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# Accenture Placement Questions & Answers :: Accenture

140.78K

## Total Qs: 107+

NA
SHSTTON
23
Solv. Corr.
26
Solv. In. Corr.
49
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31 / 107

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The average number of visitors of a library in the first 4 days of a week was 58. The average for the 2nd, 3rd, 4th and 5th days was 60.If the number of visitors on the 1st and 5th days were in the ratio 7:8 then what is the number of visitors on the 5th day of the library?

A64

B56

C45

D43

| | Important Formulas | Topic: | Asked In Accenture |

Explanation:

If number of visitors on 1st, 2nd, 3rd, 4th & 5th day are a, b, c, d & e respectively, then
a+b+c+d=58*4=232 ----(i)
b+c+d+e=60*4=240 ----(ii)
Subtracting eq. (i) from (ii)
e-a=8 ---(iii)
Given, a/e=7/8 ---(iv)
So from eq. (iii) & (iv)
a=56, e=64

Tags: Accenture

NA
SHSTTON
18
Solv. Corr.
40
Solv. In. Corr.
58
Attempted
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Find the smallest number which leaves 22,35, 48 and 61 as remainders when divided by 26, 39, 52 and 65 respectively.

A886

B776

C786

D675

| | Important Formulas | Topic: | Asked In Accenture |

Explanation:

26-22=4
39-35=4
52-48=4
65-61=4
LCM of (26,39,52,65)=780
So smallest number = (780-4) = 776

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NA
SHSTTON
21
Solv. Corr.
18
Solv. In. Corr.
39
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A constructor estimates that 3 people can paint Mr. khans house in 4 days. If he uses 4 people instead of 3,how long will they take to complete the job?

A4

B2

C3

D5

| | Important Formulas | Topic: | Asked In Accenture |

Explanation:

Lets assume day required to complete the job = x day

Men Day
---------------------
3(u) 4(d)
4 x
x/4 = 3/4
=> x = 3 days.

Tags: Accenture

NA
SHSTTON
22
Solv. Corr.
18
Solv. In. Corr.
40
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In a party attended by 11 persons, each clinch their glass with every other. How many glass clinches?

A55

B45

C56

D46

| | Important Formulas | Topic: | Asked In Accenture |

Explanation:

Total no. of person = 11
Total no. of glass clinches = n(n-1)/2
=11*10/2 = 55

Tags: Accenture

NA
SHSTTON
12
Solv. Corr.
31
Solv. In. Corr.
43
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Two circles touch each other externally. The distance between their centres is 14 cm and the sum of their areas is 130 cm^2. Find their radii.

A9, 5

B13, 1

C11,3

D10,4

| | Important Formulas | Topic: | Asked In Accenture |

Explanation:

Lets assume the radius of 1st circle = x cm.
so, the radius of 2nd circle = (14-x)cm.

(pi*x*x)+(pi*(14-x)*(14-x))=130
By solving above eq.
x = 11 or 3

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NA
SHSTTON
21
Solv. Corr.
21
Solv. In. Corr.
42
Attempted
29 M:59 S
Avg. Time

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A vessel is filled to its capacity with pure milk. Ten litres are withdrawn from it and replaced by water. This procedure is repeated again. The vessel now has 32 litres of milk. Find the capacity of the vessel (in litres).

A40 litres.

B50 litres.

C2 litres.

DNone of these

| | Important Formulas | Topic: | Asked In Accenture |

Explanation:

Lets assume the capacity of the vessel = x litres.
x (1- 10/x)^2 = 32
x^2 +100-20x = 32x
x^2 +100 - 52x= 0
x^2 - 50x - 2x + 100 = 0
=> (x-2) (x-50) = 0
=> x=2 & x=50
As 10 litres is withdrawn so vessel capacity will be 50 litres.

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NA
SHSTTON
16
Solv. Corr.
22
Solv. In. Corr.
38
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Two pipes can fill a tank in 10 hours and 12 hours respectively while a third, pipe empties the full tank in 20 hours. If all the three pipes operate simultaneously, in how much time will the tank be filled?

A8.5 hrs.

B6 hrs.

C8 hrs.

D7.5 hrs.

| | Important Formulas | Topic: | Asked In Accenture |

Explanation:

Given, All the pipes are operate simultaneously
=> Tank filled in 1 hrs = 1/10+1/12-1/20 = 16/120 = 2/15
So, time taken to fill the tank = 15/2 = 7.5 hrs.

Tags: Accenture

NA
SHSTTON
21
Solv. Corr.
26
Solv. In. Corr.
47
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38 / 107

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If the sales tax reduced from 3 1/2% to 3 1/3%, then what difference does it make to a person who purchases an article with market price of Rs. 8400 ?

ARs. 12

BRs. 24

CRs. 14

DNone of these

| | Important Formulas | Topic: | Asked In Accenture |

Explanation:

Tax reduced from 3 1/2 or 7/2% to 3 1/3% or 10/3%.
So, the difference in tax = (7/2 - 10/3)% = 1/6%.
=> 1/6 % of Rs. 8400 = 8400*1/6% = 8400* (1/6 * 1/100) = Rs. 14.

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NA
SHSTTON
16
Solv. Corr.
27
Solv. In. Corr.
43
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In a stream running at 2 kmph,a motar boat goes 6 km upstream and back again to the starting point in 33 minutes. Find the speed of the motarboat in still water.

A24 km/hr

B22 km/hr

C21 km/hr

DNone of these

| | Important Formulas | Topic: | Asked In Accenture |

Explanation:

Lets assume speed of boat in still water = x km/hr
So boat downstream speed = (x+2) km/hr.
boat upstream speed = (x-2) km/hr.

6/(x-2)+6/(x+2)=33/60 => 6/(x-2)+6/(x+2)=11/20
=> 120*[(x-2) + (x+2)] = 11*x^2 -44
=> 240 x = 11*x^2-44
=> 11* x^2 -240x -44 = 0 ---------(1)
By solving eq. (1)
x = 22 km/hr.

Tags: Accenture

NA
SHSTTON
12
Solv. Corr.
26
Solv. In. Corr.
38
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Exact time of a clock was set right at 5:00 am then it loses 16 min. every day, on the 4th day when it shows 10:00 am, what is the exact time?

A10:52 AM

B11:05 AM

C10:42 AM

D10:52 PM

| | Important Formulas | Topic: | Asked In Accenture |

Explanation:

Total late in three day = 16*3 = 48 min.
Total late in one day =16 min.
so late in 1 min. = 16/(24*60) = 0.01111;
Hence in 5 hour (5:00 AM to 10:00 AM on 4th day) =.0111*5*60 = 3.333;
So, Exact time will be = 10:52 AM. 