# Placement Questions & Answers :: Accenture

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61. In a mixture of petrol and kerosene, petrol is only 99 litres. If this same quantity of petrol would be presented in another mixture of petrol and kerosene where total volume would be 198 litres less than the actual mixture then the concentration of petrol In the present mixture would have been 13.33% point less than that. What is the concentration of petrol in actual mixture?

**Answer:**** Option C **

**Explanation:**

Lets assume amount of petrol = x

So, (x*100)/198=13.33

x=26.3934

Now same amount of petrol is in 99 liters also.

so the percentage in actual mixture is

(26.3934*100)/99 =26.66%

**ShortCut By ::**

**RAKESH RAWAT**

Ans=20%

(99/(t-198))*100 - (99/t)*100= 13.33

on solving t=495

so in actual mixture, conc of petrol= 99/495*100= 20%

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62. In a election between two candidate 10% of votes were invalid winner got 70% of valid votes and was elected by a majority of 900 votes. find the total number of votes?

**Answer:**** Option C **

**Explanation:**

Lets assume votes = x

valid votes are 0.9x,

Given 70% of 0.9x is 900 more than 30% of 0.9x,

=> 0.9*0.7-900=0.3*0.9x

=> x=2500

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63. log base 12 144p=3 then p= ?

**Answer:**** Option A **

**Explanation:**

log base 12 144p=3

=> 144p=12^3

=> 144p=12^2 *12

=> 144p=144*12

=> p=12

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64. 3 men and 8 women complete a task in same time as 6 men and 2 women do. How much fraction of work will be finished in same time if 4 men and 5 women will do that task.

**Answer:**** Option C **

**Explanation:**

3M + 8W = 6M + 2W ---------(1)

solving this we get

M = 2W

Therefore 3M + 8W = 14W

4M + 5W =13W

=>fraction of work is 13/14

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65. The sum of ages of suresh and his father is 78 years.6 years hence father's age will be twice of suresh's age. Find present age of father.

**Answer:**** Option A **

**Explanation:**

Lets assume suresh age = x years.

So, father age = (78-x) years.

Condition : 6 years hence

2* (x + 6) = (78 - x + 6)

=> 2x + 12 = 84 - x

=> 3x = 72

x = 24 years.

Father age = 78 - 24 = 54 years.

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66. In this question A^B means A raised to the power of B Start with the integers from 1 to 10^2012. Replace each of them by the sum of its digits to get a string of 10^2012 numbers. Keep doing this until you get 10^2012 single digit numbers. Let m be the number of 1's and n be the number of 2's. Then m - n

**Answer:**** Option A **

**Explanation:**

We divide all the numbers into groups of 9. (1 to 9), (10 to 18).....

Now when we divide each term in the first group by 9, we get 1, 2, 3 ..0 as remainders. Now digit sum is nothing but finding remainder when a number is divided by 9. So the last term, 10^2012 gives remainder 1 when divided by 9. So there is one "1" extra than 2's.

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67. Two trains A and B start simultaneously from stations X and Y towards each other respectively. After meeting at a point between X and Y,train A reaches station Y in 9 hours and train B reaches station X in 4 hours from the time they have met each other. If the speed of trainA is 36 km/hr, what is the speed of train B?

**Answer:**** Option B **

**Explanation:**

Naming the trains as A and B. Then,

(A's speed) : (B's speed) = (b : a)^.5

where b and a is the time taken by trains B and A, to reach their destination after they meet.

hence,

36/B's speed = (4: 9)^.5

=> B's speed = 54km/hr

**ShortCut By ::**

**yogen**

s1/s2=underroot(t2/t1)

s1/s2=underroot(4/9)

s1/s2=2/3

in question value of 2 is 36kmph

therefore value of 3 i.e s2 will be 54kmph

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68. Five different roads join a village to nearby city. The no. of different ways in which a person can go to town and come back is ?

**Answer:**** Option A **

**Explanation:**

If we choose 1st road, To come back we have 5 ways..

similarly for 2nd,3rd,4th,5th road.

so total ways = 5+5+5+5+5 = 25 ways

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69. Which of the following values of 'n' satisfies the in-equality n2 - 24n + 143 < 0?

**Answer:**** Option C **

**Explanation:**

n^2 - 24n + 143 < 0

=> (n-11)(n-13) < 0

=> 11 < n < 13

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70. A car starts from rest and accelerates uniform upto speed 90 km/hrs in 5 sec. Total distance covered by car in this time will be

**Answer:**** Option A **

**Explanation:**

Speed of car at last instant of given interval

= 90*5/ 18 m/s = 25 m/s

so average speed = 0+25 / 2

Therefore distance = 5 * 25/2 = 125/2 = 62.5 m

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Here is the list of questions asked in Accenture Aptitude Test Question with Answers Accenture Mock Test page 7. Practice Accenture Written Test Papers with Solutions and take Q4Interview Accenture Online Test Questions to crack Accenture written round test. Overall the level of the Accenture Online Assessment Test is moderate. Only those candidates who clear the written exam will qualify for the next round, so practic all the questions here and take all the free tests before going for final selection process of Accenture