31. What is the number of odd days in a leap year ?
Answer:
Explanation:In a given period the number of days more than complete week are called odd days
366 divided by 7
remainder is 2
so the number of odd days in a leap year is 2
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HCL Technologies
32. 5% of (25% of Rs1600) is?
Answer:
Explanation:25% of 1600=(25*1600)/100=400
5% of 400=(5*400)/100=20
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HCL Technologies
33. If angles of a pentagon are in the ratio 1 : 3 : 6 : 7 : 10, then smallest angle is?
Answer:
Explanation:angle of pentagon = 540degree
now
x+3x+6x+7x+10x= 540
27x = 540
x=20
now smallest angle will be of 20 degree
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HCL Technologies
34. Few years ago on 31st January on her 26th birthday a lady laid a baby. Now what's the sum of their ages?
Answer:
Explanation:All other options have thier unit place digit odd while we require even digit
because before x years she laid a baby. That time she is 26years old
So, now sum of thier ages is 26 + 2x. The total should be even number.
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HCL Technologies Broadcom Ltd
35. A man starts from B to K, another starts from K to B, at the same time. After passing each other they complete their journeys in 3.33 and 4.80 hours respectively. Find the speed of the second man if the speed of the first is 12 km/ hr
Answer:
Explanation:12:x=sqrt(288):sqrt(199.8)
12:x=17:14
x=168/17 ~10km/hr
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HCL Technologies
36. The number 50 is divided into two parts, the ratio of the largest part to the smallest is 2/3, then the largest part is?
Answer:
Explanation:Assume two numbers are x and y
x/y = 2/3, 2x = 3y ----(1)
The number 50 is divided into two equal parts. If you make equal parts there is no question of Largest part and Smallest Part. So assuming 50 is devided in to two parts.
x+ y = 50 ---- (2)
simplyfy 1 and 2
x =30 and y = 20
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HCL Technologies
37. The value of 36 coins of 10 p and 20 p is Rs. 6.60. The number of 20 p coins is :
Answer:
Explanation:(36-x)*10+x*20=660
so x=30
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HCL Technologies
38. A person has to cover a distance of 6 km in 45 minutes. If he covers one-half of the distance in two-thirds of the total time; to cover the remaining distance in the remaining time, his speed(in Km/hr) must be
Answer:
Explanation:he covers half of the distance i.e (3km)in 2/3rd of time i.e 30 min ,so speed to cover these half is 3/0.5 km/hr=6km/hr
we know speed is inversly propositional to time
t2=45-30=15min=0.25hr
so s1t1=s2t1
6*0.5=s2*0.25 = 12km/hr
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HCL Technologies
39. In how many ways can the letters of the word COLLEGE be arranged,such that its vowels do not come together?
Answer:
Explanation:COLLEGE
C=1,O=1,G=1, L=2,E=2
vowels = O E E
total no. of words formed = 7!/(2!*2!) = 7!/4 = 1260
no. of words when vowels come together = CLLG(OEE) => 5!/2! * 3!/2! = 180
no. of words having vowels not together = 1260 - 180 = 1080
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HCL Technologies
40. What will be the value of x^(1/2).x^(1/4).x^(1/8)............to infinty.
Answer:
Explanation:x^(1/2+1/4+1/8.infinite )so x^(1/2(1+1/2+1/4+.....))
=x^(1/2(1/(1-1/2))....................infinite terms formula a/1-r for a+ar+.....
=x^1
=x
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HCL Technologies Broadcom Ltd
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