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Placement Questions & Answers :: TCS NQT

611. In an election contested by two parties, Party D secured 12% of the total votes more than Party R. If party R got 132,000 votes, by how many votes did it lose the election?

Answer: 36000

Explanation:

Let the percentage of the total votes secured by Party D be x%
Then the percentage of total votes secured by Party R = (x – 12)%
As there are only two parties contesting in the election, the sum total of the votes secured by the
two parties should total up to 100%
i.e., x + x – 12 = 100
2x – 12 = 100
or 2x = 112 or x = 56%.
If Party D got 56% of the votes, then Party got (56 – 12) = 44% of the total votes.
44% of the total votes = 132,000 i.e. 44/100 * T = 132,000
T = (132000 * 100)/44 = 300000 votes.
The margin by which Party R lost the election = 12% of the total votes
= 12% of 300000 = 36000.

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612. If the Arithmetic mean is 34 and geometric mean is 16 then what is greates number in that series of numbers?

Answer: 64

Explanation:

Lets assume two numbers be x, y;
Arthmetic mean=34=>( x+y)/2=34
=> x+y=68
geometric mean=16=>(xy)^(1/2) = 16
=> xy=16*16=256

By trail and error 16*16=64*4
And 64+4/2=34
So the greatest number int that series is 64.

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