101. By mixing two qualities of pulses in the ratio 2: 3 and selling the mixture at the rate of Rs 22 per kilogram, a shopkeeper makes a profit of 10 %. If the cost of the smaller quantity be Rs 14 per kg, the cost per kg of the larger quantity is :
Answer:
Explanation:Cost Price of 5 kg = Rs.(14*2 + x*3) = (28 + 3x).
Sell price of 5 kg = Rs. (22x5) = Rs. 110.
[{110 - (28 + 3x)}/(28 + 3x) ]* 100 =10
[82-3x/28 + 3x]= 1 / 10
820 - 30x = 28 +3x
33x = 792
x = 24
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MindTree HCL Technologies Radisys
102. Excluding stoppages, the speed of the bus is 54 kms /hr and with stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?
Answer:
Explanation:By including stoppages, bus will cover 9km less..(54km -45km = 9km)
Excluding stoppages, x = 54 kmph
Including stoppages, y = 45 kmph
Difference, z = 9km
Time taken to cover that 9km(bus stops per hour(60minutes))= z/x(60minutes)
= 9/54(60) = 1/6(60) = 10minutes.
Workspace
MindTree HCL Technologies GlobalLogic
103. the two numbers (23__)^32 and (12__)^ 33 has 6 in the last digit. What is the missing digit?
Answer:
Explanation:As last digit in all powers of nos with unit digit 6 is 6.
Hence answer is 6.
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MindTree HCL Technologies Aricent
104. A certain organization has three committees.Only two persons are members of all committees,but every pair of committees have three members in common.What is the least possible no of member of members on any one committee?
Answer:
Explanation:In all 3 committees, say X,Y,Z, 2 persons say A and B are common.
C is common between X and Y.
D is common between Y and Z.
E is common between X and Z.
So X committee has ABCE. Y committee has ABCD. Z committee has ABDE.
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MindTree HCL Technologies Cisco
105. How many six digit phone numbers can you frame using the digits from 0 to 9 if a condition restricts you to start the number with 35 and another condition restricts you from using any digit more than once?
Answer:
Explanation:It's a permutation question.
there are totally 10 numbers and in which 3 and 5 are already fixed as first two digits.
hence total numbers n=8
and the remaining digits which are needed to be formed its 4 digits apart from the first two digits already formed in the 6 digit phone number.
so r=4
permutation formula npr=n!/(n-r)!
=8!/4!
=8*7*6*5*4*3*2*1/4*3*2*1
=8*7*6*5
=1680
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MindTree HCL Technologies Brocade
106. (10^23)-7 is divided by 6, what is the remainder?
Answer:
Explanation:Anything power by 10 we get 10 and some zeroes after that(i.e,1000000000000000...)
After that if we minus 7 means, we must get last two digits is 93.
(i.e., 9999999999993)
Divided by 6, we get remainder 3.
Workspace
MindTree HCL Technologies Wipro
107. If 5√5 x 5^3 + 5^-3/2 = 5 ^(a + 2), then the value of a is:
Answer:
Explanation:5^1x5^1/2x5^3+5^-3/2 = 5^(a+2)
5^3/2x5^3+5^-3/2
5^9/2+5^-3/2
5^6/2
5^3 = 5^(a+2)
now, 3 = a+2
a=1
Workspace
MindTree HCL Technologies Broadcom Ltd
108. A and B can do a piece of work in 12 days, B and C can do it in 15 days and C and A can do the same work in 20 days. How long would each take to complete the job?
Answer:
Explanation:(A+B)'s one day work is 1/12
(B+C)'s one day work is 1/15
(C+A)'s one day work is 1/20
Thus,2(A+B+C)'s one day work is 1/12+1/15+1/20=1/5
so,(A+B+C) can complete the work in 10 days.
(A+B+C)'s one day work=1/10
A 's one day work=1/10-1/15=1/30
B's one day work=1/10-1/20=1/20
C's one day work=1/10-1/12=1/60
Workspace
MindTree HCL Technologies Broadcom Ltd
109. There are two sections in a question paper each contain five questions. A student has to answer 6 questions. Maximum no. of questions that can be answered from any section is 4. How many ways he can attempt the paper?
Answer:
Explanation:If the max number from each section is 4 and a total of 6 questions must be answered then the possible ways to answer are:
4 from A and 2 from B
or 2 from A and 4 from B
or 3 from both A and B
Number of ways of choosing 4 from part A AND 2 from part B = 5C4 * 5C2 = 50 ... (AND means multiply)
Number of ways of choosing 2 from part A AND 4 from part B = 5C2 * 5C4 = 50
Number of ways of choosing 3 from part A AND 3 from part B = 5C3 * 5C3 = 100
So total number of ways to answer the paper = 50 + 50 + 100 = 200
Workspace
MindTree HCL Technologies Broadcom Ltd
110. In a cricket, the average of eleven players is 28 years. Out of these, the average ages of three groups of three players each are 25 years, 28 years and 30 years respectively. If in these groups, the captain and the youngest player are not included, and the captain is eleven years older than the youngest player, what is the age of the captain ?
Answer:
Explanation:Here is no explanation for this answer
Workspace
MindTree HCL Technologies Cisco
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