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Hexaware Technologies Aptitude Questions and Answers for Freshers

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Total Qs: 60+

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136
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Solv. In. Corr.
321
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There are three numbers, these are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. What will be the sum of three numbers :


A80

B82

C85

D87

Answer: Option C

Explanation:

Given that numbers are co primes,
and two products have the middle number in common.

=> Middle number = H.C.F. of 551 and 1073 = 29

so first number is = 551/29 = 19
=> Third number = 1073/29 = 37

Therefore, sum of these numbers is = (19 + 29 + 37) = 85

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SHSTTON
3
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8
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11
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If 11 oranges bought for 10 rs and 10 oranges sold for 11 rs. What is the profit?


A2.10%

B1.20%

C12%

D21%

Answer: Option D

Explanation:

C.P. of one orange=10/11
S.P. of one orange=11/10
Profit=(sp-cp)/cp*100=21%.

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SHSTTON
1
Solv. Corr.
9
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10
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| x | + x^3 =0. Solve x


A0

B-1

CBoth A and B

DNone of these

Answer: Option B

Explanation:

let x=-1
|X|=1
x^3=(-1)^3=-1
|x|+x^3=1-1=0
so X=-1
and also x= 0 because here didn't mention any condition

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SHSTTON
7
Solv. Corr.
6
Solv. In. Corr.
13
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The total population of a village is 5000. The number of males and females increases by 10% and 15% respectively and consequently the population of the village becomes 5600. what was the number of males in the village ?


A2000

B2500

C3000

D4000

Answer: Option C

Explanation:

suppose number of males =m
and number of females =f
so m+f=5000-----(1)
after increase males by 10%, m1=110m/100
and female by 15%, f1=115f/100
and m1+f1=5600
so putting values of m1 and f1
equation become 110m+115f=560000-----(2)
after solving both equations we get f=2000 and m=3000
so no of males =3000 answer is (c)

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NA
SHSTTON
3
Solv. Corr.
9
Solv. In. Corr.
12
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The average of 5 consecutive numbers is n. If the next two numbers are also included, the average will:


Aincreases by 1

Bremain the same

Cincrease by 1.4

Dincrease by 2

Answer: Option A

Explanation:

let x is first no then x,x+1,x+2,x+3,x+4 are consecutive nos
avg of this 5 nos is (x+x+1+x+2+x+3+x+4)/5=n
x+2=n ;n=x+2
add next 2 nos new avg is (x+x+1+x+2+x+3+x+4+x+5+x+6)/7=m
x+3=m ;m=x+3
new avg-old avg=x+3-x-2=1
increased by 1

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SHSTTON
6
Solv. Corr.
4
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10
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The mean of 100 abservations was calculated was 40. It was found later on that one of the observations was misread as 83 instead of 53. The correct mean is :


A39

B39.7

C40.3

D42.7

Answer: Option B

Explanation:

(x1+..........+83+........+x100)/100=40
=> x1+...........+83+........+x100=4000
=>x1+...............+x100=4000-83 -(1)

(x1...........+53+.........+x99+x100)/100=y
=> x1+...........+53+...........+x100=100y
=> x1+..............+x100=100y-53 -(2)
from (1)(2),we get
4000-83=y*100-53
100y=3970
y=39.70

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SHSTTON
0
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Find the angle between the hour and the minute hand of a clock when the time is 3.25.


Answer: Option A

Explanation:

formula::angle=11/2m-30h
11/2 * 25-30*3
=95/2
=47.5
ans:: AIs

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NA
SHSTTON
3
Solv. Corr.
5
Solv. In. Corr.
8
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A, B ans C are three speakers. They have to speak randomly along with another 5 speakers in a function. A has to speak before B and B has to speak before C. What is the probability?


A1/4

B1/6

C1/8

D1/10

Answer: Option B

Explanation:

Without considering other speakers , their arrangement should be ABC
whereas 6 arrangements are possible among these 3 persons.

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NA
SHSTTON
0
Solv. Corr.
8
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8
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There is a circle of radius 5. What is the area of the biggest rectangle that can be cut out of this circle?


A30

B35

C50

D60

Answer: Option C

Explanation:

Biggest rectangle would be a square,whose diagonal is 10(5+5)
if side of square is a, 100=a^2+a^2=2a^2
so area of square=a^2=100/2=50

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NA
SHSTTON
3
Solv. Corr.
3
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6
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Two mixers and one T.V. cost Rs. 7000, while two T.V.s and a mixer cost Rs. 9800. The value of one T.V. is ?


ARs. 2800

BRs. 2100

CRs.4200

DRs. 8400

Answer: Option C

Explanation:

Let x=mixer, and y=tv;
So, 2x+y=7000 and x+2y=9800;
solving for x& y
x=1400 - Mixer
y=4200 - T.V

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