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Time and Distance Questions

Home > Quantitative Aptitude > Time and Distance > General Questions
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Vivek travelled 1200km by air which formed 2/5 of his trip.One third of the whole trip , he travelled by car and the rest of the journey he performed by train. The distance travelled by tain was:


A1000km

B900km

C700km

D800km

Answer: Option D

Explanation:

Let the total trip be x km.
Then 2x/5=1200
x=1200*5/2=3000km
Distance travelled by car =1/3*3000=1000km
Journey by train =[3000-(1200+1000)]=800km.

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A girl rode her bicycle from home to school, a distance of 15 miles, at an average speed of 15 miles per hour. She returned home from school by walking at an average speed of 5 miles per hour. What was her average speed for the round trip if she took the same route in both directions?


A8.5 miles/hr.

B7 miles/hr.

C7.5 miles/hr.

DNone of these

Answer: Option C

Explanation:

Avg speed=(total disance)/(total time)
Total distance= 15+15 = 30 miles.
Total time= 1+3=4 hrs.
So average Spedd = 30/4 = 7.5 miles/hr.

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Car A leaves city C at 5pm and is driven at a speed of 40 kmph. Two hours later another car leaves city C and is driven in same direction as car A. In how much time car B be 9 km ahead of car A if the speed of car B is 60 kmph.


A4 hr

B4 hr 10min

C4 hr 37min

D4 hr 27min

Answer: Option D

Explanation:

Given, car A speed = 40 kmph,
car B speed 60 kmph

Relative speed=(60-40)=20 kmph(as both are in same direction)

when car B started A has already covered distance = 40*2=80m

Time required for both car to be at same position = 80/20 = 4 hr

Additional distance = 9 km
Time required to cover this distance = (9/20)*60=27 min

Therefore, required time = 4hrs 27 min

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J is faster than P. J and P each walk 24 km. Sum of the speeds of J and P is 7 kmph. Sum of time taken by them is 14 hours. Then speed of J is equal to


A5 kmph

B2 kmph

C4 kmph

D7 kmph

Answer: Option C

Explanation:

As per the question: J > P ---(1)
and J + P = 7 ----- (2)
So, the below option can satisfy above both eq. (1) & (2)
(6, 1), (5, 2), (4, 3)
sum of time taken by them = 14 hrs. ---- (3)
To satisfy the 3rd condition

If J = 4 and P = 3.
Times taken by them = 24/4 + 24/3 = 14.

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A person travels in a car with uniform speed. He observes the milestone,which has 2 digits. After one hour he observes another milestone with same digits reversed. After another hour he observes another milestone with same 2 digits separated by 0. Find the speed of the car?


A40 Kmph

B55 Kmph

C50 Kmph

D45 Kmph

Answer: Option D

Explanation:

Let 10'splace digit is x and unit's place digit y

First milestone : 10x+y
Second milestone : 10y+x
Third milestone: 100x+y

Since the speed is uniform so
Distance covered in first Hr = Distance covered in Second Hr
(10y+x)-(10x+y) = (100x+y)-(10y+x)
By solving,
y=6x
but since x and y are digits so only possible combination is x=1 and y=6,
So average speed = 45 Kmph

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In a covering a certain distance, the speeds of A and B are in the ratio of 3:4. A takes 30 minutes more than B to reach the destination. The time taken by A to reach the destination is?


A3 hours.

B2 1/2 hours.

C2 1/4 hours.

D2 hours.

Answer: Option D

Explanation:

As per the question:
Ratio of speeds = 3:4
Ratio of times taken = 4:3
Suppose A takes 4x hrs and B takes 3x hrs to reach the destination.
Then, 4x - 3x = 30/60 => x = 1/2
Time taken by A = 4x hrs = 4 * 1/2 = 2 hrs.

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A ship went on a voyage after 180 miles a plane started with 10 times speed that of the ship. Find the distance when they meet from starting point.


A200

B202

C120

D100

Answer: Option A

Explanation:

Lets assume u is the speed of ship and 10u is of plane.
So, relative speed = 9u
Distance covered = (time to meet * speed of plane)
=180*10u/9u =200 miles

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Agil is twice as fast as Mugil.Mugil is thrice as fast as Annie. The distance covered by Annie in 54 minutes will be covered by Mugil in ___ minutes.


A27 min.

B9 min.

C38 min.

D18 min.

Answer: Option D

Explanation:

Let Annie's speed be X km/hr.
Its given, Mugil is thrice as fast as Annie. Therefore Mugil's speed be 3X km/hr.
Also it is said Agil is twice as fast as Mugil. Therefore, Agil's speed = Mugil's speed x 2 = 6X km/hr.
Therefore ratio of their speeds = 6X : 3X : X = 6 : 3 : 1
For a given distance, the time taken will be inversely proportional to speed.
Therefore, Ratio of times taken by the three friends Agil, Mugil and Annie = 1/6 : 1/3 : 1 = 1 : 2 : 6
If Annie takes 6 minutes then Mugil takes 2 minutes.
If Annie takes 54 minutes then Mugil takes [2/6 * 54]= 18 minutes.
Hence the answer is 18 minutes.

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Ferrari S.P.A is an Italian sports car manufacturer based in Maranello, Italy. Founded by Enzo Ferrari in 1928 as Scuderia Ferrari, the company sponsored drivers and manufactured race cars before moving into production of street-legal vehicles in 1947 as Ferrari S.P.A. Throughout its history, the company has been noted for its continued participation in racing, especially in Formula One where it has employed great success .Rohit once bought a Ferrari. It could go 4 times as fast as Mohan's old Mercedes. If the speed of Mohan's Mercedes is 35 km/hr and the distance traveled by the Ferrari is 490 km, find the total time taken for Rohit to drive that distance.


A20.72

B3.5

C238.25

D6.18

Answer: Option B

Explanation:

Speed of Ferrari =4*35=140,time=distance/velocity

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At 12.00 hours Ravi starts to walk from his house at 8 kms an hour. At 13.30 hours, Shankar follows him from Ravi's house on his bicycle at 12 kms per hour. When will Ravi be 6 kms behind Paul?


A18:00hrs

B18:30hrs

C20:00hrs

D19:30hrs

Answer: Option A

Explanation:

Here is no explanation for this answer

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