Capgemini Technical Questions in Written Test
111 / 483
Rs 5000 was divided among 5 men, 6 women and 5 boys, such that the ratio of the shares of men, women and boys is 5:3:2 what is the share of the boy?
ARs. 200
BRs. 100
CRs. 250
DRs. 150
Answer: Option A
Explanation:Given the that ratio is 5:3:2.
Now the share of all boys will be (2/10)*5000=1000
So share of each boy will be: 1000/5= Rs. 200
Submit Your Solution
112 / 483
if x-y+z=19,y+z=20,x-z=3
find the value of x+4y-5z.
A-14
B-13
C13
D14
Answer: Option B
Explanation:Given:
x-y+z=19 -----(1)
y+z=20-----(2)
x-z=3-------(3)
By solving eq (1) & (2)
x-y-2z=-17-------(4)
By solving eq. (2) & (4)
z=12.
put the value of z in eq (2)
y=8
Similarly x=15
Put the value of x, y and z
x+4y-5z=15+32-60=-13.
Submit Your Solution
113 / 483
Find min value of f(x) : |-5-x| + |2-x|+|6-x|+ |10-x|; where x is an integer
A19
B17
C23
D10
Answer: Option A
Explanation:Note: | a | = | ?a |
| ?5 ? x | = | ?(?5 ? x) | = | 5 + x | and
| 2 ? x | = | ?(2 ? x) | = | ?2 + x | = | x ? 2 |
=> | ?5 ? x | + | 2 ? x | + | 6 ? x | + | 10 ? x |
= | 5 + x | + | x ? 2 | + | 6 ? x | + | 10 ? x |
Also | a | + | b | ? | a + b | for all a and b
and | c | + | d | ? | c + d | for all c and d
and so:
| a | + | b | + | c | + | d | ? | a + b | + | c + d | ? | a + b + c + d |
| a | + | b | + | c | + | d | ? | a + b + c + d |
Therefore
| ?5 ? x | + | 2 ? x | + | 6 ? x | + | 10 ? x |
= | 5 + x | + | x ? 2 | + | 6 ? x | + | 10 ? x |
? | 5 + x + x ? 2 + 6 ? x + 10 ? x | = | 19 | = 19
Submit Your Solution
114 / 483
There are 2 different blue toys, 3 different green toys and 4 different red toys. In how many ways one can choose 3 toys, such that there is at least one green toy in the chosen three?
A33 ways.
B36 ways.
C64 ways.
D40 ways.
Answer: Option C
Explanation:Sample can be (1 green + 2 non-green) or (2 green + 1 non-green) or (3 green).
Number of ways = (3C1 * 6C2) + (3C2 * 6C1) + (3C3)= 45+18+1= 64 ways.
Submit Your Solution
115 / 483
In triangle PQR, PQ=6 cm,PR=8 cm and QR=12 cm. Calculate the area of the triangle PQR:
A17.5 cm^2
B23.33 cm^2
C28.67 cm^2
D21.33 cm^2
Answer: Option D
Explanation:s=6+8+12/2=26/2=13
area=sqrt(s(s-a)(s-b)(s-c)
sqrt(13(13-6)*(13-8)*(13-12))
sqrt(455)=21.33 cm^2
Submit Your Solution
116 / 483
The sides of the triangle are in the ratio 1/2:1/3:1/5 and Its perimeter is 155 cm, what is the difference between the largest sides?
A45 cm
B60 cm
C100 cm
D90 cm
Answer: Option A
Explanation:Given Trinagle sides ratio = 1/2:1/3:1/5 = 15:10:6
and its perimeter = 155 cm.
So its sids
15/31*155=75 cm.
10/31*155=25 cm.
6/31*155=30 cm.
So, difference between largst side = (75-30) = 45 cm.
Submit Your Solution
117 / 483
A is 30% more efficient than B. How much time will they, working together, take to complete a job which A alone could have done in 23 days?
A13 days
B15 days
C23 1/12 days
DNone of these
Answer: Option A
Explanation:Ratio of times taken by A and B = 100 : 130 = 10 : 13.
Suppose B takes x days to do the work.
Then, 10 : 13 :: 23 : x
=> x = (23 * 13)/10
=> x = 299/10
A's 1 day's work = 1/23
B's 1 day's work = 10/299
(A + B)'s 1 day's work = (1/23 + 10/299) = 23/299 = 1/13 .
So, A and B together can complete the work = 13 days.
Submit Your Solution
118 / 483
The sum of the ages of A,B and C was 52 three years ago.Four years ago B,who is a year younger than C,was 1 1/2 times as old as A.The sum of the ages of B and C two years hence,will be
A50 years
B45 years
C49 years
DNone of these
Answer: Option C
Explanation:Present sum of ages of A,B & C = A+B+C = 52+9=61 ---(i)
Given B is a year younger than C, so B+1 = C ---(ii)
Also B-4=(A-4)*3/2
=> 2B - 8 = 3A-12
=> 2B -3A= -4 ---(iii)
Substituting C=B+1 from (ii) in (i)
A+2B=60 ---(iv)
On solving (iii) & (iv)
A=16, B=22 so C=23
So sum of the ages of B & C two year hence= (B+2)+(C+2)=24+25 = 49 Years.
Submit Your Solution
119 / 483
How many rotations per minute must a wheel of diameter 1.5m make to achieve a speed of 45 kmph?
A155
B159
C125
DNone of these
Answer: Option B
Explanation:For 45kmph, distance to cover in one hour = 45 * 1000 = 45000 m.
Distance to be covered per minute (d) = 45000 / 60 = 750 m/min
Distance covered in 1 rotation of wheel =Pi*diameter=Pi*1.5 m.
So rotation /minute Required =750/(Pi*1.5)=750/[(22/7)*1.5]=159.09 ~ 159
Submit Your Solution
120 / 483
A circular cylinder of internal diameter 8 cm and height 10 cm contain water to a depth of 6 cm.Two solid lead sphere each of diameter 4 cm are placed in it. Find height by which water level rises.
A2 cm
B10 cm
C1 cm
D1 1/3
Answer: Option D
Explanation:Volume of cylinder = (pi*r^2*h)
column of sphere = ( (4*pi*r^3)/3)
r(sphere) = 2,
so volume of 2 sphere = 64pi/3.
r(cylinder) = 4,
pi * 4^2 * h = 64*pi/3
so, h = 4/3 = 1 1/3
Submit Your Solution
Here is the list of questions asked in Capgemini Technical Questions in Written Test. Practice Capgemini Written Test Papers with Solutions and take Q4Interview Capgemini Online Test Questions to crack Capgemini written round test. Overall the level of the Capgemini Online Assessment Test is moderate. Only those candidates who clear the written exam will qualify for the next round, so practic all the questions here and take all the free tests before going for final selection process of Capgemini