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Placement Questions & Answers :: Accenture

91. In a class there are 45 pupil, out of them 12 are in debate only and 22 in singing only. Then how many in both?

Answer: 11

Explanation:

Given, total pupil = 45
Debate + Singing = (12 + 22) = 34
The intersection for two (play both games) = (45 - 12 - 22) = 11

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92. The average number of visitors of a library in the first 4 days of a week was 58. The average for the 2nd, 3rd, 4th and 5th days was 60. If the number of visitors on the 1st and 5th days were in the ratio 7:8 then what is the number of visitors on the 5th day of the library?

Answer: 64

Explanation:

If number of visitors on 1st, 2nd, 3rd, 4th and 5th day are a, b, c, d and e respectively then
a + b + c + d = 58 * 4 = 232 - - - (i)
b + c + d + e = 60 * 4 = 240 - - - (ii)
Subtracting (i) from (ii)
e - a = 8 - - - (iii)
Given that e : a = 8 : 7
Let e = 8x and a = 7x.
Given, 8x - 7x = 8 => x = 8 - - - (iv)
So a = 56 and e = 64.

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93. If 2x+y = 11, 2y+z = 12 and z+2x = 8, find the value of 2x + 3y +4z.

Answer: 29

Explanation:

Without Finding x & y & z
2x+y = 11 -->(1) 2y+z = 12 -->(2) z+2x = 8 ---> (3)
(2)* 2=> 4y+2z=24-----(A)
(3)* 2=> 2z+4x=16-----(B)
(1)*-1=> -2x-y =-11-----(C)
Add (A),(B) and (C)
2x + 3y +4z=29

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94. In an examination involving quantitative aptitude and logical reasoning, 65% examinees cleared quantitative aptitude test while 70% cleared logical reasoning test. If 50% examinees passed both the tests, then how many failed in both tests?

Answer: 15%

Explanation:

p(AUB)=p(A)+p(B)-p(AnB)
=65+70-50 =85%(the persons who cleard all)
the persons who did not clear any=100-85=15%

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95. A father is three times as old as his son. After fifteen years the father will be twice as old as his son's age at that time. Hence
the father's present age is

Answer: 45 years.

Explanation:

Lets assume son's current age = x years
So, father's current age = 3x
After 15 years (condition)
2(x+15)=3x+15
Son's age = 15 years, and father's age = 45 years.

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96. Three jackals Paar, Marr and Taar together have 675 loaves of bread. Paar has got three times as much as Maar but 25 loaves more than Taar. How many does Taar have?

Answer: 275

Explanation:

Lets assume maar (M) = x,
So Paar (P) = 3x
as per the question
Taar (T) = (3x-25)

As per the condition
M+P+T = x + 3x + 3x-25 = 675
7x - 25 = 675 => x=100
=> Taar (T) = 275

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97. There are two boxes, one containing 32 black balls and other containing 31 red balls you are allowed to move the boxes at random so that when you choose the box at random and a ball at random from the chosen box, the probability of getting the black ball is maximized. This maximum probability is

Answer: 0.75

Explanation:

Here is no explanation for this answer

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98. A closed wooden box of thickness 0.5 cm and length 21 cm, width 11 cm, and height 6 cm, is painted on the inside. The cost of painting is Rs 70. What is the rate of painting in rupees per sq. cm?

Answer: 0.7

Explanation:

Here is no explanation for this answer

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99. A train overtakes 2 persons walking at 3 km/hr and 5 km/hr respectively in the same direction and completely passes them in 8 seconds and 10 seconds respectively. Find the speed of the train.

Answer: 13 Km/hr

Explanation:

Lets assume train speed = x km/hr.
Relative speed respect to 1 person and train= (x-3)
Relative speed respect to 2 person and train= (x-5)
Dist. = speed * time
8(x-3)= 10(x-5)
=> x=13Km/hr

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100. The cost of two varieties of paint is Rs.3969 per 2 kg and Rs.1369 per 2 kg respectively. After how many years, the value of both paint will be the same, if variety 1 appreciates at 26% per annum and variety 2 depreciates at 26% per annum?

Answer: 2

Explanation:

Simply appreciates variety 1 by 26% and depreciates variety 2 by 26% as:
3969(1-(1/26))^n=1369(1+)1/26))^n
For n = 2 we get both values equal.
Variety 2 Variety1
3969.00 1369 Initially
2937.06 1724.94 after I year
2173.42 2173.42 after II year
So the price become same after 2 years.

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