Login/RegisterQuantitative Aptitude :: Permutation and Combination - Discussion
Home > Quantitative Aptitude > Permutation and Combination > MCQs Questions Discussion
469 / 100
Choose the correct option.
How many 6 digit even numbers can be formed from digits 1, 2, 3, 4, 5, 6, and 7 so that the digit should not repeat and the second last digit is even?
A6480
B320
C2160
D720
Answer: Option (Login/Signup)
Show Explanation
If the we have to form even numbers, units digit must be 2, 4, 6. i.e., 3 ways.
Also 5th digit should be even.
So it can be filled in 2 ways. Now remaining 5 digits can be filled in 5! ways. So total 5! * 3 * 2 = 720 ways.
Asked In ::
No Discussion on this question yet!
