Placement Questions & Answers :: HCL Technologies

Answer: 0.18

Given numbers are 1.08 , 0.36 and 0.90
H.C.F of 108, 36 and 90 is 18 ( G.C.D is nothing but H.C.F)
So H.C.F of given numbers = 0.18

Answer:

Total volume of three metallic balls(spheres)= (4/3)*Pi*(3^3+4^3+5^3)
=(4/3)*Pi*216= Volume of new ball with radius 'r'
so (4/3)*Pi*r^3=(4/3)*Pi*216
r^3=216 , r=6

Answer:

Let total population = p
no. of males =5p/9
no. of females =(p-5p/9)=4p/9
married males = 30% of 5p/9=30*5p/100*9 =p/6
married females = p/6
unmarried females =(4p/9-p/6)=5p/18
%age of unmarried females in the total population = {(5p/18)/p}*100= 250/9% = 27.78%

Answer:

Let the labelled price of TV be Rs. x, then difference between 80% of x and 75% of x is Rs. 500.
=> 0.8x - 0.75x = 500
=> 0.05x =500 or x=10000
So the buying price=80% of x= 0.8*10000=Rs. 8000

Answer:

In the period of First 3 hrs, the demand of water = 10000.
but the water poured by 10000 per hour.
Thus the end of 3 hours it will poured 30000 ltr then the excess of water = 20000.
Similarly at the end of Second 3 hrs period the excess of water 20000+20000 = 40000.

Third, 3 hrs water poured = 30000
already we have 40000 of excess water and demand 45000.
Then the excess water at the end of 3rd 3 hrs= 40000+30000–45000= 25000
Fourth 3 hrs. water = 25000+30000–25000= 30000
Fifth = 30000+30000–40000= 20000
Sixth = 20000+30000–15000=35000
Seventh = 35000+30000–60000= 5000
Eighth = 5000+30000–35000= 0
By analyzing the above results, we have 40000 ltrs is the highest measure of excess water.
So the minimum capacity of water tank = 40000 litres = 40
i.e. = 40

Answer:

Ratio of investment = 1/2 : 1/3 : 1/4,
taking lcm of (2,3,4) and divide by this ratio's we get 6 : 4 : 3,
we have to assume there initial investment is 6x, 4x and 3x
now we can write A : B : C = (6x * 2 + 3x*10) : (4x *12) : (3x*12) after doing calculation we got
= 42:48:36 more simplify it
= 7:8:6
now we need to calc B'share = (8/21) * 378 = 144

Answer:

Let the length of the train be x meter and the speed of the cyclist is y m/s
Now when the train and the cyclist are in the same direction, the relative speed is :(35/3-y)m/s
[converting 42km/h to m/s-35/3m/s]
Now distance/relative speed =9 seconds
Substituting the values, we get x+9y.....................(1)
Similarly calculate the relative speed when they are in the opposite direction
The relative speed is (35/3+y)
Now distance/relative speed is equivalent to 5 seconds
Substituting the values, we get the equation
3x-15y=175.................................(2)
Solving (1) and (2), we get x=75 meters

Answer:

Discount=0.9*0.75*0.85=0.57
S0, 0.57*400=230

Answer:

If x is common result, then numbers are 2x, x/2, x+2, x-2
and
2x+ x/2+ x+2+x-2 = 45
4x+x/2 =45
9x =90
x=10
hence numbers are
8,12,5,20

Answer:

Without any Repetetion of the numbers Sum would be
(n-1)!(sum of the numbers)(1 as many times as digits of the number)

Here
(5-1)!(1+3+5+7+9)(11111)
24*25*11111 = 6666600