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# Time and Distance Questions

Home > Quantitative Aptitude > Time and Distance > General Questions
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A horse starts to chase a dog that has left the stable two hours earlier. The horse runs at an average speed of 22km/hr. It crosses a 10 metre road, two small ponds 3 metres deep, and finally runs along two small streets of 200 metres long. After traveling 6 hrs, 2 hrs after sunset, it catches the dog. Compute the speed of the dog in Km/hr?

A20 Km/hr

B22 Km/hr

C16.5 Km/hr

D18.5 Km/hr

Explanation:

We have the speed of horse = 22 kmph

And it ran for 6 hours.

Hence distance covered by it in 6 hours = 22 * 6

= 132 km

We know that dog has covered the same distance in 6 + 2 = 8 hours.

Hence speed of the dog = 132 / 8

= 16.5 kmph

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Ram and Shakil run a race of 2000 meters. First, Ram gives Shakil a start of 200 meters and beats him by one minute. If, Ram gives Shakil a start of 6 minutes Ram is beaten by 1000 meters. Find the time in minutes in which Ram and Shakil can run the races separately.

A12, 18

B10, 12

C11, 18

D8, 10

Explanation:

Let x & y be the speeds of Ram & Shakil
Then acc. To the problem
2000/x=1800/y-1 .... (i) and 1000/x=2000/y-6 ..... (ii)
Solving the above equations we get x=250m/sec and y=200m/sec
So to cover a distance of 2000m separately they will take 2000/250 and 2000/200 secs respectively.

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George walks 36 kms partly at a speed of 4 kms per hour and partly at 3 km per hour If he had walked at a speed of 3km per hour when he had walked at 4 and 4 km per when he had walked at 3 he would have walked only 34 kms. The time (in hours) spent by George in walking was

A8

B12

C5

D10

Explanation:

Let George walked "a" hours at 4 kmph, and "b" hours at 3 kmph.
Given, 4a + 3b = 36 - - - (1)
3a + 4b = 34 - - - (2)
Adding the above two equations and simplifying them, a + b = 10.

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George while driving along the highway saw road markers which are at equal distances from each other. He crosses the markers every 20 seconds. If he increases his speed by x meters per second, he crosses the markers at every 15 seconds. But if he increases his speed by y meters per second, he crosses the marker at every 10th second. If y-x = 40 meters per second, then what is the distance between two markers.

A1100

B1200

C1301

D1220

Explanation:

Let speed be =z m/s then Distance= 20z m (z+x)15=20z; (z+y)10=20z

Also given that y - x = 40 solving we get 20z=1200

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One day, Eesha started 30 minutes late from home and reached her office 50 minutes late, while driving 25% slower than her usual speed. How much time in minutes does Eesha usually take to reach her office from home?

A20

B40

C60

D80

Explanation:

Let us time taken by eesha daily = x
and usual speed = y
extra time taken = 50-30 = 20 min
So, (x+20)*(0.75*y) = x*y ----- (1)
0.75x+15 = x
=> 0.25x = 15
=> x = 60 min

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Tim and Elan are 90 km from each other, they start to move each other simultaneously, Tim at speed 10 and Elan 5kmph, if every hour they double their speed what is the distance that Tim will pass until he meet Elan?

A45

B60

C20

D80

Explanation:

1st hour=tim 10kmph elan 5 the dist will be 90-15=75
2nd hr=tim->20kmph & elan->10 dist=75-30=45
3rd hr =tim->40 & elan->20..the totl dist for 3rd hr is 60.but we need only 45km to meet ..so we consider only 45mins instead of 3rd hr..
In 45mins =>tim ->30 & elan->15
totl dist travld by tim is 10+20+30=60

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An old man and a young man are working together in an office and staying together in a near by apartment. The old man takes 30 minutes and the young 20 minutes to walk from appartment to office. If one day the old man started at 10.00 AM and the young man at 10:05AM from the apartment to office, when will they meet?

A10:15

B10:30

C10.45

D10:00

Explanation:

Ratio of old man speed to young man speed = 2:3
The distance covered by old man in 5 min = 10
The 10 unit is covered with relative speed=10/(3-2)=10 min

so, they will meet at 10:15 am.

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In a potato race, 20 potatoes are placed in a line of intervals of 4 meters with the first potato 24 meters from the starting point. A contestant is required to bring the potatoes back to the starting place one at a time. How far would he run in bringing back all the potatoes?

A2400

B1440

C2480

D1240

Explanation:

Given, total number of potatos = 20.
First potato 24 metres from the starting point. There are 4 meters in the intervals. A contestant is required to bring the potatoes back to the starting place one at a time. So for the first potato he has to travel 48 meters, for second 56 meters ...
48,56,64............20 terms.
a = 48, d= 8, n = 20.

Important Point:
Sum of n terms in A.P = Sn=n2[2a+(n?1)d]

S20 = 202[2*48+(20?1)8]
S20 = 202[96+152]
S20 = 10*248 = 2480

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Ferrari is leading car manufacturer. Ferrari S.P.A. is an Italian sports car. It has enjoyed great success. If Mohan's Ferrari is 3 times faster than his old MERCEDES which gave him 35 km/ph if Mohan travelled 490 km in his Ferrari the how much time in hours he took?

A4

B4.7

C4.2

D4.3

Explanation:

Time = (Distance/Speed) = (490/35)
Therefore the total time = time/3 = (490/35)/3 = 4.6666 ~ 4.7

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My flight takes off at 2am from a place at 18N 10E and landed 10 Hrs later at a place with coordinates 36N 70W.What is the local time when my plane landed?

A6:00 am

B6:40 AM

C7:40 am

D7:00 am

Explanation:

Latitudianal difference=(10+70)=80
So, time difference=80X4=320mins=5 hrs 20 mins
Since the place is located towards west
Therefore local time of that place during take off=8:40 p.m.
So, local time during landing=8:40p.m.+10hrs=6:40a.m

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