121. By selling toffees at 20 for a rupee, a man loses 4 %. To gain 20 for one rupee, he must sell
Answer: 16 toffees
Explanation:Here is no explanation for this answer
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Wipro
122. A horse and a cow were sold for Rs. 12000 each. The horse was sold at a loss of 20% and the cow at the gain of 20%. The entire transaction resulted in :
Answer: a. no loss or gain
Explanation:Sp of cow=12000. Sp of horse=12000. Cp of cow=100/120*12000=10000. Similarly for horse cp=15000. Total sp= 24000 and total cp= 25000 loss= 1000
Workspace
Wipro
123. A boy was asked to find the value of 7/12 of a sum of money. Instead of multiplying The sum by 7/12 he divided it by 7/12 and thus his answer exceeded the correct Answer By Rs.95. Find the correct answer.
Answer: 49
Explanation:Lets assume the sum = x
So as per the ques.
x*12/7 - x*7/12 = 95
x*(144-49) = 84*95
x = 84*95 / 95 = 84.
Therefore, correct answer = 84*7/12 = 49
Workspace
Wipro
124. The radius of a sphere is increased by 50%. The increase in surface area of the sphere is :
Answer: 125%
Explanation:Take here radius as 100.
So, surface area = 4*22/7*100*100. (Surface area of sphere = 4*pi*r^2)
As per condition:
After increase radius by 50% the new radius = 100+50% of 100=150,
So, new surface area = 4*22/7*150*150
Increase in surface area = ((4*22/7)*150*150 -(4*22/7)*100*100)/(4*22/7-100*100)=125%
Workspace
Wipro
125. On increasing the price of T.V. sets by 30%, their sale decreases by 20%. What is the effect on the revenue receipts of the shop ?
Answer: 4% increase
Explanation:Let, price = Rs.100, sale = 100
Then, sale value = Rs.(100*100)=Rs.10000
New sale value = Rs.(130*80)=Rs.10400
Increase % = 400/10000*100=4%
Workspace
Wipro
126. 2 men and 3 boys can do a piece of work in 10 days while 3 men and 2 boys can do the same work in 8 days. In how many days can 2 men and 1. boy do the work? .
Answer: 12.5 days
Explanation:If 1 day work of a man=m and a boy=b, then
2m + 3b =1/10 ----(i) and
3m + 2b =1/8 ----(ii)
On solving (i) and (ii), m=7/200, b=1/100
So 2 men and 1 boy's 1 day work= (2*7/200)+(1/100)=8/100=2/25
Hence they can complete the work in 25/2=12.5 days
Workspace
Wipro
127. A polygon has 44 diagonals. Number of sides=?
Answer: 11
Explanation:No. of diagonals=[n(n-3)]/2
n=no. of sides
=> 44=(n2-3n)/2
=> n2-3n-88=0
=> n2-11n+8n-88=0
=> n=11
Workspace
Wipro
128. A and B undertake to do a piece of work for Rs. 600. A alone can- do it in 6 days while B alone can do it in 8 days. With the help of C, they finish it in 3 days. Find the share of each.
Answer: Rs.75
Explanation:C's 1 day's work=1/3 - (1/6 + 1/8)
A:B:C = Ratio of their 1 day's work = 1/6 : 1/8 : 1/24= 4:3:1 (by taking LCM)
therefore,
A's Share = Rs.(600* 4/8) = Rs.300
B's Share = Rs.(600* 3/8) = Rs.225
C's Share = Rs.[600 - (300 + 225)] = Rs.75
Workspace
Wipro
129. The average of 5 consecutive numbers is n. If the next two numbers are also included, the average will :
Answer: Increases by 1
Explanation:let x is first no.
So, x,x+1,x+2,x+3,x+4 are consecutive no.
avg. of this 5 no.
=> (x+x+1+x+2+x+3+x+4)/5=n
x+2=n; n=x+2
As per the question:
Add next 2 no.
so new avg = (x+x+1+x+2+x+3+x+4+x+5+x+6)/7=m
x+3=m ;m=x+3
New avg-Old avg=x+3-x-2=1
Increased by 1
Workspace
Wipro
130. The average of four consecutive even numbers is 27. The largest of these numbers is :
Answer: 30
Explanation:(x+(x+2)+(x+4)+(x+6))/4=27
=>x=24
so consecutive even numbers are 24,26,28,30
i.e 30 is largest
Workspace
Wipro
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