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Placement Questions & Answers :: Accenture

111. Study the flow chart give below and the questions that follow

Answer: 11

Explanation:

Here is no explanation for this answer

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112. Read these Directions
In the following programme you must grasp the significance of the individual steps in the flow chart
and correct an error which has been deliberately placed there
In the following problem no two boxes contain the same number

Answer: Instruction 4 Box 2 Box 3

Explanation:

Here is no explanation for this answer

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113. Study the flow chart give below and the questions that follow

Answer: 66

Explanation:

Here is no explanation for this answer

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114. Study the flow chart give below and the questions that follow

Answer: 15

Explanation:

Here is no explanation for this answer

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115. The object of the following flow-chart is to rearrange the numbers in boxes 1, 2 and 3 in such a fashion that, at the end:

Box 3 will always contain the largest number,
Box 1 will always contain the smallest number,

However, this flow-chart is INCORRECT. As it stands, it will not accomplish the desired purpose.

Which one instruction must be changed to correct the flow-chart?

Answer: Instruction 5 Box 3 Box 2

Explanation:

The two conditions in the flowchart are :
Instruction 1 : IS (1) < (2) ? YES --(1)
Instruction 5 : IS (3) < (2) ? NO --(2)
ANSWER
The error is in Instruction 5, because BOX 3 will always contain the largest number and so the output to Instruction 5 will always be NO and the loop will end only on a YES.

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116. Study the flow chart give below and the Answer the questions that follow.

What number is now in box 11?

Answer: 55

Explanation:

Instruction 1 : 1[Box 2] + 0[Box 12] = 1[Box 4]
Instruction 2 : 2[Box 7] * 2[Box 7] = 4[Box 7]
Instruction 3 : Is 1[Box 4] = 5[Box 9] ? NO
Instruction 4 : 1[Box 4 + 2[Box 1] = 3[Box 4]
Instruction 5 : 4[Box 7] - 1[Box 2] = 3[Box 7]
Instruction 2 : 3[Box 7] * 3[Box 7] = 9[Box 7]
Instruction 3 : Is 3[Box 4] = 5[Box 9] ? NO
Instruction 4 : 3[Box 4] + 2[Box 1] = 5[Box 4]
Instruction 5 : 9[Box 7] - 1[Box 2] = 8[Box 7]
Instruction 2 : 8[Box 7] * 8[Box 7] = 64[Box 7]
Instruction 3 : Is 1[Box 4] = 5[Box 9] ? YES
Instruction 6 : 4[Box 3] + 5[Box 9] = 9[Box 10]
Instruction 7 : 64[Box 7] - 9[Box 10] = 55[Box 11]
ANSWER BOX 11 = 55.

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117. Study the flow chart give below and the Answer the questions that follow.

What number is in box 12?

Answer: 19

Explanation:

Instruction 1 : 5[Box 7] - 5[Box 3] = 0[Box 12]
Instruction 2 : 0[Box 12] + 6[Box 13] = 6[Box 12]
Instruction 3 : Is 6[Box 12] / 5 ? NO
Instruction 4 : 13[Box No.] - 2[Box 4] = 11[Box No.]
Instruction 5 : IS 8[Box 2] < 11[Box No.] ? YES
Instruction 6 : 7[Box 9] - 1 = 6[Box 9]
Instruction 2 : 6[Box 12] + 4[Box 11] = 10[Box 12]
Instruction 3 : Is 10[Box 12] / 5 ? YES
Instruction 2 : 10[Box 12] + 4[Box 11] = 14[Box 12]
Instruction 3 : IS 14[Box 12] / 5 ? NO
Instruction 4 : 11[Box No.] - 2[Box 4] = 9[Box No.]
Instruction 5 : 8[Box 2] < 9[Box No.] ? YES
Instruction 6 : 6[Box 9] - 1 = 5[Box 9]
Instruction 2 : 14[Box 12] + 5[Box 9] = 9[Box 12]
Instruction 3 : IS 19[Box 12] / 5 ? NO
Instruction 4 : 9[Box No.] - 2[Box 4] = 7[Box No.]
Instruction 5 : 8[Box 2] < 7[Box No.] ? NO
ANSWER Box 12 = 19.

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118. Kanak owns a plot worth Rs. 10000, He sells it to Raman at 10% profit Raman sells the plot back to Kanak at a loss of 10%. In the whole transaction, Kanak gets :

Answer:

Explanation:

profit of 1100

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119. Find the probability if a two digit number multiplied by 3 but not 5

Answer:

Explanation:

Total two digit numbers are 90 i.e. from 10 to 99
numbers multiple of 3 are 12, 15, 18, ......., 99 so 12+(n-1)3=99, n=30
numbers multiple of 3 & 5 both are 15,30,45,60,75,90 total 6
So two digit numbers multiple of 3 but not of 5 are 30-6=24
Probability=24/90=4/15

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120. The difference between the compound and simple interest on a certain sum for 2 years at the rate of 8% per annum is Rs.80. What is the sum?

Answer:

Explanation:

Since we know that SI and CI are same for first year. Difference is due to the SI of 1st year is treated as PRINCIPLE of 2nd year in CI.
So 1st we calculate the amount which treated as P in CI
P = 100*SI/R*T = 100*80/8*1 = 1000
This amount is also the SI for 1 year.
So,
SI = 1000
T = 1 Year
R = 8%
P = 100*1000/8*1 = 12500

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