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Boats and Streams Questions

Home > Quantitative Aptitude > Boats and Streams > General Questions
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Choose the correct option.

A man rows downstream 32 km and 14 km upstream. If he takes 6 hours to cover each distance, then the velocity (in kmph) of the current is:


A1.5 kmph

B1.75 kmph

C2 kmph

D3 kmph

ENone of these

Answer: Option A

Explanation:

Rate downstream = [32/6] kmph; Rate upstream = [14/6] kmph.
? Velocity of current = 1/2[32/6 - 14/6] kmph = 3/2 kmph = 1.5 kmph.

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Speed of a boat in standing water is 9 kmph and the speed of the stream is 1.5 kmph. A man rows to place at a distance of 105 km and comes back to the starting point. The total time taken by him is:


A12 hours

B24 hours

C36 hours

D48 hours

Answer: Option B

Explanation:

Speed upstream = 7.5 kmph; Speed downstream = 10.5 kmph.
? total time taken = [105/7.5 + 105/10.5] hours = 24 hours.

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A man can row 7 kmph in still water. If in a river running at 1.5 km an hour, it takes him 50 minutes to row to a place and back, how far off is the place?


A3 km

B4 km

C5 km

D6 km

Answer: Option A

Explanation:

Speed downstream = (7.5 + 1.5) kmph = 9 kmph;
Speed upstream = (7.5 - 1.5) kmph = 6 kmph.
Let the required distance be x km. Then,
x/9 + x/6 = 50/60 ? 2x + 3x = [5/6 * 18] ? 5x = 15 ? x =3.
Hence, the required distance is 3 km.

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A man can row 30 km downstream and 20 km upstream in 4 hours. He can row 45 km downstream and 40 km upstream in 7 hours. Find the speed of man in still water?


A15 kmph

B10 kmph

C12 kmph

D12.5 kmph

ENone of these

Answer: Option D

Explanation:

Let's assume speed of the man in still water = x kmph
and the speed of the stream = y kmph.
As per the question Downstream + upstream
30/(x + y) + 20/(x - y) = 4 ------ (1)
45/(x + y) + 40/(x - y) = 7 ----- (2)
By Solving above equation the speed of man in still water = 12.5 kmph.

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A boat goes 100 km downstream in 10 hours, and 75 km upstream in 15 hours. The speed of the stream is?


A7 km/h

B5 km/h

C3 km/h

D2 (1/2) km/h

Answer: Option D

Explanation:

Boat downstream speed = 100/10 kmph = 10 kmph

Boat upstream speed = 75/15 kmph = 5 kmph
So speed of stream = (10 - 5)/2 kmph => 2 1/2 kmph

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A man takes twice as long to row a distance against the stream as to row the same distance in favour of the stream. The ratio of the speed of the boat(in still water) and the stream is:


A1:2

B1:3

C2:1

D3:1

Answer: Option D

Explanation:

Let man's rate upstream be x kmph. Then, his rate downstream = 2x kmph.
? (Speed in still water) : (Speed of stream)
= [2x + x / 2] : [2x - x / 2]
3x / 2 : x / 2 = 3:1.

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A man can row 6 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and black. How far is the place?


A3.12 km

B2.88 km

C3 km

D2 km

Answer: Option B

Explanation:

river speed = 6 kmph
man can row in still water by speed = 1.2 kmph
man can row in downstream by speed = (6 + 1.2) kmph = 7.2 kmph
man can row in upstream by speed = (6 - 1.2) kmph = 4.8 kmph
Let's assume place distance form starting point = x km
So time taked for up and down = x/7.2 + x/4.8 = 1
=> x = 2.88 km

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A man can row 50 km upstream and 72 km downstream in 9 hours. He can also row 70 km upstream and 90 km downstream in 12 hours. Find the rate of current.


A14 km/hr.

B4 km/hr.

C4 3/4 km/hr.

D4 1/2 km/hr.

Answer: Option B

Explanation:

Let x and y be the upstream and downstream speed respectively.
Hence 50/x + 72/y = 9 and 70/x + 90/y = 12
Solving for x and y we get x = 10 km/hr and y = 18 km/hr
Speed of the stream = 1/2 * (downstream speed - upstream speed)
= 1/2 (18 - 10) = 4 km/hr.

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A man can row a distance of 5 km in 60 min with the help of the tide. The direction of the tide reverses with the same speed. Now he travels a further 20 km in 10 hours. How much time he would have saved if the direction of tide has not changed?


A5 hrs

B6 hrs

C12 hrs

DNone of these

Answer: Option B

Explanation:

man row 5 km in 60 min (1hr)
=> 5=(u+v)*1 ---------(1)
Further 20 km in 10 hrs.
=> 20=(u-v)*10 -------(2)
By solving eq. (1) & (2)
u=7/2
v=3/2
Therfore,
=> 20=(u+v)*t
=> 20=(3/2 + 7/2)*t => t=4hr
Hence, time saved = 6 hr.

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A boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes. How long will it take to go 5 km in stationary water?


A40 minutes

B1 hour.

C1 hr 30 min.

D1 hr 15 min D.

Answer: Option D

Explanation:

upstream speed = 2km/h
downstream speed = 6km/h
speed in still water = 1/2(6+2) = 4km/h
so to cover 5 km 75 minutes or 1h15m requires.

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