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71. In a potato race, 20 potatoes are placed in a line of intervals of 4 meters with the first potato 24 meters from the starting point. A contestant is required to bring the potatoes back to the starting place one at a time. How far would he run in bringing back all the potatoes?
Answer: Option C
Explanation:Given, total number of potatos = 20.
First potato 24 metres from the starting point. There are 4 meters in the intervals. A contestant is required to bring the potatoes back to the starting place one at a time. So for the first potato he has to travel 48 meters, for second 56 meters ...
48,56,64............20 terms.
a = 48, d= 8, n = 20.
Important Point:
Sum of n terms in A.P = Sn=n2[2a+(n?1)d]
S20 = 202[2*48+(20?1)8]
S20 = 202[96+152]
S20 = 10*248 = 2480
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TCS
72. Ferrari is leading car manufacturer. Ferrari S.P.A. is an Italian sports car. It has enjoyed great success. If Mohan's Ferrari is 3 times faster than his old MERCEDES which gave him 35 km/ph if Mohan travelled 490 km in his Ferrari the how much time in hours he took?
Answer: Option B
Explanation:Time = (Distance/Speed) = (490/35)
Therefore the total time = time/3 = (490/35)/3 = 4.6666 ~ 4.7
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TCS
73. My flight takes off at 2am from a place at 18N 10E and landed 10 Hrs later at a place with coordinates 36N 70W.What is the local time when my plane landed?
Answer: Option B
Explanation:Latitudianal difference=(10+70)=80
So, time difference=80X4=320mins=5 hrs 20 mins
Since the place is located towards west
Therefore local time of that place during take off=8:40 p.m.
So, local time during landing=8:40p.m.+10hrs=6:40a.m
Workspace
TCS
74. Two people A and B starts running at 10:00 AM towards north at a speed of 40Kmph and 60Kmph respectively. After 2 hours(12:00 noon ), A turned left and B turned right. They stopped at 2:00 PM.Find the distance between A and B at 2:00 PM.
Answer: Option D
Explanation:Here is no explanation for this answer
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TCS
75. The time taken to travel from city X to city Y is 12 hrs. If a person starts at 6 A.M from city x and another person leaves in city y at 8 P.M. When they will meet.
Answer: Option A
Explanation:Here is no explanation for this answer
Workspace
iGate
76. A man leaves office daily at 7pm. A driver withcar comes from his home to pick him from office and bring back home. One day he gets free at 5:30 andinstead of waiting for driver he starts walking towards home. In the way he meets the car and returns home on car. He reaches home 20 minutes earlier than usual. In how much time does the man reach home usually?
Answer: Option A
Explanation:Here is no explanation for this answer
Workspace
iGate
77. A car is 15 minutes late by running at a speed of 4/5th of its actual speed. The actual time taken by the car to cover that distance is
Answer: Option B
Explanation:Here is no explanation for this answer
Workspace
iGate
78. A boy standing idle sounds a whistle to his friend at a distance of 1200 m moving away from him in a speeding car at 108 kmph. Find the duration (seconds) after which his friend is going to hear him. (Speedof sound = 330m/sec).
Answer: Option B
Explanation:Here is no explanation for this answer
Workspace
iGate
79. A man takes 5 hours 45 min in walking to a certain place and riding back. He would have gained 2 hours by riding both ways. The time he would take to walk both ways is
Answer: Option C
Explanation:Here is no explanation for this answer
Workspace
iGate
80. A person traveled from his house to office at 30 kmph, then he was late to his office by 5 minutes. If he increases his speed by 10 kmph he would be early by 15 minutes to his office. What should be his speed so that he reaches his office on time ?
Answer: Option B
Explanation:Let the distance between house and office be x km.
=> (x/30) – (x/40) = 20/40;
=> x/120 = (1/3)x = 40 km
Travelling at 40 kmph, he reaches office in 1 hour i.e. 15 minutes early. So, required speed = 40/ 5/4 = 40 * 4/5 = 160/5 = 32 kmph
Workspace
iGate