these

Answer: Option C

Explanation:

as per the question (4 days per week one costs $7 )
So, total on fuel for week= 7*4=$28
and she expend on partking for week = $36
Total she expend per week = $(28+36) = $64
Per day by bus both side = 2*1.30= $2.60
Total cost 4 days of week = 4*2.60 = $10.40
So she save = ($64-$10.40) = $53.60

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