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131 / 362
A candidate scores an aggregate of 60% marks, scoring an average of 56% in 4 of the papers and 68% in the others. How many papers were there totally?
A6
B7
C10
D9
ENone of these
Answer: Option A
Explanation:Lets assume no. of subject scoring avg. 68% = y
so, (56*4 + 6x * y)/(4+y) = 60
=> y=2
Therefore total subject = (2+4) = 6
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132 / 362
In an examination, A got 10% marks less than B, B got 25% marks more than C and C got 20% less than D. If A got 360 marks out of 500. The percentage of marks obtained by D was :
A70%
B75%
C80%
D85%
Answer: Option C
Explanation:A got 360/500 * 100 = 72%
(as per question)it is 90% of B.
So B = 72 * 100 / 90 = 80%.
Which was 125% of C.
So C = 80 * 100 / 125 = 64%.
Which was 80% of D.
So D = 64 * 100 / 80 = 80%.
=> D got 80% marks.
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133 / 362
A man drives 150 km from to in 3 hours and 20 minutes and returns to the place in 4 hours and 10 minutes. If is the average speed of the entire trip, then the average speed of the trip from to, exceeds by:
A5.0 km/hour
B4.5 km/hour
C4.0 km/hour
D2.5 km/hour
Answer: Option B
Explanation:Let's assume Man drives From point A to B i.e 150 km.
Man drive (from point A to B) in 3 hours 20 minutes (i.e 3 + 1/3 = 10/3 hours) then Speed is 150/(10/3) = 45km/hr.
Return, Man drives (from point B to A) (same 150 km) in 4 hours 10 minutes (i.e 4+1/6 = 25/6 hr) then speed = 150/(25/6) = 36km/hr.
So, Average Speed (45+36)/2 = 40.5 km/hr.
So, Average speed exceeds Speed from to by (i.e from A to B by) = (45 - 40.5) = 4.5km/hr.
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134 / 362
5% of (25% of Rs1600) is
ARs. 5
BRs 17.50
CRs 20
DRs 25
Answer: Option C
Explanation:25% of 1600 = (25*1600)/100=400
5% of 400 = (5*400)/100 = Rs.20
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135 / 362
Sudhir goes to the market once every 64 days and Sushil goes to the same market once every 72 days. They met each other one day. How many days later will they meet each other again?
A567
B576
C765
DNone of these
Answer: Option B
Explanation:Find the LCM of 64,72
i.e 2*2*2*8*9=576
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136 / 362
A is 6 times as fast as B and takes 100 days less to complete a work than B. find the total no of days taken by A and B to complete the work.
A17/7 days
B120/7 days
C121/7 days
DNone of these
Answer: Option B
Explanation:Given, A is 6 times as fast as B
So, Ratio of time taken by A and B will be 1:6
Lets assume time taken by A = x.
and time taken by B = 6x.
According to the question, A take 100 days less.
=> 6x-x=100 .
=> x=20.
So, A takes 20 days and B takes 120 days to complete the work.
A's 1 day work = 1/20.
B's 1 day work = 1/120.
(A+B)'s 1 day work = 1/20 + 1/120 = 7/120.
Therefor, total time taken by A & B = 120/7 days.
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137 / 362
The speed of a car increases by 2 kms after every one hour. If the distance travelling in the first one hour was 35 kms. what was the total distance travelled in 12 hours?
A456 kms
B482 kms
C552 kms
D556 kms
Answer: Option C
Explanation:Given, Speed of car increases by 2kms after every one hrs.
=> speed of the car is in AP.
First find the no. of term in the series of speeds.
=> a+(n-1)d= 57
=> 35 + (n-1)*2=57.
=> 33 + 2n = 57.
=> n= 24/2 = 12.
Total distance traveled = (n/2)[2a +(n -1)d].
=> (12/2)[2 * 35 + 11 * 2]
=> 6*[70+22]= 92 * 6 = 552 kms.
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138 / 362
Of the three numbers, second is twice the first and is also thrice the third. If the average of the three numbers is 44, the largest number is :
A24
B36
C72
D108
Answer: Option C
Explanation:Lets assume numbers as x, y, and z.
Given, 2nd is twice the 1st and three times the 3rd (i.e so y is the largest).
x = (1/2)*y
z = (1/3)*y
Average = y[1/2 + 1 + 1/3]/3
=> (11/18)y = 44. => y = 18*44/11 = 72.
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139 / 362
A producer of tea blends two varieties of tea from two tea gardens one costing Rs 18 per kg and another Rs 20 per kg in the ratio 5 : 3. If he sells the blended variety at Rs 21 per kg, then his gain percent is
A10%
B12%
C14%
D22%
Answer: Option B
Explanation:As per the question,
=> (20-x)/(x-18)=5/3.
=> 60-3x=5x - 90.
=> 8x=150.
=> x=75/4
Now, sell price is 21 and the cost price is 75/4
So, the required profit% is [ (21 - 75/4) / 75/4 ]* 100 = (9/4) * (4/75) * 100 = 900/75 = 60/5 = 12%.
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140 / 362
A garrison of 3300 men has provisions for 32 days, when given at a rate of 850 grams per head. At the end of 7 days a reinforcement arrives and it was found that now the provisions will last 8 days less, when given at the rate of 825 grams per head.How, many more men can it feed?
A1000
B1650
C1700
D1690
Answer: Option C
Explanation:Initial stock = 3300*32*850
stock consumed in 7 days = 3300*7*850
stock remains = 3300*25*850
a/q
3300*25*850 = (3300+reinforcement) *825*(32-7-8)
gives reinforcement = 1700
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