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181 / 438
If 200 chocolates were distributed among 100 people, in such a manner that each man received 1 chocolate, each woman received 4 chocolates and each child received 6 chocolates. Find which of the following is a possible value for the number of children?
A12
B16
C8
D0
Answer: Option C
Explanation:Here is no explanation for this answer
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182 / 438
An exhibition was conducted for 4 weeks. The number of tickets sold in 2nd workweek was increased by 20% and increased by 16% in the 3rd workweek but decreased by 20% in the 4th workweek. Find the number of tickets sold in the beginning, if 1392 tickets were sold in the last week.
A1750
B1550
C1250
D1000
Answer: Option C
Explanation:Here is no explanation for this answer
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183 / 438
The cost of two varieties of paint is Rs.3969 per 2 kg and Rs.1369 per 2 kg respectively. After how many years, the value of both paint will be the same, if variety 1 appreciates at 26% per annum and variety 2 depreciates at 26% per annum?
A3
B4
C1
D2
Answer: Option D
Explanation:Simply appreciates variety 1 by 26% and depreciates variety 2 by 26% as:
3969(1-(1/26))^n=1369(1+)1/26))^n
For n = 2 we get both values equal.
Variety 2 Variety1
3969.00 1369 Initially
2937.06 1724.94 after I year
2173.42 2173.42 after II year
So the price become same after 2 years.
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184 / 438
If \(3\sqrt{5} + \sqrt{125}\) = 17.88, then what will be the value of \(\sqrt{80} + 6\sqrt{5}\) ?
A13.41
B20.46
C21.66
D22.35
Answer: Option D
Explanation:\(3\sqrt{5} + \sqrt{125} = 17.88\)
\(\Rightarrow 3\sqrt{5} + \sqrt{25 \times 5} = 17.88\)
\(\Rightarrow 3\sqrt{5} + 5\sqrt{5} = 17.88\)
\(\Rightarrow 8\sqrt{5} = 17.88\)
\(\Rightarrow \sqrt{5} = 2.235\)
\(\sqrt{80} + 6\sqrt{5} = \sqrt{16 \times 5} + 6\sqrt5\)
= \(4\sqrt5 + 6\sqrt5\)
= \(10\sqrt{5} = (10 \times 2.235) = 22.35\)
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185 / 438
If pq=28 where p and q are whole numbers then which of the following will be (p2 - q2)?
A32
B83
C783
Dcannot be determined.
Answer: Option C
Explanation:Here is no explanation for this answer
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186 / 438
A manufacturing company has 15% cobalt ,25% led and 60% of copper. If 5kg of led is used in a mixture, how much copper we need to use:
A12 kg
B14 kg
C10 kg
D9 kg
Answer: Option A
Explanation:25%=5kg
100%=20kg
60% of 20 kg= 12 kg
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187 / 438
A man bought some mangoes at Rs. 12 per dozen and bought the same number of at Rs 10 per kg. He sold these mangoes at Rs 13 per dozen and gained Rs 160.The total number of mangos bought by him:
A60 dozens
B70 dozens
C80 dozens
D90 dozens
Answer: Option C
Explanation:Lets assume total no of mangoes = 2x..
Then we profit=sp-cp
160=13*2x-(12x+10x)
160=4x
x=40
hence 2x=80 dozens
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188 / 438
In a bus left side are 15 seats available, 3 few seats in right side because in rear exit door. Each seat hold 3 people.In addition, there is a seat back can sit 7 people all together. How many people can sit in a bus?
A52
B49
C95
D88
Answer: Option D
Explanation:Right Side =15 seat
Left Side =15-3 (3 few seat in right side)= 12 seat
Total= 15+12= 27
People can seat in 27 seat= 27*3=81
People can seat in Last Seat = 7
Total People can seat= 81+7=88
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189 / 438
Three numbers A,B,Care in ratio 1:2:3. Their average is 600. If A is increased by 10% and B is increased by 20%, then to get the average increased by 5%, C will increased by:
A90
B100
C150
D180
Answer: Option D
Explanation:Let be A= x, B=2x, and C=3x.
(x+2x+3x)/3=600
this will be x=300
so, the numbers will be 300,600,900
new average= 105%of 600= 630
Let 110% of 300+80% of 600 + y= 630*3
solve it for y, you will get, y=1080
so, increase in C= 1080-900 =180
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190 / 438
A and B together can complete a work in 12 days. A alone can complete it in 20 days. If B does the work only for half a day daily, then in how many days A and B together will complete the work?
A10 days
B11 days
C15 days
D20 days
Answer: Option C
Explanation:Here is no explanation for this answer
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