41 / 100
A group of workers can do a piece of work in 24 days. However as 7 of them were absent it took 30 days to complete the work. How many people actually worked on the job to complete it?
A10
B50
C40
D28
Answer: Option D
Explanation:Let the original number of workers in the group be 'x'
Therefore, actual number of workers = x-7.
We know that the number of manhours required to do the job is the same in both the cases.
Therefore, x (24) = (x-7).30
24x = 30x - 210
6x = 210
x = 35.
So, the actual number of workers who worked to complete the job = x - 7 = 35 -7 = 28.
Workspace
42 / 100
Two persons A and B working together can dig a trench in 8 hrs while A alone can dig it in 12 hrs. In how many hours B alone can dig such a trench?
A20 hours.
B14 hours.
C24 hours.
DNone of these
Answer: Option C
Explanation:Given (A+B)'s one hours work = 1/8
and A's one hours work =1/12
Therefore, B's one hours work = (1/8-1/12) =1/24.
So, B alone can dig the trench = 24 hours.
Workspace
43 / 100
X alone can do a piece of work in 15 days and Y alone can do it in 10 days. X and Y undertook to do it for Rs. 720. With the help of Z they finished it in 5 days. How much is paid to Z?
ARs. 80.
BRs. 120.
CRs. 110.
DNone of these
Answer: Option B
Explanation:In one day X can finish 1/15 th of the work.
In one day Y can finish 1/10 th of the work.
Let us say that in one day Z can finish 1/Z th of the work.
When all the three work together in one day they can finish 1/15 + 1/10 + 1/Z = 1/5 of the work.
Therefore, 1/Z = 1/30.
Ratio of their efficiencies = 1/15: 1/10: 1/30 = 2: 3: 1.Therefore Z receives 1/6 of the total money.
According to their efficiencies money is divided as 240: 360: 120.
S0, the share of Z = Rs. 120.
Workspace
44 / 100
A and B can do a piece of work in 12 days. B and C can do it the same work in 20 days. In how many days will A, B and C finishes it working all together? Also, find the number of days taken by each to finish it working alone?
ATogether=10 days, A=20 days, B=30 days, C=60 days
BTogether=10 days, A=30 days, B=20 days, C=60 days
CTogether=15 days, A=300 days, B=20 days, C=60 days
DTogether=20 days, A=20 days, B=30 days, C=50 days
Answer: Option B
Explanation:Given (A+B)â€™s one dayâ€™s work=1/12 ---- (1)
(B+C)â€™s one dayâ€™s work=1/15 ------- (2)
and (A+C)â€™s one dayâ€™s work=1/20. -------- (3)
By eq. 1, 2 and 3
2(A+B+C)â€™s one dayâ€™s work = (1/12+1/15+1/20)=1/5.
=> (A+B+C)â€™s one dayâ€™s work=1/10.
=> A, B and C together can finish the work in 10 days.
Now, Aâ€™s one dayâ€™s work
= [(A+B+C)â€™s one dayâ€™s work] â€“ [(B+C)â€™s one dayâ€™s work]
= 1/10-1/15)
= 1/30.
Therefore, A alone can finish the work in 30 days.
Similarly, Bâ€™s 1 dayâ€™s work = (1/10 -1/20) = 1/20.
Therefore, B alone can finish the work in 20 days.
And, Câ€™s 1 dayâ€™s work= (1/10-1/12) = 1/60.
Therefore, C alone can finish the work in 60 days.
Workspace
45 / 100
Jake can dig a well in 16 days. Paul can dig the same well in 24 days. Jake, Paul and Hari together dig the well in 8 days. Hari alone can dig the well in ?
A24 days.
B48 days.
C36 days.
D27 days.
Answer: Option B
Explanation:As Jake , Paul and Hari can dig the well in 8 days,
Jack one day work = 1/16
Paul one day work = 1/24
Given, (Jake,Paul and hari) 1 day work = 1/8
So, 1/16 + 1/24 + 1/x = 1/8
=> 1/x=1/48
Therefore, Paul can finished work in 48 days.
Workspace
46 / 100
15 men take 21 days of 8 hrs. each to do a piece of work. How many days of 6 hrs. each would it take for 21 women if 3 women do as much work as 2 men?
A30
B20
C19
D29
Answer: Option A
Explanation:15 men - 8hrs - 21 days ( Its given 3 women = 2 men so 21 women= 14 men)
15 men - 1 hr - 21*8days
1 man - 1 hr - 21*8*15 days =2520 days
1 man - 6 hours - 2520/6 days
14 men - 6 hours - 2520/(14*6)= 30 days
Workspace
47 / 100
A completes a work in 2 days, B in 4 days, C in 9 and D in 18 days. They form group of two such that difference is maximum between them to complete the work. What is difference in the number of days they complete that work?
A14/3
B8/3
C3/5
DNone of these
Answer: Option A
Explanation:If C and D form a pair and A and B form a pair the difference is maximum.
Now C and D together can complete the work = 9*189+189*189+18 = 6 days.
A and B together can complete the work = 2*42 + 42*42 + 4 = 4/3 days.
Difference = (6 - 4/3) = 14/3 days.
Workspace
48 / 100
A alone can do a piece of work in 6 days and B alone in 8 days. A and B undertook to do it for Rs 3200. With the help of C, they completed the work in 3 days. How much is to be paid to C?
ARs. 375
BRs. 400
CRs. 600
DRs. 800
Answer: Option B
Explanation:A's 1 day work = 1/6
B's 1 day work = 1/8
So, C's 1 day's work = 1/3 - (1/6 + 1/8) = (1/3 - 7/24) = 1/24.
So, A's wages : B's wages : C's wages
=> 1/6 : 1/8 : 1/24 = 4:3:1
So, C's share = (1/8 * 3200) = Rs 400.
Workspace
49 / 100
Hanuman can complete a bridge in 10 days and Ravanan can complete the same bridge in 20 days. Now they are working together and they are completing the bridge in 20 days. What is the contribution of Ravanan in constructing the bridge?
AHalf the work
BOne-third of the work
CTwo-fourth of the bridge
DDestructing the bridge
Answer: Option D
Explanation:Hanuman= 10 days so in 1 day= 1/10
Ravanan = 20 days so in 1 day= 1/20
If Ravanan helps Hanuman then their one day work will be =1/10+1/20= 3/20 so they can complete the bridge in 20/3 days= 6.33 days
But acc. to the question the bridge is constructed in 20 days so its only possible when Ravanan is involved in
destructing the bridge coz (1/10-1/20)= 1/20
hence 20 days required to built the bridge.
Workspace
50 / 100
Daniel can do some work in 12 hours, Roy can do the same work in 10 hours while Hillari can do the same work in 15 hours. All the three of them start working at 9 a.m while Daniel stops works at 11 a.m and remaining two complete the work. Approximately at what time will the work be finished?
A1.30 pm
B12.30 am
C2.00 pm
D1.00 pm
Answer: Option C
Explanation:Daniel= 12 hrs so 1 hr work = 1/12 Similarly Roy= 1/10 and Hillari =1/15
In 1 hr they will do 1/12+1/10+1/15= 1/2 in 1 hr
so in 2 hrs (9 am -11 am) work done is 1/2
Now Daniel stops working so Roy and Hillari work together
1/10+1/15 = 1/6 in 1 hr
So 1 in 6 hr hence 1/2 in 3 hr hence three hours from 11 am they will finish the work that is 2pm.
Workspace
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