A can lay railway track between two given stations in 16 days and B can do the same job in 12 days. With the help of C, they did the job in 4 days only. Then, C alone can do the job in :
1 day's work done by A = 1/16
1 day's work done by B = 1/12
1 day's work done by (A, B and C) = 1/4
=> so C 1 day's work = (1/4-1/12-1/16) = (12/48-4/48-3/48) = 5/48
so C alone can do the work = 48/5 days = 9 3/5 days
Workspace
NA
SHSTTON
47
Solv. Corr.
61
Solv. In. Corr.
108
Attempted
1 M:52 S
Avg. Time
22 / 100
Choose the correct option.
A takes twice as much time as B or thrice as much time to finish a piece of work. Working together, they can finish the work in 2 days. B can do the work alone in .
Let's suppose A, B and C take x, x/2 and x/3 hours respectively to finish the work.
So their 1 day's work (1/x+2/x+3/x)=1/2 => 6/x = 1/2
=> x=12
So, B take 6) hours to finish the work.
Workspace
NA
SHSTTON
46
Solv. Corr.
55
Solv. In. Corr.
101
Attempted
2 M:3 S
Avg. Time
23 / 100
Choose the correct option.
A machine P can print one lakh books in 8 hours, machine Q can print the same number of books in 10 hours while machine R can print them in 12 hours. if All the machines are started at 9 a.m. while machine P is closed at 11 a.m. and the remaining two machines complete the work. Approximately at what time will the work be finished ?
find the (P + Q + R)'s 1 hour's work = (1/8+1/10+1/12) = 37/120
So Work done by P, Q and R in 2 hours = (2*37/120) = 37/60
Now find the Remaining work = (1?37/60) = 23/60
(Q + R)'s 1 hour's work = (1/10+1/12) = 11/60
OR
Time taken to do 11/60 part of work by (Q+R) = 1 hrs.
=> so to do whole work by (Q&R) = 60/11 hrs
so for 23/60 part of work = (23/60*60/11) hrs. = 23/11 = ~2 hrs.
So, the work will be finished approximately 2 hours after 11 a.m . i.e., around 1 p.m.
Workspace
NA
SHSTTON
44
Solv. Corr.
47
Solv. In. Corr.
91
Attempted
0 M:59 S
Avg. Time
24 / 100
Choose the correct option.
A and B can complete a work in 15 days and 10 days respectively. They started doing the work together but after 2 days B had to leave and A alone completed the remaining work. The whole work was completed in:
A 1 day work = 1/15
or
1/15 work is done by A in = 1 day.
? 2/3 work will be done by A = (15?2/3) = 10 days.
so total time required = (10 + 2) = 12 days.
Workspace
NA
SHSTTON
56
Solv. Corr.
34
Solv. In. Corr.
90
Attempted
2 M:6 S
Avg. Time
25 / 100
Choose the correct option.
A can finish a work in 24 days, B in 9 days and C in 12 days. B and C start the work but are forced to leave after 3 days. The remaining work was done by A in :
A's 1 day work = 1/24
B's 1 day work = 1/9
C's 1 day work = 1/12
S0 (B + C)'s 1 day's work = (1/9+1/12)=7/36
Work done by B and C in 3 days = (3*7/36)=7/12
left work = (1?7/12)=5/12
.
1/24 part of work done by A = 1 day.
So 5/12 part of work is done by A = (24?5/12) = 10 days.
Workspace
NA
SHSTTON
48
Solv. Corr.
41
Solv. In. Corr.
89
Attempted
1 M:22 S
Avg. Time
26 / 100
Choose the correct option.
P can do a piece of work in 40 days. He works at it for 8 days arid then Q finished it in 16 days. How long will they together take to complete the work ?
P one day work = 1/40
So P 8 days Work = (8*1/40)=1/5
Left work = (1?1/5)=4/5
4/5 part of work is done by Q = 16 days.
So Whole work will be done by Q = [16/(4/5)] = 16*5/4 = 20 days.
Q's 1 day's work = 1/20
(P + Q)'s 1 day's work = (1/40+1/20) = 3/40
Hence,( P and Q) together complete the work = 40/3=13 1/3 days.
Workspace
NA
SHSTTON
54
Solv. Corr.
33
Solv. In. Corr.
87
Attempted
1 M:30 S
Avg. Time
27 / 100
Choose the correct option.
A does 4/5 of a work in 20 days. He then calls in B and they together finish the remaining work in 3 days. How long B alone would take to do the whole work ?
Whole work will be none by A and B = (3 x 5) = 15 days.
A's 1 day's work = 1/25
(A + B)'s 1 day's work = 1/15
B's 1 day's work = (1/15?1/25)=10/(15*25)=2/75
So, B alone would do the work in 75/2=37 1/2 days.
Workspace
NA
SHSTTON
36
Solv. Corr.
49
Solv. In. Corr.
85
Attempted
1 M:26 S
Avg. Time
28 / 100
Choose the correct option.
A, B and C together can complete a piece of work in 10 days. All the three started working at it together and after 4 days A left. Then B and C together completed the work in 10 more days. A alone could complete the work in :
1 day's work done by man = 1/5
1 day's work done by man and his son = 1/3
=> His son 1 day's work = (1/3-1/5) = (5/15-3/15) = 2/15
so his son can do it alone = 15/2 days = 7 1/2 days
Workspace
NA
SHSTTON
57
Solv. Corr.
61
Solv. In. Corr.
118
Attempted
3 M:4 S
Avg. Time
30 / 100
Choose the correct option.
A and B can finish a piece of work in 20 days .B and C in 30 days and C and A in 40 days. In how many days will A alone finish the job
Find one day work for all three
(A+B)'s 1 day work = 1/20 ----(1)
(B+C)'s 1 day work = 1/30 ----(2)
and (C+A)'s 1 day work = 1/40 ----(3)
2(A+B+C) 1 day work = (1/20 + 1/30 + 1/40)
=> (A+B+C) = (6+4+3)/2*120
=> (A+B+C) = 13/240 -----------(4)
By eq. (2) and (4)
A + 1/30 = 13/240
=> A = 13/240 - 1/30 = (13-8)/240 = 1/48
then A's 1 day work = 1/48
so A alon can finish the job = 48 days
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