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Placement Questions & Answers :: Huawei

41. If 8 men and 6 boys can dig a well in 2 days, and 6 men and 2 boys can do it in 3 days, how long will 5 men and 3 boys take to do it?

Answer:

Explanation:

Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.
so 8x+6y=1/2,& 6x+2y=1/3 on solving these two equation we get x=1/20 and y=1/60 days..5 men(x)+3 boy(y) 1 days work =(5/20+3/60)=3/10
so they will complete the work in 3.33 days.

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42. The ratio of the ages of Mona and Sona is 4:5. Twelve years hence, their ages will be in the ratio of 5:6. What will be Sona's age after 6 years?

Answer:

Explanation:

Let their present ages be 4x & 6x
Then (4x + 12)/(5x + 12) = 5/6 ; x=12
Sona's age after 6 years = (5x +6) = 66 years

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43. One bottle is half-full of oil and another bottle with twice the capacity is one quarter full of oil. If water is added so that both the bottles are full and the contents of both are then poured into a third bottle that is empty and large enough to hold the contents of both, what fractions of the contents in the third bottle is oil?

Answer:

Explanation:

Let assume that 1st bottle capacity = 1Litre;

Therefore, it contain 1/2 litre Oil and 1/2 litre water .
(i.e) Water = 1/2 litre
Oil = 1/2 litre

2nd bottle is twice the capacity
i.e. 2 litre capacity
It means, 1/2litre filled with oil and 1(1/2)litre filled with water.
i.e. Oil = 1/2 liter
Water = 1(1/2)litre

In total the third bottle will contain,
1 litre oil and 2 litre water.
i.e., Oil = 1 litre
Water = 2 liter

Therefore, oil proportion is 1/3Is

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44. In a shop 80% of the articles are sold at a profit of 10% and the remaining at a loss of 40%. What is the overall profit/loss?

Answer:

Explanation:

80*1.1+20*0.6/100=1

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45. A dealer professing to sell his goods at cost price, uses a 900 gm weight for a kilogram. His gain percent is

Answer:

Explanation:

formula is: error/(truevalue-error)*100
so 100/(1000-100)*100=100/900*100 = 11 1/9

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46. In a school the number of girls is 15 more that that of the boys. Now if 19% of the girls were newly joined and 25% of the boys were newly joined the number of girls is 9 more than that of the boys. How many girls and boys were there?

Answer:

Explanation:

In a school the number of girls is 15 more that that of the boys.
Means G = 15 + B ------ (1)
Now if 19% of the girls were newly joined and 25% of the boys were newly joined
Total Girls are 1.19G
Total Boys are 1.25B
Girls is 9 more than that of the boys.
1.19G = 9 + 1.25B ------ (2)
Solving (1) and (2)
B= 147
G= 147 + 9 = 156

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47. A light was seen at intervals of 13 seconds. It was seen for the first time at 1 hr 54 min 50 secs. a. m. and the last time at 3 hrs 17 min 49 secs. a.m. How many times was light seen ?

Answer:

Explanation:

It is an A.P.
where a=1hr 54min 50sec= 6890 sec.
(last term) L=3hr 17min 49sec= 11869sec.
d=13.
L=a+(n-1)d
11869=6890+(n-1)13.
4979=(n-1)13
n-1=383.
n=384
hence number of times light was seen is 384

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48. A box contain 4 small boxes, each small box again contain 3 box, again these box contain 2 box. Total how many boxes are there?

Answer:

Explanation:

A box contain 4 small box means 1+4 = 5 Boxes
Each small box again contain 3 box means 4*3 = 12 boxes
Again these 12 boxes contain 2 boxes each, means 12*2 = 24
Total Boxes till now are 5 + 12 + 24 = 41

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49. How many 4 digit integers formed between >990 and <5000 by using 0,4,5,7,8,9 repetition of integers are allowed?

Answer:

Explanation:

numbers are of 4-digits > 990 and < 5000

thousand place can be filled by 4 only in one way
as repetition is allowed , rest three places can be filled in 6 ways each

total no. formed = 1*6*6*6 = 216

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50. When a stone is dropped from a building 200 m high, its speed is proportional to the time elapsed after dropping. The distance traveled is proportional to the square of the time elapsed. After 1 second the speed of the train was 10 m/sec and it was 190 m above the ground. When its speed is 25 m/sec, what would be its distance from the ground?

Answer:

Explanation:

v= x*t and s= y*t^2
10 = x*1, hence x=10 units
(200-190) = y*1*1
y=10
When speed = 25m/sec, time elapsed = 25/10 = 2.5 sec
Distance travelled by stone = 10*(2.5)^2 = 62.5 mts
So, distance of stone above ground = 200-62.5 = 137.5 mtrs

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