Quantitative Aptitude :: Average - Discussion
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The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 43 kg, then the weight of B is:
A17 kg
B20 kg
C26 kg
D31 kg
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1. A+B/2=40kg and B+C/2=43kg
2. A+B=80kg and B+C=86kg
3.A+B+C/3=45kg
4. A+B+C=135
5. 80+C=135 and A+86 = 135 {Substituting A+B=80 and B+C=86 in original equation}
6. C=55kg and A=49
7. B+55+49=135
8.B=31kg {Required Answer}
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In mathematics, the Pythagoras theorem, also known as the Pythagoras
theorem, is a fundamental relation in Euclidean geometry between three
sides of a right triangle. This states that the area of the square
whose side is the hypotenuse is equal to the sum of the squares on the
other two sides.
<br><span style="padding-left:38px;"></span>In a
right-angled triangle, \(Hypotenuse^{2}\) = \(Base^{2}\) +
\(Height^{2}\).
<br><span style="padding-left:38px;"></span>\( \mathbb{iv.} \) The line joining the mid-point of a side of a triangle to the positive vertex is called the <b>median</b>.
<br><span style="padding-left:38px;"></span>\( \mathbb{v.} \) The point where the three medians of a triangle meet, is called <b>centroid</b>. The centroid divided each of the medians in the ratio 2 : 1.
<br><span style="padding-left:38px;"></span>\( \mathbb{vi.} \) In an isosceles triangle, the altitude from the vertex bisects the base.
<br><span style="padding-left:38px;"></span>\( \mathbb{vii.} \) The median of a triangle divides it into two triangles of the same area.
<br><span style="padding-left:38px;"></span>\( \mathbb{viii.} \) The area of the triangle formed by joining the mid-points of the sides of a given triangle is one-fourth of the area of the given triangle.
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