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Placement Questions & Answers :: TCS Digital

11. Mr. X decides to travel from Delhi to Gurgaon at a uniform speed and decides to reach Gurgaon after T hr. After 30 km, there is some engine malfunction and the speed of the car becomes 4/5th of the original speed. So, he travels the rest of the distance at a constant speed 4/5th of the original speed and reaches Gurgaon 45 minutes late. Had the same thing happened after he travelled 48 km, he would have reached only 36 minutes late. What is the distance between Delhi and Gurgaon?

Answer:

Explanation:

Let the distance from Delhi to Gurgaon be 'd' km. The first 30 km he travels at his usual speed. However, the remaining'd-30' km he travels at a reduced speed.
To travel 'd' km he usually takes T hr. Therefore, to travel 'd - 30' km he should ideally take (d−30)xT/d hr. However, this is only if he travels at his usual speed. It is given that he travelled only at 4/5th of his usual speed. Because of this he would have taken 5/4th of the time to travel the remaining distance, i.e., he takes 1/4th of the time extra. This is given to be 45 minutes (or 3/4th hr)
1/4x(d−30)xT/d = 3/4 (1)
On the other hand, had the same thing happened after he travelled 48 km, he would have reached only 36 minutes or 34 hrs late. Hence,
1/4x(d−48)xT/d = 3/5 (2)
Dividing (1) by (2) and solving for d, we get d = 120 km.
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12. A pipe can fill a tank in 3 hrs .Due to a leakage in the tank it takes 3.5 hrs to fill the same tank. Then how many hours will the leakage can empty the tank.

Answer:

Explanation:

The electric pump can fill the tank in 3 hrs. Because of the leak it took 3.5 hrs.
Now, if there is no leak and the electric pump works for 3.5 hrs instead of 3 hrs, 0.5/3 = 1/6 of the tank must have been overflown. But we are unable to see the overflow because this 1/6 is emptied by the leak of course working for 3.5 hrs.
Hence the leak can empty 1/6 of the tank in 3.5 hours. So it can empty a full tank in 21 hrs.

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13. It is dark in my bedroom and I want to get two socks of the same colour from my drawer, which contains 26 red and 24 blue and 34 brown socks. How many socks do I have to take from the drawer to get at least two socks of the each colour?

Answer:

Explanation:

Maximum of (red, blue, brown) + 2nd maximum of (red, blue, brown) + 2
36 + 24 + 2 = 62.

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14. Find the maximum possible value of x-y+33 if x, y are any two single digit integers, not necessarily the same.

Answer:

Explanation:

x and y are 2 single digit integer to get the maximum value for equation
x-y+33
Since it is difference between x&y one number should be maximum and other should be minimum to get maximum value take x=9&y=1
9-1+33=41

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15. A family consists of father, mother, two sons and the youngest daughter. The age of first son and daughter are in the ratio 3:1. The mother is 3.5 times as old as the second son. The age of the second son is 2/3 of the age of the first son. The age of the youngest daughter is 5 years. What is the age of the mother?

Answer:

Explanation:

Let us take the ages of Father, Mother, First son, Second son and daughter as F, M, S1, S2 and D respectively.
Given,
S1: D = 3: 1 M = 3.5 (S2) S2 = 2/3 (S1) D = 5
Now, S1: D = 3: 1 => S1 = 3D => S1 = 3(5) => 15 So, S1 = 15
S2 = 2/3 (S1) => S2 = 2/3(15) => 10 S2 = 10
M = 3.5 (10) => 35
Mother's age is 35

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16. Rahul buys an article at Rs.15850 from the retailer who sells it at a profit of 15 %. The retailer bought it from a wholesaler who sold it at a profit of 20 %. The manufacture sold it at a profit of 30 % to the wholesaler. Find the cost price of manufacturing the article (approximately)?

Answer:

Explanation:

Going from options Option 8835
If manufacturing cost is 8835,
Manufacturer to Wholesaler = 30/100 * 8835 = 2650.5 Total = 8835 + 2650.5 = 11485.5
Wholesaler to Retailer = 20/100 * 11485.5 = 2297.1 Total = 11485.5 + 2297.1 = 13782.6
Retailer to Rahul = 15/100 * 13782.6 = 2067.34 Total = 13782.6 + 2067.34 ~ 15850
Hence option 8835 will be the answer.

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17. 66 people {a1, a2,..., a66} meet and shake hands in a circular fashion. In other words, there are totally 36 handshakes involving the pairs, {a1, a2}, {a2, a3}, ...,{a65, a66}, {a66, a1}. Then size of the smallest set of people such that the rest have shaken hands with at least one person in the set is

Answer:

Explanation:

For minimum people in a set we can consider handshakes as {a1, a2, a3}, {a4, a5, a6},
{a7, a8, a9},…….{ an-2,an-1,an}
For minimum people, we can consider the set {a2, a5, a8… an-1}.
So, MINIMUM people in a set = n / 3 so n/3=66/3=22

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18. There will be 20 3s in between 1 to 100
Similarly, 20 3s in between 200 to 300 but (100+20) in between 300 to 400 (because at unit place 19 3s and 10's place 1 and 100 3s at 100's place ) and 20 3s in between 400 to 500
20 3s in between 500 to 600
20 3s in between 600 to 700
20 3s in between 700 to 800
20 3s in between 800 to 900
20 3s in between 900 to 1000
So total number of 3s will be 180+19+1+100 = 300 This count is in decimal but in question base value is 8 so we need to convert (300)8 = 192

Answer:

Explanation:

t=24
D = 4*sqrt(24 - 8) D = 4*sqrt(16)
D = 4*4 D = 16

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19. If there are 30 cans out of them one is poisoned. If a person tastes very little of this he will die within 14 hours so they decided to test it with mice. Given that a mouse dies in 24 hours and you have 24 hours in all to find out the poisoned can, how many mice are required to find the poisoned can?

Answer:

Explanation:

The mice will die within 24 hours not exactly on the 24th hour.
For example, if there are 7 cans,
1st Can's solution is given to mice A. 2nd Can's solution is given to mice B. 3rd Can's solution is given to mice C. 4th Can's solution is given to A and B. 5th Can's solution is given to B and C. 6th Can's solution is given to C and A. 7th Can's solution is given to A, B and C.
Then within 24 hours if A alone dies, Can 1 is poisoned. If B alone dies, Can 2 is poisoned.
If C alone dies, Can 3 is poisoned.
A and B dies if Can 4 is poisoned, B and C dies if Can 5 is poisoned, C and A dies if Can 6 is poisoned & if all A, B, C dies then Can 7 is poisoned.
From this we can tell that to check 23-1 = 7 Cans we need 3 mouse.
Therefore we can tell that in order to check 30 Cans (25-1 = 31 maximum) we need 5 mouse.

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20. The citizens of planet nigiet are 6 fingered and have thus developed their decimal system in base 6. A certain street in nigiet contains 1000 (in base 6) buildings numbered 1 to 1000. How many 3s are used in numbering these buildings?

Answer:

Explanation:

In decimal system total no. of 3's from 1 to 1000 are 100*3 = 300 In base 6, value of 300 = 3*(6^2) + 0*(6^1) + 0*(6^0) = 108.

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