Recent Placement Papers of Capgemini
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The first letters are in alphabetical order with a letter skipped in between each segment: C, E, G, I, K. The second and third letters are repeated; they are also in order with a skipped letter: M, O, Q, S, U.
A1
B2
C3
D4
E5
Answer: Option D
Explanation:In each step, the CW-end element moves to the ACW-end position.
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62 / 483
Select a figure from amongst the Answer Figures which will continue the same series as established by the five Problem Figures.
A1
B2
C3
D4
E5
Answer: Option A
Explanation:One, two, three, one, two, three.....arcs get inverted sequentially. This inversion takes place in an ACW direction.
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63 / 483
A sum was put at simple interest at certain rate for 3 years. Had it been put at 1% higher rate it would have fetched Rs. 63 more. The sum is:
ARs. 2400
BRs. 2100
CRs. 2200
DRs. 2480
Answer: Option B
Explanation:1 percent for 3 years= 63
1 percent for 1 year = 21
=> 100 percent = 2100
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64 / 483
For what value of "k" will the equation (2kx^2 + 5kx +2)=0 have equal roots?
A2/7
B9/4
C16/25
D7/1
Answer: Option C
Explanation:For a 2nd degree equation "ax2+bx-c=0" has equal roots the condition is b2-4ac =0
So in the given equation (2kx^2 + 5kx +2)
a=2k, b=5k, c=2
=> (5k)^2-4(2k)(2)=0
=> 25k^2-16k=0
=>k(25k-16)=0
=> k=16/25;
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65 / 483
A 5-digit number is formed by the digits 2,4,5,6,8 (each digit used exactly once) . What is the probability that the number formed is divisible by 4 ?
A1/5
B2
C3
D2/5
Answer: Option D
Explanation:A no. is divisible by 4 if last two digit is divisible by 4
so numbers ending with 24,28,48,52,56,64,68,84 are divisible by 4
last two places are fixed by 24,28,48,52,56,64,68,84
so remaining 3 places can be filled in 3! ways for each
total=8*3!=48=n(E)
n(S) = 5!
so
= n(E)/n(S)
=48/120=2/5
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66 / 483
A builder has to pour a concrete slab 12 centimeters thick to cover an area 10 meters long and 2 meters wide. How many cubic meters of concrete will the builder need?
A2
B2.4
C3
D4
Answer: Option B
Explanation:Thikness= 12cm. =0.12m.
area is 10m. long and 2m. wide;
So, total concrete needed is = the volume of the area = (0.12 * 10 * 2)= 2.4 cubic meter.
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67 / 483
A man reaches his office 30 min late, if he walks from his home at 3 km per hour and reaches 40 min early if he walks 4 km per hour. How far is his office from his house?
A3km
B14km
C5km
D7km
Answer: Option B
Explanation:Lets assume distance between office and his house =x km
Time taken when speed is 3 kmph = x/3 min.
Time taken when speed is 4 kmph = x/4 min.
Difference between time taken 40-(-30) = 70mins = 70/60 hours.
x/3- x/4 = 70/60
x/12= 7/6
x=14 km
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68 / 483
A sum of Rs 468.75 was lent out at simple interest and at the end of 1 year and 8 months, the total amount of Rs 500 is received. find the rate of interest.
A4%
B4.50%
C6%
D8%
Answer: Option A
Explanation:Given principle P=468.75, Rate of Intreset = R%
Total Amount received = Rs 500
=> Total Amount received = Simple Intrest + Principle.
=> 500 = [468.75*(20/12)*R]/100 + 468.75
=> 31.25=156.25*5R/100
=> R=4%
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69 / 483
In a certain college, 20% of the boys and 40% of the girls attended the annual college outing. If 35% of all the students are boys, what percent of all the employees went to the outing?
A33%
B35%
C25%
D33.33%
Answer: Option A
Explanation:Lets assume total students =100
so in that 35 students are boys and remaining 65 will be girl.
20% of boys = (35)*20/100 = 7
40% of girls = (65)*40/100 = 26
Totally (26+7)=33 employee went to outing.
So 33 is 33% in 100
=> 33% employees went for outing.
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70 / 483
Radha bought a watch for Rs. 144 and got a percentage of profit equal to the cost price of the watch. What is the cost price of the watch?
ARs. 72
BRs. 80
CRs. 78
DRs. 90
Answer: Option B
Explanation:SP=144
Lets assume cost price of watch= Rs. x
so profit %=x
C.P.= (100/(100+gain%))*S.P. -----(formula to get CP)
x=(100/100+x) *144
=> x^2+100x=14400
=> x^2+180x-80x-14400=0
=> (x+180) (x-80)=0
=> x=-180
=> x=80
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