# Accenture Placement Questions & Answers :: Accenture

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31 / 136

**Choose the correct option.**

The average number of visitors of a library in the first 4 days of a week was 58. The average for the 2nd, 3rd, 4th and 5th days was 60.If the number of visitors on the 1st and 5th days were in the ratio 7:8 then what is the number of visitors on the 5th day of the library?

A64

B56

C45

D43

**Answer:**** Option A **

**Explanation:**

If number of visitors on 1st, 2nd, 3rd, 4th & 5th day are a, b, c, d & e respectively, then

a+b+c+d=58*4=232 ----(i)

b+c+d+e=60*4=240 ----(ii)

Subtracting eq. (i) from (ii)

e-a=8 ---(iii)

Given, a/e=7/8 ---(iv)

So from eq. (iii) & (iv)

a=56, e=64

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32 / 136

**Choose the correct option.**

Find the smallest number which leaves 22,35, 48 and 61 as remainders when divided by 26, 39, 52 and 65 respectively.

A886

B776

C786

D675

**Answer:**** Option B **

**Explanation:**

26-22=4

39-35=4

52-48=4

65-61=4

LCM of (26,39,52,65)=780

So smallest number = (780-4) = 776

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33 / 136

**Choose the correct option.**

A constructor estimates that 3 people can paint Mr. khans house in 4 days. If he uses 4 people instead of 3,how long will they take to complete the job?

A4

B2

C3

D5

**Answer:**** Option C **

**Explanation:**

Lets assume day required to complete the job = x day

Men Day

---------------------

3(u) 4(d)

4 x

x/4 = 3/4

=> x = 3 days.

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34 / 136

**Choose the correct option.**

In a party attended by 11 persons, each clinch their glass with every other. How many glass clinches?

A55

B45

C56

D46

**Answer:**** Option A **

**Explanation:**

Total no. of person = 11

Total no. of glass clinches = n(n-1)/2

=11*10/2 = 55

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35 / 136

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Two circles touch each other externally. The distance between their centres is 14 cm and the sum of their areas is 130 cm^2. Find their radii.

A9, 5

B13, 1

C11,3

D10,4

**Answer:**** Option C **

**Explanation:**

Lets assume the radius of 1st circle = x cm.

so, the radius of 2nd circle = (14-x)cm.

(pi*x*x)+(pi*(14-x)*(14-x))=130

By solving above eq.

x = 11 or 3

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36 / 136

**Choose the correct option.**

A vessel is filled to its capacity with pure milk. Ten litres are withdrawn from it and replaced by water. This procedure is repeated again. The vessel now has 32 litres of milk. Find the capacity of the vessel (in litres).

A40 litres.

B50 litres.

C2 litres.

DNone of these

**Answer:**** Option B **

**Explanation:**

Lets assume the capacity of the vessel = x litres.

x (1- 10/x)^2 = 32

x^2 +100-20x = 32x

x^2 +100 - 52x= 0

x^2 - 50x - 2x + 100 = 0

=> (x-2) (x-50) = 0

=> x=2 & x=50

As 10 litres is withdrawn so vessel capacity will be 50 litres.

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37 / 136

**Choose the correct option.**

Two pipes can fill a tank in 10 hours and 12 hours respectively while a third, pipe empties the full tank in 20 hours. If all the three pipes operate simultaneously, in how much time will the tank be filled?

A8.5 hrs.

B6 hrs.

C8 hrs.

D7.5 hrs.

**Answer:**** Option D **

**Explanation:**

Given, All the pipes are operate simultaneously

=> Tank filled in 1 hrs = 1/10+1/12-1/20 = 16/120 = 2/15

So, time taken to fill the tank = 15/2 = 7.5 hrs.

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38 / 136

**Choose the correct option.**

If the sales tax reduced from 3 1/2% to 3 1/3%, then what difference does it make to a person who purchases an article with market price of Rs. 8400 ?

ARs. 12

BRs. 24

CRs. 14

DNone of these

**Answer:**** Option C **

**Explanation:**

Tax reduced from 3 1/2 or 7/2% to 3 1/3% or 10/3%.

So, the difference in tax = (7/2 - 10/3)% = 1/6%.

=> 1/6 % of Rs. 8400 = 8400*1/6% = 8400* (1/6 * 1/100) = Rs. 14.

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39 / 136

**Choose the correct option.**

In a stream running at 2 kmph,a motar boat goes 6 km upstream and back again to the starting point in 33 minutes. Find the speed of the motarboat in still water.

A24 km/hr

B22 km/hr

C21 km/hr

DNone of these

**Answer:**** Option B **

**Explanation:**

Lets assume speed of boat in still water = x km/hr

So boat downstream speed = (x+2) km/hr.

boat upstream speed = (x-2) km/hr.

6/(x-2)+6/(x+2)=33/60 => 6/(x-2)+6/(x+2)=11/20

=> 120*[(x-2) + (x+2)] = 11*x^2 -44

=> 240 x = 11*x^2-44

=> 11* x^2 -240x -44 = 0 ---------(1)

By solving eq. (1)

x = 22 km/hr.

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40 / 136

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Exact time of a clock was set right at 5:00 am then it loses 16 min. every day, on the 4th day when it shows 10:00 am, what is the exact time?

A10:52 AM

B11:05 AM

C10:42 AM

D10:52 PM

**Answer:**** Option A **

**Explanation:**

Total late in three day = 16*3 = 48 min.

Total late in one day =16 min.

so late in 1 min. = 16/(24*60) = 0.01111;

Hence in 5 hour (5:00 AM to 10:00 AM on 4th day) =.0111*5*60 = 3.333;

So, Exact time will be = 10:52 AM.

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Accenture Campus Recruitment written test is conducted by aspiring minds. The test had 3 sections i.e Quantitative Aptitude, Logical Reasoning and Verbal Ability. Practice accenture placement questions with Answers and take Q4Interview accenture aptitude test to crack Accenture Online Aptitude Test. Overall the level of the Accenture Written Test Papers is moderate. Only those candidates who clear the accenture placement mock test will qualify for the next round i.e Group Interview. So prepare well for this round