A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5?
Milk in 1 litre mixture in 1st can = 3/4 litre.
Milk in 1 litre mixture in 2n d can = 1/2 litre.
Milk in 1 litre final mixture = 5/8 litre.
By rule of alligation we have required ratio 5 : 8
3/4 1/2
\ /
(5/8)
/ \
1/8 : 1/8
Therefore ratio of two mixtures =1/8:1/8=1:1
So, quantity of mixture taken from each can =(1/2)*12= 6 litres
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How many litres of water should be added to a 30 litre mixture of milk and water containing milk and water in the ratio of 7 : 3 such that the resultant mixture has 40% water in it?
30 litres of the mixture has milk and water in the ratio 7 : 3. i.e. the solution has 21 litres of milk
and 9 litres of water.
When you add more water, the amount of milk in the mixture remains constant at 21 litres. In the
first case, before addition of further water, 21 litres of milk accounts for 70% by volume. After
water is added, the new mixture contains 60% milk and 40% water.
Therefore, the 21 litres of milk accounts for 60% by volume.
Hence, 100% volume =21/0.6 = 35 litres.
We started with 30 litres and ended up with 35 litres.
So, 5 litres of water was added.
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A merchant mixes three varieties of rice costing Rs.20/kg, Rs.24/kg and Rs.30/kg and sells the mixture at a profit of 20% at Rs.30 / kg. How many kgs of the second variety will be in the mixture if 2 kgs of the third variety is there in the mixture?
lets assume x kg be rice A,
y kg be rice B
and 2 kgs is rice C
Given final CP = 25
So, 20x+24y+60=25(x+y+2) ------(1)
By Solving above eq. y=10-5x
Since , y cannot be zero or negative
Hence, x can only be 1 giving y = 5kg
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There are two bottles A and B, each filled with milk and water in the ratio 5:3 and 1:2 respectively. A new mixture is formed by mixing the contents of A and B in the ratio 4:3.What is the ratio of composition of milk and water in the new mixture?
Bottle A mixture: milk = 5/8 & water=3/8
Bottle B mixture: milk = 1/3 & water=2/3
Given New mixture (Bottle A & B) ratio = 4:3
Now milk ratio = (5/8*4/7) + (1/3*3/7) = 1/2
and water = (3/8*4/7) + (2/3*3/7) = 1/2
So, New mixture ration milk : water = 1 : 1
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A merchant has 1000 kg of sugar, part of which he sells at 8% profit and the rest at 18% profit. He gains 14% on the whole. The quantity sold at 18% profit is:
Profit on 1st part Profit on 2nd part:
8% 18%
\ /
Mean Profi 14%
/ \
4 6
Ratio of 1st and 2nd parts = 4 : 6 = 2 : 3
Quantity of 2nd kind = (3/5 ) * 1000 kg = 600 kg
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A coffee seller has two types of coffee Brand A costing 5 bits per pound and Brand B costing 3 bits per pound. He mixes two brands to get a 40 pound mixture. he sold this at 6 bits per pound. the seller gets a profit of 33 1/2 percent. how much he has used Brand A in the mixture?
Let x and y quantities of A and B respectively are mixed.
=> x+y=40 --------- (1)
His total selling price = 40*6=240
His cost price 180 approx(as he makes 33.5 % profit)
5x+3y=180 ------------- (2)
On solving (1) and (2)
x=30 pounds.
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If a and b are mixed in 3:5 ration and b and c are mixed in 8:5 ration if the final mixture is 35 liters, find the amount of b?
5 coffee and 4 tea costs Rs.96, 5 badam milk and 6 coffee costs Rs. 32 and 7 tea and 6 badam milk costs Rs.37. What is the combined price of 1 tea, 1 coffee and 1 badam milk?
Acc. to the question:
5c+4t=96 ----- (i)
5b+6c=32 ----- (ii)
7t+6b=37 ----- (iii)
Adding (i), (ii) & (iii)
11c+11b+11t=165
b+c+t= 15Rs
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If a Strawberry and a Butterscotch together cost Rs. 18.00, a Vanilla and a Strawberry cost Rs. 9.00 and a Butterscotch cost Rs.9.00 more than a Vanilla or a Strawberry then which of the following can be the price of a Butterscotch?
Acc. to the question
S+B= 18 ---- (1)
V+S= 9 ---- (2)
B-S=9 ---- (3)
Adding (1) and (3) we get
2B= 27 so B= 13.5Rs
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Two beakers are on the table. The capacity of the first beaker is x liters and that of the second beaker is 2x liters. Two thirds of the first beaker and one fourth of the second beaker is filled with wine. The remaining space is filled with water. If the content in both the beakers are mixed in a large beaker of volume 3x liters, what is the proportion of wine in the beaker?
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