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Accenture Placement Questions & Answers :: Accenture

140.76K

Tot. Mock Test: 5


Total Qs: 107+

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Choose the correct option.

Cost of an item is x. It's value increases by p% and decreases by p% Now the new value is 1 rupee, what is the actual value ?


A10000/[10000-(p^2)]

B1000/[1000-(p^2)]

C100/[100-(p^2)]

DNone of these

Answer: Option A

Explanation:

Given cost of an item = Rs. X
Item cost by increasing p% will be = x(100+p)/100
After p% decrement, value = {x+(xp/100)}-[{x+(xp/100)}p/100]
= [x+(xp/100)] [1-(p/100)]
= x[1+(p/100)][1-(p/100)]
Givne new value is 1
x[1-((p^2)/10000)] = 1
x = 1/[1-((p^2)/10000)] = 10000/[10000-(p^2)]

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NA
SHSTTON
25
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45
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52 / 107

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how many matches would have to be played to decide a winner in a knockout tournament consisting of eight teams?


A7

B6

C8

D5

Answer: Option A

Explanation:

1 match for 2 team, first 8 team = 4 match
4 team - 2 match
2 team - 1 match
So, Total = 4+2+1=7 match

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NA
SHSTTON
17
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20
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37
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53 / 107

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A man traveled from the village to the post-office at the rate of 25 kmph and walked back at the rate of 4 kmph. If the whole journey took 5 hours 48 minutes, find the distance of the post-office from the village.


A12 Km.

B32 Km

C22 Km.

D20 Km.

Answer: Option D

Explanation:

Average speed = (2*a*b)/(a + b) here a = 25 b = 4
Average speed = 2*25 * 4/(25 + 4) = 200/29 kmph.
Distance covered in 5 hours 48 minutes = Speed * time
Distance = (200/29)*(29/5) = 40 kms
Distance covered in 5 hours 48 minutes = 40 kms
Distance of the post office from the village = (40/2) =20 km.

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NA
SHSTTON
29
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17
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46
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54 / 107

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There ara two bags A and B. A contains 6 red flowers and 3 pink flowers. where as bag B contains 2 red flowers and 7 pink flowers. One flower is choosen from a bag randomly. What is the probability that the flower choosen is pink?


A4/9

B1/3

C5/9

D3/9

Answer: Option C

Explanation:

Probability of pink ball=((1/2)*3/9)+((1/2)*7/9)=5/9

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NA
SHSTTON
9
Solv. Corr.
22
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31
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55 / 107

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Three friends Gerard, Rooney and Ronaldson work together to dig a hole. Gerard alone can complete the work in 10 days, Rooney in 8 days and together all three can complete it in 4 days. They earn a total of Rs. 1,200. Find the share of Rooney if the money that they receive is proportional to the work that they do?


ARs 480

BRs 165.51

CRs 500

DRs 600

Answer: Option D

Explanation:

Ronaldson can complete work in 40 days ( 1/4-1/10-1/8)
So, ratio of work done = 1/10 :1/8 : 1/40 = 4 : 5 : 1
So, amount payed rooney = 1200 * (5 / (5+4+1) ) = 1200 * 1/2 = 600

So, Rooney share = 1200/2 = 600

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NA
SHSTTON
25
Solv. Corr.
19
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44
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0 M:14 S
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56 / 107

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A train runs first half of the distance at 40 km/hr and the remaining half at 60 km/hr. What is the average speed for the entire journey?


A28 Km/hr.

B52 Km/hr.

C48 Km/hr.

DNone of these

Answer: Option C

Explanation:

Avg speed=2xy/(x+y)
=2*40*60/100 = 48 Km/hr.

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NA
SHSTTON
26
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13
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57 / 107

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The product of two positive numbers is p. If each of the numbers is increased by 2, the new product is how much greater twice the sum of the two original numbers?


A3

B4

C5

D2

Answer: Option B

Explanation:

Lets assume number are x,y
So, there product = xy
Given number increased by 2
so, now number are x+2,y+2.
Given product is twice the sum of two original No.
=> product = (x+2)(y+2) = 2(x+y)
=> xy+2x+2y+4 =2(x+y)
=> xy+4
so it increase by 4

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NA
SHSTTON
15
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20
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35
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The price of a jewel, passing through three hands, rises on the whole by 65%. If the first and second sellers earned 20% and 25% profit respectively, find the percentage profit earned by the third seller.


A10%

B22%

C18%

D12%

Answer: Option A

Explanation:

Lets assume the original price of the jewel = Rs. P
and profit earned by the third seller= x%.

Then, ( 100 +x )% of 125% of 120% of P = 165% of p
=> [ ( 100+x )/100*125/100*120/100* P ] = [ 165/100* P ]
=> ( 100 + X ) = (165*100*100)/(125*120) = 110,
=> X = 10%.

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NA
SHSTTON
36
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find the number between 100 to 400 which is divisible by either 2,3,5,7..


A120

B100

C205

D210

Answer: Option D

Explanation:

LCM of 2,3,5,7=210

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NA
SHSTTON
15
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23
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38
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60 / 107

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In a mixture of petrol and kerosene, petrol is only 99 litres. If this same quantity of petrol would be presented in another mixture of petrol and kerosene where total volume would be 198 litres less than the actual mixture then the concentration of petrol In the present mixture would have been 13.33% point less than that. What is the concentration of petrol in actual mixture?


A20%

B16.66%

C26.66%

D8.33%

Answer: Option C

Explanation:

Lets assume amount of petrol = x
So, (x*100)/198=13.33
x=26.3934
Now same amount of petrol is in 99 liters also.
so the percentage in actual mixture is
(26.3934*100)/99 =26.66%

ShortCut By :: RAKESH RAWAT

Ans=20%
(99/(t-198))*100 - (99/t)*100= 13.33
on solving t=495
so in actual mixture, conc of petrol= 99/495*100= 20%

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Here is the list of questions asked in Online Aptitude Test for Accenture Accenture online arithmetic test. Practice Accenture Written Test Papers with Solutions and take Q4Interview Accenture Online Test Questions to crack Accenture written round test. Overall the level of the Accenture Online Assessment Test is moderate. Only those candidates who clear the written exam will qualify for the next round, so practic all the questions here and take all the free tests before going for final selection process of Accenture