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# Problems on Time and Work

Home > Quantitative Aptitude > Time and Work > General Questions
NA
SHSTTON
58
Solv. Corr.
85
Solv. In. Corr.
143
Attempted
1 M:9 S
Avg. Time

71 / 100

Choose the correct option.

Rishab starts for a weeding venue at 6:00 pm and drives at a speed of 60km/hr. Ramesh starts for the same venue at 6.30 pm,and drives at a speed of 75km/hr. When will both reach the venue,provided they reach at the same time.

A8.00pm

B9.30pm

C9pm

D8.30pm

Explanation:

Acc. to the question both of them travel the same distance. Let it be d
d= 60*t1 and d= 75*t2. Rishabh time= t1 and Ramesh time= t2
Also t1= t2+30; ---- (i)
So 60*t1= 75*t2 => t1= 5/4t2 putting this t1 value in eq.(i)
We get 5/4t2-t2=30 hence t2= 2 hrs.
So t2 is the time of Ramesh time hence 6:30p.m+ 2 hrs= 8:30pm

Workspace

NA
SHSTTON
42
Solv. Corr.
57
Solv. In. Corr.
99
Attempted
0 M:0 S
Avg. Time

72 / 100

Choose the correct option.

To finish a piece of work, P takes Five times as Q and six times as R. Working together, they can finish the work in 4 days. Q can do the work alone in:

A24 days

B48/5 days

C13 days

D11 days

Explanation:

Lets assume Q take x days to finish the work
so P take time = 5x, and R take time R=5x/6
Given, They took 4 day to finish the work.
1/5x+1/x+6/5x= 1/4 => 12/5x = 1/4
x=48/5
So, Q can do work alone in 48/5 days.

Workspace

NA
SHSTTON
45
Solv. Corr.
64
Solv. In. Corr.
109
Attempted
0 M:43 S
Avg. Time

73 / 100

Choose the correct option.

Two guys work at some speed. After some time one guy realises he has done only half of the other guy completed which is equal to half of what is left So how much faster than the other is this guy supposed to do to finish with the first.

A2 times

B3 times

C5 times

DNone of these

Explanation:

If x is the part of task this is completed then,
1st has done work = (1 - x)/4
and 2nd has done work = (1- x)/2
So 2nd will have to increase his speed by 2 times.

Workspace

NA
SHSTTON
21
Solv. Corr.
42
Solv. In. Corr.
63
Attempted
0 M:17 S
Avg. Time

74 / 100

Choose the correct option.

A is 30% more efficient than B. How much time will they, working together, take to complete a job which A alone could have done in 23 days?

A13 days

B15 days

C23 1/12 days

DNone of these

Explanation:

Ratio of times taken by A and B = 100 : 130 = 10 : 13.

Suppose B takes x days to do the work.
Then, 10 : 13 :: 23 : x
=> x = (23 * 13)/10
=> x = 299/10

A's 1 day's work = 1/23
B's 1 day's work = 10/299
(A + B)'s 1 day's work = (1/23 + 10/299) = 23/299 = 1/13 .

So, A and B together can complete the work = 13 days.

Workspace

NA
SHSTTON
21
Solv. Corr.
19
Solv. In. Corr.
40
Attempted
0 M:0 S
Avg. Time

75 / 100

Choose the correct option.

A works thrice as much as B. If A takes 60 days less than B to do a work then find the number of days it would take to complete the work if both work together?

A221 days

B221/2 days

C223/2 days

DNone of these

Explanation:

Given A works trice as much as B
So the ratio between A and B = 3:1
so 3x-x=60
and x = 30
so 1/90+1/30=221/2 days

Workspace

NA
SHSTTON
29
Solv. Corr.
11
Solv. In. Corr.
40
Attempted
0 M:0 S
Avg. Time

76 / 100

Choose the correct option.

Tony alone can paint a wall in 7 days and his friend Roy alone can paint the same wall in 9 days. In how many days they can paint the wall working together? Round off the answer to the nearest integer.

A3

B4

C5

D7

Explanation:

use formula (xy / x+y)
So nearest value for 3.93 = 4

Workspace

NA
SHSTTON
27
Solv. Corr.
22
Solv. In. Corr.
49
Attempted
0 M:0 S
Avg. Time

77 / 100

Choose the correct option.

4 men can check exam papers in 8 days working 5 hours regularly. What is the total hours when 2 men will check the double of the papers in 20 days?

A8 hrs.

B9 hrs.

C4 hrs.

DNone of these

Explanation:

Let a man can do 1 unit of work in 1 hour.
Total units of work = 4 * 8 * 5 = 160 units.
Now work = 2 * 160 = 320 units.
Now 2 men work for 20 days. Let in x hours they have to work per day.
Now total work = 2*x*20 = 40 x
40x = 320 So x = 320/40 = 8 hours.

Workspace

NA
SHSTTON
44
Solv. Corr.
28
Solv. In. Corr.
72
Attempted
0 M:0 S
Avg. Time

78 / 100

Choose the correct option.

George can do some work in 8 hours: Paul can do some work in 10 hours while Hari can do the same work in 12 hours. All the three of them start working at 9 a.m. while George stops work at 11 a.m. and the remaining two complete the work. Approximately at what time the work be finished?

A11:30 a.m.

B1 p.m.

C12 noon

D12:30 p.m.

Explanation:

Chocolate method : Take Lcm of george,paul and Hilllari we get LCM(8,10,12)=120
Let the no of chocolates are 120 in that
George can eat 15 chocolates/hr
paul can eat 12cho/hr
Hillari can eat 10cho/hr
total choclates they can eat in 1 hr =Paul + George+hillari=15+12+10=37choclates
for 9:00 to 11:00 difference -2hrs
so for 2 hrs they can eat 37*2=74
George left after 11 remaing choclates are 120-74=46
Paul and hillari can eat=12+10=32/hr
=46/32 =2 hrs approx so ans is 11:00 + 2hrs =1:00 pm

Workspace

NA
SHSTTON
14
Solv. Corr.
27
Solv. In. Corr.
41
Attempted
0 M:0 S
Avg. Time

79 / 100

Choose the correct option.

2 workers, one young and one old, live together and work at the same office. It takes 20 minutes for the young man to walk to office. The old man takes 30 minutes for the same distance. When will the young man catch up with the old man if the old man starts at 10:00 a.m. and the young man start 10:05 a.m.?

A11:00 a.m.

B10:20 a.m.

C10:10 a.m.

D10:15 a.m.

Explanation:

Time ratio is 3:2, so
3 min for old = 2 min fro young
1 min for old = 2/3 min fro young
Now we will take multiple of 3 both side,
3 min for old = 2 min fro young
6 min for old = 4 min fro young
9 min for old = 6 min fro young
12 min for old = 8 min fro young
15 min for old = 10 min fro young and so on
Now the difference of time to start for old and young is 5 min. So when they meet then old will take 5 minute more than young ( or their time difference should be 5 min) which is given by only
15 min for old = 10 min fro young
So at 10:15 for old and for young it is 10:05 + 10 min = 10:15

Workspace

NA
SHSTTON
25
Solv. Corr.
30
Solv. In. Corr.
55
Attempted
0 M:0 S
Avg. Time

80 / 100

Choose the correct option.

A,B ,C can do some work in 36 days. A and B together do twice as much work as C can do alone, and A and C together can do thrice as much work as B alone can do. Find the time taken by C to do whole work?

A96 days.

B108 days.

C120 days.

D72 days.

Explanation:

Given A, B and C can do some work = 36 days.

=> (A+B+C) can do work in 1 day = 1/36
=> (A+B+C) = 1/36 -----------------(i)
Given (A+B) = 2C ----------------(ii)

From eq. (i)and(ii)
3C = 1/36
C = 1/108

=> C takes 108 days to complete whole work alone.

Workspace

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