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# Accenture Placement Questions & Answers :: Accenture

150.39K

## Total Qs: 135+

NA
SHSTTON
17
Solv. Corr.
32
Solv. In. Corr.
49
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0 M:0 S
Avg. Time

71 / 135

Choose the correct option.

If a man reduces the selling price of a fan from 400 to 380 his loss increases by 20% .What is the cost price of fan ?

A400

B500

C450

D550

Explanation:

Lets assume the cost price = x.
So, initial loss = (x - 400).
Given, 20% ( x - 400) = 20
=> (x - 400) = 100
=> x = 500

Tags: Accenture

NA
SHSTTON
24
Solv. Corr.
22
Solv. In. Corr.
46
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A piece of ribbon 4 yards long is used to make bows requiring 15 inches of ribbon for each. What is the maximum number of bows that can be made?

A8

B9

C10

D11

Explanation:

1 yard = 3 feet = 3*12 = 36 inches
4 yard = 4*36 = 144 inches
The maximum number of bows will be 4 yards divided by 15 inches = 144/15 = 9.6

Tags: Accenture

NA
SHSTTON
8
Solv. Corr.
20
Solv. In. Corr.
28
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73 / 135

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Q is as much younger than R as he is older than T. If the sum of the ages of R and T is 50 years, what is definitely the difference between R and Q's age?

A1 year

B2 years

C25 years

Explanation:

As per question R > Q > T
So, R - Q = Q - T and R + T = 50
By solving above 2 condition.
=> Q = 25
As the difference between R & Q and Q & T is same
So it is 25 years

Tags: Accenture

NA
SHSTTON
7
Solv. Corr.
17
Solv. In. Corr.
24
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In an exam, Ajith, Sachu, Karna, Saheep and Ramesh scored an average of 39 marks. Saheep scored 7 marks more than Ramesh. Ramesh scored 9 fewer than Ajith. Sachu scored as many as Saheep and Ramesh scored. Sachu and Karna scored 110 marks between them. If Ajith scores 32 marks then how many marks did Karna score?

A57

B75

C55

D45

Explanation:

Lets assume marks of Ajith, Sachu, Karna, Saheep and Ramesh respectively u, v, w, x, y
So, as per the question:
z+7=x ---(i)
u- 9=z ---(ii)
x+ z=v ---(iii)
v+w=110 ---(iv)
Given, u=32 ---- (v)
By solving eq. (i), (ii), (iii), (iv) and (v)
w=57

Tags: Accenture

NA
SHSTTON
16
Solv. Corr.
16
Solv. In. Corr.
32
Attempted
0 M:11 S
Avg. Time

75 / 135

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Silu and Meenu were walking on the road. Silu said,

A58 Kgs.

B60 Kgs.

C48 Kgs.

D62 Kgs.

Explanation:

Given that Meenu weighs 29 Kgs plus half of her own weight.
It means that 29 Kgs is the other half. So she weighs 58 Kgs.
Solving mathematically, let's assume that her weight is A Kgs.
A = 29 + A/2
2*A = 58 + A
A = 58 Kgs.

Tags: Accenture

NA
SHSTTON
14
Solv. Corr.
29
Solv. In. Corr.
43
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76 / 135

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A man purchased a watch for Rs.400 and sold it at a gain of 20% of the selling price. The selling price of the watch is:

ARs. 500

BRs. 460

CRs. 480

DRs. 440

Explanation:

Given Cost price of watch = 400
and Gain% = 20% of SP
20%of SP = SP - CP
CP = SP(1-20/100)
=> CP = SP*4/5
=> SP = CP * 5/4
=>SP = 400*5/4
=> SP = Rs. 500

NOTE:
If the question if it would have given like"purchased for Rs. 400 and sold it at a gain of 20% of the Cost price ?"
Then
Given Cost price of watch = 400
and Gain% = 20%
Gain = 400 * 20/100 = 80
Cost price = (400 + 80) = 480

As in this questions it has given "purchased for Rs. 400 and sold it at a gain of 20% of the Selling price ?"

Tags: Accenture

NA
SHSTTON
26
Solv. Corr.
14
Solv. In. Corr.
40
Attempted
1 M:29 S
Avg. Time

77 / 135

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A new apartment complex purchased 60 toilets and 20 shower heads. If the price of a toilet is three times the price of a shower head, what percent of the total cost was the cost of all the shower heads?

A9%

B10%

C11%

D13%

Explanation:

Lets assume the cost of shower head = x.
So,cost of the toilet = 3x.
Total cost of 60 toilets and 20 shower heads = 60 * 3x + 20* x = 200x
So shower heads cost as a percentage of total cost = (200x/20x)% = 10%

Tags: Accenture

NA
SHSTTON
36
Solv. Corr.
21
Solv. In. Corr.
57
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78 / 135

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A two-digit number is such that the product of the digits is 8. When 18 is added to the number, then the digits are reversed. The number is:

A18

B24

C42

D81

Explanation:

Check the options, by subtracting 18 from each option for getting reverse number.
42 - 18 = 24 (which is in reverse)

Tags: Accenture

NA
SHSTTON
29
Solv. Corr.
31
Solv. In. Corr.
60
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Two guys work at some speed. After some time one guy realises he has done only half of the other guy completed which is equal to half of what is left So how much faster than the other is this guy supposed to do to finish with the first.

A2 times

B3 times

C5 times

DNone of these

Explanation:

If x is the part of task this is completed then,
1st has done work = (1 - x)/4
and 2nd has done work = (1- x)/2
So 2nd will have to increase his speed by 2 times.

Tags: Accenture

NA
SHSTTON
66
Solv. Corr.
22
Solv. In. Corr.
88
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80 / 135

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A teacher can divide her class into groups into groups of 5,13 and 17. What is the smallest possible strength of the class?

A835

B940

C1105

D1220