61. There is a clock which shows false timing ie it shows 10 minutes less for each 1 hour. If the clock shows 12 noon now how many minutes will be lost when it shows 3 pm?
Answer:
Explanation:For 1 hour, 10minutes is slower, then for
06 miuntes - 1 minutes is slower
30 minutes - 5 minutes
Actual time false time
12 12
01 PM 12.50 PM (10 minutes slower)
02 PM 01.40 PM (12.50 + 60 min - 10 minutes slower)
03 PM 02.30 PM (01.40 + 60 min - 10 minutes slower)
03.36 PM 03.00 PM (02.30 + 36 min - 6 minutes slower )
So, 36 minutes will be lost when it is showing 3.00 PM. and the actual time is 3.36 PM
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HCL Technologies Broadcom Ltd
62. An air conditioner can coo the hall in 40 miutes while another takes 45 minutes to cool under similar conditions. if both air conditioners are switched on at same instance then how long will it take to cool the room?
Answer:
Explanation:A cools at 40min other at 45min together = (45*40)/85 = 21.1764 = about 22 min
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HCL Technologies
63. A passenger train takes two hours less for a journey of 300km if its speed is increased by 5 kmph from its normal speed. The normal speed is
Answer:
Explanation:let normal speed = x
Increased speed = x + 5
Initialy, x = 300/t1
t1 = 300/x
After, (x + 5) = 300/(t1 - 2)
(x + 5) = 300 / [ (300/x) - 2]
x = 25kmph
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HCL Technologies
64. There are 25 Horses which all run at different speeds. A faster horse always beats a slower horse. You can race 5 horses at a time. There are no ties and you may not time them. What is the minimum number of races needed to determine the 3 fastest horses in order from fastest to slowest.
Answer:
Explanation:Minimum 7 races required.
A1 B1 C1 D1 E1
A2 B2 C2 D2 E2
A3 B3 C3 D3 E3
A4 B4 C4 D4 E4
A5 B5 C5 D5 E5
Consider the above five races first to find top (A1,B1,C1,D1,E1). Lets race top 5 (5+1 now). We say winners are (A1 B1 C1).
Here A1 is absolute top to all. There is a possiblity where B1 might be slower than A2,A3,A4,A5.
So Race B1, A2, A3, A4, A5 (Now 5+1+1 = 7). If A3 beats B1, top hourses are A1,A2,A3.
Please let me know if the explanation suits.
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HCL Technologies
65. 81*82*83*84*85*86*87*89. What should be in the unit place in this product?
Answer:
Explanation:It should be zero in the unit place in this product.
85*82 will give zero in unit place.
Workspace
HCL Technologies
66. A cube is of size 5*5*5 .every side has green coloured. It is divided into
125 equal parts.
1) What is the no. of parts having only one side coloured
2) no. of parts having two sided coloured
3) having no side coloured
Answer:
Explanation:One side colored = 6 * 9=54
Two side colored = 12*3=36
No side colored= 125-54(one side colored)-36(two side colored)-8(three side colored) =27
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HCL Technologies
67. In a garden man has to pick some flowers ans has to pass thrrough 3 doors. Each door has a guard. Man has to give half of the flowers he had, to the guard and in return guard returns the man one flower back. How many flower should man pick so that at the end he is left with same number of flowers he has picked?
Answer:
Explanation:Suppose man picks up x flowers.
He gives half flowers he had to guard and guard in return gives 1 flower to man.
So, after 1st door remained flowers towards guard=(x/2)+1
i.e(x+2)/2
After 2nd door remained flowers towards guard=[(x+2)/4]+1
After 3rd door remained flowers towards guard=[(x+6)/8]+1
i.e.(x+14)/8
At the end he is left with same number of flowers he has picked.
So, (x+14)/8=x
8x-x=14
x=2
Hence he should pick up 2 flowers.
Workspace
HCL Technologies Broadcom Ltd
68. What is the area of a circle having the same perimeter as that of a square whose area is 121.
Answer:
Explanation:Side of the square=sqrt(12)=11
Perimeter of the square=44
2*π*r=44
r=44/2*π
area of the circle=π*r^2=308
Workspace
HCL Technologies
69. The average of six numbers is 30.If the average of first four is 25 and that of last three is 35, the fourth number is :
Answer:
Explanation:sum of six nos is 180.
sum of first four is 100
sum of last three is 105.
sum of last two is 180-100=80.
fouth one is obtained by 105-80=25.
Workspace
HCL Technologies
70. Abel, Loyla and Sel are three channels , if 30% of the populatio watch Abel, and 5% of the people watch any two of the channel, and 5% of the people watch none of the channel then the number of people watching all the three channels are?
Answer:
Explanation:Assume A,B,C are channels. P(A)=0.3 Intersection of any two channels = 0.05
People watch atleast one channel is = 1-0.05=0.95.
Now people watching all the three can be found by,
0.95=0.3-3*0.05+ x
x = 0.8.
Hence answer is 80%.
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HCL Technologies
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