The current of a stream runs at the rate of 4 kmph. A boat goes 6 km and back to the starting point in 2 hours, then find the speed of the boat in still water?
Let's assume speed of the man in still water = x kmph.
and speed of stream = y kmph.
As per the question
x + y = 18 --- (1)
and x - y = 10 --- (2)
By solving (1) & (2)
2x = 28 => x = 14, y = 4.
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22
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21
Solv. In. Corr.
43
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The speed at which a man can row a boat in still water is 15 kmph. If he rows downstream, where the speed of current is 3 kmph, what time will he take to cover 60 metres?
Given Boat speed in still water = 15 kmph.
Speed of current = 3 kmph.
So Speed of the boat in downstream = 15 + 3 = 18 kmph = 18 * 5/18 = 5 m/s
So time Required to cover 60 meters = 60/5 = 12 seconds.
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NA
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21
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21
Solv. In. Corr.
42
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A boat sails 15 km of a river towards upstream in 5 hours. How long will it take to cover the same distance downstream, if the speed of current is one-fourth the speed of the boat in still water:
Let's assume Boat speed in still water = x kmph
and current speed = y kmph.
so boat Upstream speed = (x-y) kmph
Boat Downstream speed = (x+y) kmph
as per the question
(x - y) = 15/5 = 3 km/h ---------------(1)
Given x= 4y (speed of current is 1/4 of boat speed in still water)
so form eq. (1 )
4y-y = 3 => y = 1 kmph so x= 4 km/h
So boat downstream speed (x+y) = 5km/h
=> Time required in downstream = 15/5 = 3h
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NA
SHSTTON
22
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14
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36
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The time taken by a man to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 42 kmph, find the speed of the stream?
Given ratio of times taken by man for upstream and Downstream = 2:1
Ratio of the speed of the boat in still water to the speed of the stream = (2+1)/(2-1) = 3/1 = 3:1
So Speed of the stream = 42/3 = 14 kmph.
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NA
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3
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31
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34
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A boat covers a certain distance downstream in 1 hour, while it comes back in 1 hours. If the speed of the stream be 3 kmph, what is the speed of the boat in still water?
Let the speed of the boat in still water be x kmph. Then,
Speed downstream = (x + 3) kmph, Speed upstream = (x - 3)kmph.
? (x + 3) * 1 = (x -3) * 3/2 ? 2x + 6 = 3x - 9 ? x = 15 kmph.
Workspace
NA
SHSTTON
14
Solv. Corr.
14
Solv. In. Corr.
28
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A man rows to a place 48 km distance and back in 14 hours. He finds that he can row 4 km with the stream in the same time as 3 km against the stream. The rate of the stream is:
Suppose he moves 4 km downstream in x hours. Then,
Speed downstream = [4/x] km/hr, Speed upstream = [3/x] km/hr.
? 48/(4+x) + 48/(3/x) = 14 or x = 1/2.
So, Speed downstream = 8 km/hr, Speed upstream = 6 km/hr.
Rate of the stream = 1/2 (8-6) km/hr = 1 km/hr.
Workspace
NA
SHSTTON
13
Solv. Corr.
17
Solv. In. Corr.
30
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A boat takes 19 hours for travelling downstream fro poin A to point B and coming back to a point C midway between A and B. If the velocity of the stream is 4 kmph and the speed of the boat in still water is 14 kmph, what is the distance between A and B?
Speed downstream = (14 + 4) km/hr = 18 km/hr;
Speed upstream = (14 - 4) km/hr = 10 km/hr.
Let the distance between A and B be x km. Then,
x/18 + (x/2)/10 = 19 ? x/18 + x/20 = 19 ? x = 180 km.
Workspace
NA
SHSTTON
12
Solv. Corr.
14
Solv. In. Corr.
26
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A boat running upstream takes 8 hours 48 minutes to cover a certain distance, while it take 4 hours to cover the same distance running downstream. What is the ratio between the speed of the boat and speed of the water current respectively?
Let the man rate upstream be x kmph and that downstream be y kmph. Then,
Distance covered upstream in 8 hrs 48 min. = Distance covered downstream in 4 hrs.
? [x 8 4/5] = (y * 4) ? 44/5 x = 4y ? y = 11/5 x.
? Required ratio = [y + x / 2] : [6x / 5 * 1/2] : [6x / 5 * 1/2]
= 8/5 : 3/5 = 8:3.
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