Arithmetic Aptitude :: Problems on Ages
7. Father is aged three times more than his son Mohit. After 8 years, he would be two and a half times of Mohit's age. After further 8 years, how many times would he be of Mohit's age?
Let's assume Monit's present age = X years.
So father's present age = (X + 3X) years = 4X years.
After 8 years.
(4X + 8) =5/2 * (X + 8)
=> 8X + 16 = 5X + 40
=> 3X = 24 so, X=8
Hence, required ratio = (4X + 16) / (X + 16) = 48/24 = 2