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231.
What is the next number?
11, 23, 47, 83, 131, ....
Answer: Option D
Explanation:23â€“11 = 12
47â€“23 = 24
83â€“47 = 36
131â€“83 = 48
Therefore, 131+60=191
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232. A sum of Rs.3000 is distributed among A, B, and C. A gets 2/3 of what B and C got together and c gets 1/3 of what A and B got together, C's share is?
Answer: Option A
Explanation:As A+B+C=3000. And A=2/3(B+C).
Also C=1/3(A+B).
So, 3C=A+B.
Hence now we can substitute A+B by 3C.
So final equation will be 3C+C=3000.
Hence , 4C=3000 => C=750.
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233.
Answer: Option C
Explanation:Case 1: A, B are true. In this case, Statement C also correct. So contradiction.
Case 2: B, C are true. In this case, B leads to ghost house and C confirms it. Now A is wrong. So door A does not lead to freedom. So Door C leads to freedom.
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234. What is the probability of getting sum 3 or 4 when 2 dice are rolled
Answer: Option B
Explanation:Required number of ways of sum 3 or 4 = (2, 1), (1, 2), (1, 3), (3, 1), (2, 2) = 5
Total ways = 6^2 = 36
Probability = 5/36
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235. a bb ccc dddd eeeee .........What is the 120th letter?
Answer: Option D
Explanation:Number of letters in each term are 1, 2, 3, 4, 5,….
The above number are in series of A.P.
So n*(n+1)/2 ? 120
For n = 15 above eq. condition will be true.
15th term contains 15 O's.
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236. Find the number of perfect squares in the given series 2013, 2020, 2027,................, 2300 (Hint 44^2=1936)
Answer: Option A
Explanation:The given series is an AP with common difference of 7. So the terms in the above series are in the form of 2013 + 7k. We have to find the perfect squares in this format in the given series.
Given that 44^2 = 1936.
Shortcut: To find the next perfect square, add 45th odd number to 44^2.
So 45^2 = 1936 + (2 x 45 -1) = 2025
46^2 = 2025 + (2 x 46 - 1) = 2116
47^2 = 2116 + (2 x 47 - 1) = 2209
Now subtract 2013 from the above numbers and divide by 7. Only 2209 is in the format of 2013 + 7k. One number satisfies.
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237. What is in the 200th position of 1234 12344 123444 1234444....?
Answer: Option C
Explanation:Here is no explanation for this answer
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238.
What is the next number in the given series?
70, 54, 45, 41,.....
Answer: Option D
Explanation:Consecutive squares are subtracted from the numbers.
70 - 54 = 16
54 - 45 = 9
45 - 41 = 4
So next we have to subtract 1.
So answer = 41 - 1 = 40
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239.
The sticks of the same length are used to form a triangle as shown below. If 87 such sticks are used then how many triangles can be formed?
Answer: Option B
Explanation:First triangle is formed by using 3 sticks, but any subsequent triangle may be formed by using 2 sticks.Â
Therefore, If 1st triangles uses 3 sticks,
Remaining sticks = 87 - 3 = 84.Â With these 84, we can form 42 triangles. So total = 42 + 1 = 43
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240. The numbers 272738 and 232342, when divided by n, a two digit number, leave a remainder of 13 and 17 respectively. Find the sum of the digits of n?
Answer: Option A
Explanation:From the given information, (272738 - 13, 232342 - 17) are exactly divisible by that two digit number.
We have to find the HCF of the given numbers 272725, 232325.
HCF = 25.
So sum of the digits = 7.
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